Reactions of Alcohols Susan F. Hornbuckle Associate Professor of Chemistry Clayton State University.

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Presentation transcript:

Reactions of Alcohols Susan F. Hornbuckle Associate Professor of Chemistry Clayton State University

Reactions Flow Chart What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN.

What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN. Example 1

What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN. Example 2

What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN.

Example 2 What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN.

Example 2 What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN.

Example 3 What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN.

Example 3 What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN.

Example 3 What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN.

Example 3 What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN.

Example 3 What are the reaction conditions? K2Cr2O 7 / H2SO4 “Oxidation Conditions” Is the starting alcohol 1 o, 2 o, or 3 o ? 1 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form an ALDEHYDE. Insert an oxygen atom in the C-H bond of the carbonyl to form a CARBOXYLIC ACID. 2 o Remove the alpha- hydrogen and the hydroxyl-hydrogen to form a KETONE. 3 o NO RXN.