Entry Task: Feb 27 th -28 th Block #1 Grab New Entry task sheet Write the question down What are the mole ratios for this reaction? Be sure to label 2H.

Slides:



Advertisements
Similar presentations
“Stoichiometry” Mr. Mole u First… –A bit of review.
Advertisements

Limiting Reactant.
Stoichiometry SAVE PAPER AND INK!!! When you print out the notes on PowerPoint, print "Handouts" instead of "Slides" in the print setup. Also, turn off.
Stoichiometry SAVE PAPER AND INK!!! When you print out the notes on PowerPoint, print "Handouts" instead of "Slides" in the print setup. Also, turn off.
Chocolate Chip Cookies!!
1.4.1 Calculate theoretical yields from chemical equations.
Stoichiometry Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups all-purpose.
It’s time to learn about.... What's The Difference Between Roast Beef And Pea Soup? Anyone Can Roast Beef.
 The Mole Chemists have adopted the mole concept as a convenient way to deal with the enormous numbers of atoms, molecules or ions in the samples they.
Stoichiometry The Mole: Review A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000, X (in scientific.
Stoichiometry.
Stoichiometry Chemistry I: Chapter 12 Chemistry IH: Chapter 12.
Cookies and Chemistry…Huh!?!? Just like chocolate chip cookies have recipes, chemists have recipes as well Just like chocolate chip cookies have recipes,
Classic Butter Cookies 2 1/2 cups all-purpose flour 1 cup butter 1/2 cup white sugar 2 eggs 1/2 teaspoon almond extract Bake at 350ºF for 10 minutes.
Quantitative study of chemical reactions The basic question - how much? - is the object of stoichiometry. It’s like baking a cake…or two.
Chemical Calculations
WHAT IS STOICHIOMETRY 1/6/12 Chapter 12 Section 12.1.
Stoichiometry “The Mathematics of Chemical Reactions” By: Ms. Buroker.
Stoichiometry I                                                               Mole-Mole.
Stoichiometric Calculations
Cookies and Chemistry…Huh!?!? Just like chocolate chip cookies have recipes, chemists have recipes as well Just like chocolate chip cookies have recipes,
Stoichiometry Chemistry IH: Chapter 9 Stoichiometry The method of measuring amounts of substances and relating them to each other.
Stoichiometry Baking Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups.
Stoichiometry A branch of chemistry that deals with the quantitative relationship that exist between the reactants and products of in chemical reactions.
Stoichiometry Chemistry I: Chapter 12 Chemistry IH: Chapter 12.
C.7 (notes) – C.8 (practice) In which you will learn about… In which you will learn about… Mole ratios Mole ratios stoichiometry stoichiometry.
Chocolate Chip Cookies!!
Bell Work “We’re Cookin’ Now” Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2.
Stoichiometry Chemistry 11 Chapter 2 Pg The Mole A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000,000.
Stoichiometry Chemistry I: Chapter 9 Molar Mass of Compounds The molar mass (MM) of a compound is determined the same way, except now you add up all.
Stoichiometry Section 12.1.
C. Johannesson Stoichiometric Calculations Stoichiometry – Ch. 9.
Chapter 9 Section 2. Chocolate chip cookies 1 c. butter ½ c. granulated sugar 1 c. brown sugar 1 tsp. vanilla 2 eggs 2 ½ c. flour 1 tsp. baking soda 1.
It’s time to learn about.... Stoichiometry Stoichiometry : Mole Ratios to Determining Grams of Product At the conclusion of our time together, you should.
Chp 9: Stoichiometry Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups.
Stoichiometry Topic – Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs.
It’s time to learn about . . .
Stoichiometry Chapter 12
Stoichiometry The Mole: Review A counting unit A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000,000 Similar.
Stoichiometry The Mole A counting unit A counting unit Similar to a dozen, except instead of 12, it’s 602,000,000,000,000,000,000,000 Similar to a dozen,
Chapter 12 - Stoichiometry I ‘m back! I ‘m back!
It’s time to learn about.... Stoichiometry Stoichiometry : Mole Ratios to Determining Grams of Product At the conclusion of our time together, you should.
Stoichiometry. Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups all-purpose.
Stoichiometry Chemistry I/IH: Chapter 11 1 Stoichiometry The method of measuring amounts of substances and relating them to each other. 2.
Stoichiometry Chapter 12. Chocolate Chip Cookies!! 1 cup butter ;1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs ; 2 1/2.
Stoichiometry molar mass Avogadro’s number Grams Moles Particles molar mass Avogadro’s number Grams Moles Particles Everything must go through Moles!!!
Percent Composition Empirical Formulas Moles Stoichiometry 1.
Stoichiometry Chapter 12
Stoichiometry Adapted from
Stoichiometry.
Stoichiometry.
Stoichiometry (Ch 12) Stoichiometry is the calculation of amounts of substances involved in a chemical reaction. Coefficients in chemical reactions show.
Stoichiometry.
Stoichiometry Chemistry I: Chapter 11
Stoichiometry.
Stoichiometry.
Chemical Stoichiometry
Stoichiometry.
Stoichiometry.
Stoichiometry (Ch 12) Stoichiometry is the calculation of amounts of substances involved in a chemical reaction. Coefficients in chemical reactions show.
Stoichiometry Chemistry I: Chapter 11
Stoichiometry.
Stoichiometry.
Bellringer I have 2 eggs. How many cookies can I make?
Stoichiometry based on the law of conservation of mass
Stoichiometry.
Stoichiometry.
Stoichiometry.
Stoichiometry.
Stoichiometry Chemistry I: Chapter 12 Chemistry I HD: Chapter 9
Presentation transcript:

