Math 3Warm Up4/23/12 Find the probability mean and standard deviation for the following data. 2, 4, 5, 6, 5, 5, 5, 2, 2, 4, 4, 3, 3, 1, 2, 2, 3, 4, 6,

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Math 3Warm Up4/23/12 Find the probability mean and standard deviation for the following data. 2, 4, 5, 6, 5, 5, 5, 2, 2, 4, 4, 3, 3, 1, 2, 2, 3, 4, 6, 5 Hint: First create a probability distribution.

Z-SCORE Unit 6: Data Analysis

Z-Scores are measurements of how far from the center (mean) a data value falls. Ex: A man who stands 71.5 inches tall is 1 standardized standard deviation from the mean. Ex: A man who stands 64 inches tall is -2 standardized standard deviations from the mean.

Standardized Z-Score To get a Z-score, you need to have 3 things 1)Observed actual data value of random variable x 2)Population mean,  also known as expected outcome/value/center 3)Population standard deviation,  Then follow the formula.

Empirical Rule & Z-Score About 68% of data values in a normally distributed data set have z-scores between –1 and 1; approximately 95% of the values have z-scores between –2 and 2; and about 99.7% of the values have z-scores between –3 and 3.

Z-Score & Let H ~ N(69, 2.5) What would be the standardized score for an adult male who stood 71.5 inches? H ~ N(69, 2.5) Z ~ N(0, 1)

Z-Score & Let H ~ N(69, 2.5) What would be the standardized score for an adult male who stood inches?

Comparing Z-Scores Suppose Bubba’s score on exam A was 65, where Exam A ~ N(50, 10). And, Bubbette score was an 88 on exam B, where Exam B ~ N(74, 12). Who outscored who? Use Z-score to compare.

Comparing Z-Scores Heights for traditional college-age students in the US have means and standard deviations of approximately 70 inches and 3 inches for males and cm and 6.35 cm for females. If a male college student were 68 inches tall and a female college student was 160 cm tall, who is relatively shorter in their respected gender groups? Male z = (68 – 70)/3 = Female z = (160 – 165.1)/6.35 = -.803

What if I want to know the PROBABILITY of a certain z-score? Use the calculator! Normcdf!!! 2 nd Vars 2: normcdf( normcdf(lower, upper, mean(0), std. dev(1))

Find P(z < 1.85)

Find P(z > 1.85)

Find P( -.79 < z < 1.85)

What if I know the probability that an event will happen, how do I find the corresponding z-score? 1)Use the z-score formula and work backwards! 2)Use the InvNorm command on your TI by entering in the probability value (representing the area shaded to the left of the desired z-score), then 0 (for population mean), and 1 (for population standard deviation).

P(Z < z*) =.8289 What is the value of z*?

Using TI-84

P(Z < x) =.80 What is the value of x?

P(Z < z*) =.77 What is the value of z*?