Print Tutorial Click Screen for Next Step Return to Main MenuMenu Solving Kinematic Problems Using Equation II d = ½ (vi + vf)t Section 1
Print Tutorial Click Screen for Next Step Return to Main MenuMenu A car is traveling at 30.0 m/s and accelerates to 75.0 m/s. If it took 40.0 seconds to complete the acceleration, what distance did the car travel? List the variables and their values. vi = 30.0 m/s vf = 75.0 m/s t = 40.0 sec d = ?
Print Tutorial Click Screen for Next Step Return to Main MenuMenu Use equation II d = ½ (vi + vf)t Substitute the known values. d = ½ (30.0 m/s m/s)(40.0 sec)
Print Tutorial Click Screen for Next Step Return to Main MenuMenu Solve for the unknown variable. d = 2100 m
Print Tutorial Click Screen for Next Step Return to Main MenuMenu Section 2 A car starts at rest and accelerates for 24.0 sec. How fast is it going after sec? a) 22.5 m/s b) m/s c) m/s d) 86.0 m/s
Print Tutorial Click Screen for Next Step Return to Main MenuMenu List the variables and their values. vi = 0 it is at rest to start d = m t = 24.0 sec vf = ?
Print Tutorial Click Screen for Next Step Return to Main MenuMenu Use equation II d = ½ (vi + vf)t Substitute the known values m = ½ (0+vf)(24.0 sec)
Print Tutorial Click Screen for Next Step Return to Main MenuMenu Solve for the unknown variable. If you picked a) try again. If you picked c) try again. If you picked d) try again. If you picked b) you are correct. Vf = 38.3 m/s
Print Tutorial Click Screen for Next Step Return to Main MenuMenu Section 3 Now you will solve problems by yourself and see if you get the correct answer.
Print Tutorial Click Screen for Next Step Return to Main MenuMenu You are going to walk m. You are starting at 5.6 m/s and are walking for sec. What is your final velocity?
Print Tutorial Click Screen for Next Step Return to Main MenuMenu Answer is Vf = 1.06 m/s
Print Tutorial Click Screen for Next Step Return to Main MenuMenu A car is traveling at 30.0 m/s and observes a stop sign. The car can safely slowdown in m. If the car comes to a complete stop, how much time did it take to stop?
Print Tutorial Click Screen for Next Step Return to Main MenuMenu The answer is t = sec