Factor completely EXAMPLE 4 Factor the polynomial completely. a.a. n 2 – + 2n –1 SOLUTION a.a. The terms of the polynomial have no common monomial factor.

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Factor completely EXAMPLE 4 Factor the polynomial completely. a.a. n 2 – + 2n –1 SOLUTION a.a. The terms of the polynomial have no common monomial factor. Also, there are no factors of – 1 that have a sum of 2. This polynomial cannot be factored.

Factor completely EXAMPLE 4 Factor the polynomial completely. b.b. 4x 3 – 44x x SOLUTION b.b. 4x 3 – 44x x = 4x(x 2 – 11x + 24) Factor out 4x. = 4x(x– 3)(x – 8) Find two negative factors of 24 that have a sum of – 11.

Factor completely EXAMPLE 4 Factor the polynomial completely. c.c. 50h 4 – 2h 2 SOLUTION c.c. 50h 4 – 2h 2 = 2h 2 (25h 2 – 1) Factor out 2h 2. = 2h 2 (5h – 1)(5h+1) Difference of two squares pattern

GUIDED PRACTICE for Example 4 Factor the polynomial completely x 3 –12x 3x(x 2 – 4) Factor out 3x. = 3x(x 2 – 2 2 ) = 3x (x + 2)(x – 2) Difference of two squares pattern Write x 2 – 4 as a 2 – b 2 3x 3 –12x =

GUIDED PRACTICE for Example 4 Factor the polynomial completely y 3 –12y 2 +18y Factor out 2y. = 2y(y – 3) 2 Perfect squares pattern trinomial pattern. Write y 2 – 6y + 9 as a 2 – 2ab 2 + b 2 2y(y 2 – 6y+9) 2y 3 –12y 2 +18y = = 2y[y 2 – 2(y 3) ]

GUIDED PRACTICE for Example 4 Factor the polynomial completely m 3 –2m 2 +8m Factor out m. = m(m – 4)(m +2) Find two factors of –8 that have a sum of –2. m(m 2 – 2m –8) m 3 –2m 2 +8m =