Final exam: CB 106 May 6 Thursday 6:00pm – 8:00pm STA 291 - Lecture 281 STA 291 Lecture 28.

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Final exam: CB 106 May 6 Thursday 6:00pm – 8:00pm STA Lecture 281 STA 291 Lecture 28

Exam II curve: conversion formula If your original score is 83 or above, then converted score = 90+(x-83)10/17 If your original score is 71  82, then converted score = 80+(x-71)9/11 If your original score is 59  70, then converted score = 70+(x-59)9/11 If your original score is 48  58, then converted score = 60+(x-48)9/10 If your original score is 1  47, then converted score = x 59/47 STA Lecture 272

STA Lecture 283 Final Exam, Thursday, May 6 When: 6:00PM - 8:00PM Where: CB 106 Make-up exam: –Only by prior arrangement: –Friday May 7, 10:00am - 12:00noon

STA Lecture 284 Last homework Online homework assignment

New materials after Exam II Chapter 11: 11.1 – 11.9 Chapter 12: 12.5 Chapter 13: 13.1 — 13.3 Chapter 14: 14.1, 14.2, 14.3, 14.4 STA Lecture 285

6 Final Exam You bring a calculator. Will be given a formula sheet/table Any technology that can receive/transmit information wirelessly is not permitted during the exam Turn off cell phone etc.

Get prepared by reviewing –The midterm exams –Online homework questions –Suggested homework questions –Lecture notes –Material from lab sessions –Textbook STA Lecture 287

8 Introduction to Linear Models -- a preview of What’s next in statistics More Confidence intervals and More Testing hypothesis plus Statistical models for more complex setting (beyond one/two samples)

STA Lecture 289 More than two samples Three groups (three populations): no drug, 10mg/day, 20mg/day 35 subjects in each group. Do blood pressure decrease as dosage increase? We postulate a Model: the average decrease of blood pressure is linearly related to the dosage. In this example, this assumes the effect must be doubled in the 20mg group compared to 10mg group

STA Lecture 2810 Modeling the parameter, mu – the average blood pressure for certain drug dose. As how mu is related to the dosage.

STA Lecture 2811 Example of a linear model Here is the placebo effect, those taking a pill of corn starch, will decrease blood pressure by Group with 10mg will further decrease 13=1.3x10 Group with 20mg will further decrease 26=1.3x20

STA Lecture 2812 Notice this same model could be describing 4 groups: No drug, 10mg, 20mg, 25mg, etc Or 5 groups or any groups…

STA Lecture 2813 The number -1.3 in the previous page is just for example. In reality we need to estimate that number (called slope). (estimator mostly produced by a computer, we fed data into a program…) Construct confidence interval for the slope Test hypothesis that slope =0; -- equivalent to testing no effect of drug

The parameters here: Slope (-1.3) and the intercept ( ) Confidence interval/testing for these two parameters, etc STA Lecture 2814

STA Lecture 2815 Models can be more and more complicated…. But we always test a hypothesis about the parameters in the model. Construct a confidence interval about (an all important slope of) the model. Once the model is established, it can be very useful: use the model to predict…….

Another model The proportion of hitting the basket decreases as the distance from hoop increases. Model : p = f( distance ) How fast it decreases? STA Lecture 2816

STA Lecture 2817

Estimate the “slope” or speed of decreasing…. Two player may have two different curve, but both decreasing. Is there a favorable spot of shooting? STA Lecture 2818

more examples: Kentucky Utility need to predict the electricity usage, as how it changes as temperature change. Financial modeling STA Lecture 2819

No matter how complicated the model is, No matter how many parameters it involves, the correspondence between confidence interval and p-value of testing hypothesis is always there STA Lecture 2820

Today’s Q Your name/ID and 291 section number A: Sta291 is my last Statistics course in college. B: I will be taking another statistics course. (Which one?) STA Lecture 2821