Deductive Reasoning “The proof is in the pudding.” “Indubitably.” Je solve le crime. Pompt de pompt pompt." Le pompt de pompt le solve de crime!" 2-1 Classroom.

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Presentation transcript:

Deductive Reasoning “The proof is in the pudding.” “Indubitably.” Je solve le crime. Pompt de pompt pompt." Le pompt de pompt le solve de crime!" 2-1 Classroom Ex. P 34.

Underline the hypothesis and box the conclusion. 1. If 2x – 1 = 5, then x = If she’s smart, then I’m a genius. 3. 8y = 40 implies y = 5

2-1 Classroom Ex. P 34. Underline the hypothesis and box the conclusion RS = RT if S is the midpoint of. “only if” and “if” are not the same.

7. Convert 5 and 6 into a biconditional

Provide a counterexample to show that each statement is false. You may use words or a diagram. 8. If, then B is the midpoint of. 9. If a line lies in a vertical plane, then the line is vertical. 10. If a number is divisible by 4, then it is divisible by is divisible by 4 but it is not divisible by 6. A B C Horizontal line

Provide a counterexample to show that each statement is false. You may use words or a diagram. 11. If X 2 = 49, then x = If today is Friday, then tomorrow is Saturday. State the converse of each conditional. Then indicate if the converse is true or false. If false, state the counterexample. -7 X 2 = 49 is a quadratic equation and has two solutions. If tomorrow is Saturday, then today is Friday. True

13. If x > 0, then x 2 > 0. State the converse of each conditional. Then indicate if the converse is true or false. If false, state the counterexample. 14. If a number is divisible by 6, then it is divisible by 3. If x 2 > 0, then x > 0. False If x = - 5+ Then (- 5) 2 > 0 If a number is divisible by 3, then it is divisible by 6. False 9 9 is divisible by 3 But 9 is not divisible by 6.

15. If 6x = 18, then x = 3. State the converse of each conditional. Then indicate if the converse is true or false. If false, state the counterexample. 16. Give an example of a false conditional whose converse is true. Cond: If x 2 > 0, then x > 0. Conv: If x > 0, then x 2 > 0. False If x = - 5+ Then (- 5) 2 > 0 True positive numbers squared are always positive. If x = 3, then 6x = 18. True

C’est fini. Good day and good luck.