Entry Task: Feb 27 th -28 th Block #1 Grab New Entry task sheet Write the question down What are the mole ratios for this reaction? Be sure to label 2H 2 + O 2  2H 2 O You have 5 minutes!

Agenda: Sign off and Discuss Ch reading notes Stoichiometry notes#1

I can… Identify the quantitative relationship in a balanced chemical equation Determine the mole ratios from a balanced chemical reaction

Stoichiometry Stoichiometry is based on law of conservation of mass The law of conservation of mass states that the mass of reactants in a chemical reaction will equal the mass of products produced from that reaction.

Stoichiometry Write the reaction for iron reacting with oxygen 4Fe (s) + 3O 2 (g)  2Fe 2 O 3 (s) What do the coefficients represent? The represent the number of moles of that particular substance

Stoichiometry So in our Iron reacting with oxygen reaction, there are ____moles of iron reacting with ____moles of oxygen to produce ____ moles of Iron II oxide

Stoichiometry We can change the number of moles (along with the molecular mass) to calculate this in to grams. 4Fe (s) + 3O 2 (g)  2Fe 2 O 3 (s) How many grams of iron are reacting in this equation? Convert from mole to gram.- Show work below. Fe= g x 4 = g 4 moles of Fe 1 moles of Fe g of Fe = 223.4g of Fe

Stoichiometry 4Fe (s) + 3O 2 (g)  2Fe 2 O 3 (s) How many grams of oxygen are reacting in this equation? Convert from mole to gram.- Show work below. O= g x 6 = g 3 moles of O 2 1 moles of O g of O 2 = g of O 2

Stoichiometry 4Fe (s) + 3O 2 (g)  2Fe 2 O 3 (s) How many grams of iron II oxide are reacting in this equation? Convert from mole to gram.- Show work below. Fe 2 O 3 = (Fe x 4) g 2 moles of Fe 2 O 3 1 moles of Fe 2 O g of Fe 2 O 3 = g of O 2 + (O x 6) g = g

Stoichiometry Mole Ratio: Is the ratio between the number of moles of any two substances in a balanced chemical equation Read through the Aluminum + bromine reaction- note the mole ratio relationships between reactants and between reactants and products.

Stoichiometry Practice Problems- Determine all possible the mole ratios for the following. 1. 4Al (s) + 3O 2 (g)  2Al 2 O 3 (s) What is the ratio between aluminum and oxygen? Answer: 4 mol of Al to 3 mol of O 2 OR 3 mol of O 2 to 4 mol of Al

Stoichiometry Practice Problems- Determine all possible the mole ratios for the following. 1. 4Al (s) + 3O 2 (g)  2Al 2 O 3 (s) What is the ratio between aluminum and aluminum oxide? Answer: 4 mol of Al to 2 mol of Al 2 O 3 OR 2 mol of Al 2 O 3 to 4 mol of Al

Stoichiometry Practice Problems- Determine all possible the mole ratios for the following. 1. 4Al (s) + 3O 2 (g)  2Al 2 O 3 (s) What is the ratio between oxygen and aluminum oxide? Answer: 3 mol of O 2 to 2 mol of Al 2 O 3 OR 2 mol of Al 2 O 3 to 3 mol of O 2

