We need to find out the surface area of the Earth (SE) and the area of the widest part of the soccer ball (WAS). We’re not finding out the surface area of the soccer ball because we’re not going to be able to stretch it apart to cover the earth. We use WAS times the Avogadro's number and use that to divide the SE. Then we use that number and times it by the diameter of the soccer to find out to what depth would it cover.

Diameter: 22.2 cm Surface Area of the widest part: A = πr 2 A = 3.14 x (22.2 cm / 2) 2 A = cm 2 Surface Area: 5.1 x 10 8 km 2 or 5.1 x cm 2 Process Area of a mole of soccer ball = SA of Ball x 1 mole =386.88cm 2 x x = 2.3 x cm 2 Number of times covering the Earth = SA of 1 mole of soccer ball ÷ SA of Earth =2.3 x ÷ 5.1 x = 4.51 x 10 7 Depth it would cover to = # of times it would cover the Earth x Soccer ball’s Diameter = 4.51 x 10 7 x 22.2 cm = x 10 9 cm Area of a Circle: πr 2 Km 2 to cm 2 = 10 x 10 9

A mole of soccer balls would cover the surface of the Earth to a depth of x 10 9 cm or km