MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 1 Bruce Mayer, PE MTH15: Applied Calculus I Bruce Mayer, PE Licensed Electrical & Mechanical Engineer MTH 15 Round-End Fenced Enclosure
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 2 Bruce Mayer, PE MTH15: Applied Calculus I Given Fenced Enclosure Given Parameters Total Enclosed Area = 1600 Square Feet (1600 ft 2 ) Fence Costs in $/Lineal-Ft –Straight = 30 –Curved = 40 Determine Lo-Cost R & L
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 3 Bruce Mayer, PE MTH15: Applied Calculus I Given Fenced Enclosure Game Plan Solve for COST FUNCTION f(R) Solve by BOTH of –Hand Calculus Develop Cost Function –Use min command on Cost Vector Will hunt-down LoCost & Address
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 4 Bruce Mayer, PE MTH15: Applied Calculus I
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 5 Bruce Mayer, PE MTH15: Applied Calculus I
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 6 Bruce Mayer, PE MTH15: Applied Calculus I
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 7 Bruce Mayer, PE MTH15: Applied Calculus I.m File Script
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 8 Bruce Mayer, PE MTH15: Applied Calculus I Answer Graphically
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 9 Bruce Mayer, PE MTH15: Applied Calculus I L vs R Plot (for Fun)
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 10 Bruce Mayer, PE MTH15: Applied Calculus I Symbol-Based Alternative
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 11 Bruce Mayer, PE MTH15: Applied Calculus I
MTH15_Lec-17a_sec_3-5_Round_End_Fence_Enclosure.pptx 12 Bruce Mayer, PE MTH15: Applied Calculus I