Chocolate Chip Cookies!! 1 cup butter 1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs 2 1/2 cups all-purpose flour 1 teaspoon baking soda 1 teaspoon salt 2 cups semisweet chocolate chips Makes 3 dozen How many eggs are needed to make 3 dozen cookies? How much butter is needed for the amount of chocolate chips used? How many eggs would we need to make 9 dozen cookies? How much brown sugar would I need if I had 1 cup white sugar? 2 eggs 1 cup 6 eggs 2 cup

Cookies and Chemistry…Huh!?!? Just like chocolate chip cookies have recipes, chemists have recipes as well. Instead of calling them recipes, we call them reaction equations Furthermore, instead of using cups and teaspoons, we use moles. Lastly, instead of eggs, butter, sugar, etc. we use chemical compounds as ingredients.

Stoichiometry Stoichiometry is the study of quantitative relationships between amounts of reactants and products formed by a chemical reaction- RATIOS!!. ___H 2 (g) + ___O 2 (g)  ___H 2 O (l) 22 For this reaction, 2 moles of hydrogen gas reacts with 1 mole of oxygen gas to create 2 moles of water molecules.

Balance: ___H 2 (g) + ___O 2 (g)  ___H 2 O (l) 22 What is the ratio of hydrogen gas to oxygen gas?2 : 1 What is the ratio of oxygen gas to water?1 : 2 What is the ratio of hydrogen gas to water?2 : 2 What is the ratio of water to oxygen gas?2 : 1 Translate into written equation: 2 moles of hydrogen gas reacts with 1 mole of oxygen gas to produce 2 moles of water

2H 2 (g) + O 2 (g)  2H 2 O(l) a. How many moles of H 2 were used if 4 moles of H 2 O were produced? = moles H 2 4 mol H 2 O 4 Mole ↔ mole Units match 2 mol H 2 O 2 mol H 2 b. How many moles of H 2 were used if moles of H 2 O were produced? = moles H molH 2 O Units match 2 mol H 2 O 2 mol H 2 Mole ratio

2H 2 (g) + O 2 (g)  2H 2 O(l) c. How many moles of O 2 were used if 2.36 moles of H 2 O were produced? = moles O mol H 2 O 1.18 Mole ↔ mole Units match 2 mol H 2 O 1 mol O 2 d. How many moles of H 2 O were produced if 36.9 moles of H 2 were used? = moles H 2 O 36.9 mol H Units match 2 mol H 2 2 mol H 2 O Mole ratio

You Try!! Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide. Provide a balanced equation below! 1. Formula of each substance, then set up equation, lastly balance the equation.

You Try!! Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide. Provide a balanced equation below! 1. Formula of each substance, then set up equation, lastly balance the equation. ___ Ag

You Try!! Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide. Provide a balanced equation below! 1. Formula of each substance, then set up equation, lastly balance the equation. ___Ag + ___S 8

You Try!! Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide. Provide a balanced equation below! 1. Formula of each substance, then set up equation, lastly balance the equation.  ___ Ag 2 S ___Ag + ___S 8

You Try!! Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide. Provide a balanced equation below! 1. Formula of each substance, then set up equation, lastly balance the equation.  ___ Ag 2 S ___Ag + ___S 8 816

a. How many moles of S 8 were used if 36 moles of Ag 2 S were produced? You Try!! Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide 16Ag + S 8  8Ag 2 S WHY did I balance the equation? To get the mole ratios

a. How many moles of S 8 were used if 36 moles of Ag 2 S were produced? You Try!! Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide Now What? Put starting amounts WITH label in correct spot 16Ag + S 8  8Ag 2 S 36 mol Ag 2 S

a. How many moles of S 8 were used if 36 moles of Ag 2 S were produced? You Try!! Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide 16Ag + S 8  8Ag 2 S What mole ratio would I use in this problem? 8 moles Ag 2 S 1 mole S 8 8 moles Ag 2 S

a. How many moles of S 8 were used if 36 moles of Ag 2 S were produced? You Try!! Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide WHY this ratio? 1 mole S 8 8 moles Ag 2 S 1 mole S 8 needs to be on top because that is what the question is asking for. 16Ag + S 8  8Ag 2 S

a. How many moles of S 8 were used if 36 moles of Ag 2 S were produced? You Try!! Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide 16Ag + S 8  8Ag 2 S 36 mol Ag 2 S 1 mole S 8 8 moles Ag 2 S

a. How many moles of S 8 were used if 36 moles of Ag 2 S were produced? = moles S 8 36 mol Ag 2 S 4.5 You Try!! Units match 8 mol Ag 2 S 1 mol S 8 Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide Mole ratio 16Ag + S 8  8Ag 2 S

