Homework (Tuesday, 11/3) Lesson 2.03 packet page 4 and 5.

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Presentation transcript:

Homework (Tuesday, 11/3) Lesson 2.03 packet page 4 and 5

Lesson 2.03 Zero Product Property

Practice Problems a)f(x)= 3x 2 – 16x – 12 b)f(x)= 4x 2 + 5x – 6 c)f(x)= 4x 2 – 49 d)f(x)= 2x X + 12 Solutions: a)(x-6)(3x+2) b)(x+2)(4x-3) c)(2x+7)(2x-7) d)(x+4)(2x+3)

SHORTCUTS a 2 + 2ab + b 2 (a+b) 2 Example: 9x 2 – 42x + 49 (3x-7)(3x-7)  (3x – 7) 2 Example: 25x x + 81 (5x+9)(5x+9)  (5x + 9) 2 a 2 - 2ab + b 2 (a - b) 2 a 2 - b 2 (a+b)(a - b) Example: x 2 – 64 (x + 8)(x – 8)

Zero-Product Property Zero-Product Property: If pq= 0, then p = 0 or q = 0 ax 2 + bx + c = 0 is called the general form of a quadratic equation

Example given f(x) = x , find the solution

Example given f(x) = 81x , find the solution

Example given 15x 2 = 7x + 2, find the solution

Example

Given x 3 + 3x 2 – 4x – 12, solve for x