You Try!! b. How many moles of Ag 2 S were produced if 7 moles of Ag were used? = moles Ag 2 S 7 mol Ag 3.5 Units match 16 mol Ag 8 mol Ag 2 S Silver metal reacts with sulfur solid (S 8 ) to create silver I sulfide Mole ratio 16Ag + S 8  8Ag 2 S

Stoichiometry- Grams ___H 2 (g) + ___O 2 (g)  ___H 2 O (l) 22 What is the molar mass of hydrogen gas? g What is the molar mass of oxygen gas? g What is the molar mass of water? g

a. How many moles of H 2 were used if 72.0g of H 2 O were produced? = moles H g H 2 O 4.00 gram ↔ mole 2H 2 (g) + O 2 (g)  2H 2 O(l) 72.0g? moles Units match 1 mol H 2 O 18 g H 2 O 2 mol H 2 O 2 mol H 2 72 X 2 = X 2 = 36 Mole/Gram conversion Mole/Mole ratio

b. How many moles of H 2 O were produced if 36.5g of H 2 were used? = moles H 2 O 36.5 g H gram ↔ mole 2H 2 (g) + O 2 (g)  2H 2 O(l) ? moles36.5 g Units match 1 mol H g H 2 2 mol H 2 2 mol H 2 O 36.5 X 2 = X 2 = Mole/Gram conversion Mole/Mole ratio

You Try! Aluminum metal reacts with bromine gas to create aluminum bromide. Provide balanced equation below! 2Al + 3Br 2  2AlBr 3

a. How many moles of AlBr 3 were produced if 65.5g of Br 2 were used? = moles AlBr g Br You Try! 2Al + 3Br 2  2AlBr 3 ? moles65.5 g Units match 1 mol Br g Br 2 3 mol Br 2 2 mol AlBr X 2 = X 3 = Mole/Gram conversion Mole/Mole ratio

b. How many moles of Al were used if 125g of AlBr 3 were produced? = moles Al 125 g AlBr You Try! 2Al + 3Br 2  2AlBr 3 ? moles 125 g Units match 1 mol AlBr g AlBr 3 2 mol AlBr 3 2 mol Al 125 X 2 = X 2 = Mole/Gram conversion Mole/Mole ratio

a. How many grams of AlBr 3 were produced if 2.35 moles of Al were used? = grams AlBr moles Al 627 Moles  Grams 2Al + 3Br 2  2AlBr 3 ? grams 2.35 moles Units match 2 mol AlBr 3 2 mol Al1 mol AlBr g AlBr X 2 X = Mole/Gram conversion Mole/Mole ratio

a. How many grams of Br 2 were used if 5.75 moles AlBr 3 were produced? = grams Br moles AlBr Moles  Grams 2Al + 3Br 2  2AlBr 3 ? grams5.75 moles Units match 3 mol Br 2 2 mol AlBr 3 1 mol Br g Br X 3 X = Mole/Gram conversion Mole/Mole ratio 1380

You Try! YOU TRY! Gold III sulfide reacts with hydrogen gas to create gold metal and dihydrogen monosulfide Provide balanced equation below! __Au 2 S 3 + __H 2  __Au + __ H 2 S

You Try! YOU TRY! Gold III sulfide reacts with hydrogen gas to create gold metal and dihydrogen monosulfide Provide balanced equation below! Au 2 S 3 + 3H 2  2Au + 3H 2 S

a. How many grams of H 2 S were produced 3.25 moles of hydrogen gas were used? = grams H 2 S 3.25 moles H Moles  Grams Au 2 S 3 + 3H 2  2Au + 3H 2 S ? grams3.25 moles Units match 3 mol H 2 S 3 mol H 2 1 mol H 2 S g H 2 S 3.25 X 3 X = Mole/Gram conversion Mole/Mole ratio

b. How many grams of H 2 were needed to react with 3.25 moles of gold III sulfide? = grams H moles Au 2 S Moles  Grams Au 2 S 3 + 3H 2  2Au + 3H 2 S ? grams3.25 moles Units match 3 mol H 2 1 mol Au 2 S 3 1 mol H g H X 3 X = Mole/Gram conversion Mole/Mole ratio