Newton’s Third Law If two objects interact, the force exerted by object 1 on object 2 is equal in magnitude and opposite in direction to the force.

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Presentation transcript:

Newton’s Third Law If two objects interact, the force exerted by object 1 on object 2 is equal in magnitude and opposite in direction to the force exerted by object 2 on object 1 Note on notation: is the force exerted by A on B

Newton’s Third Law, Alternative Statements Forces always occur in pairs A single isolated force cannot exist The action force is equal in magnitude to the reaction force and opposite in direction One of the forces is the action force, the other is the reaction force It doesn’t matter which is considered the action and which the reaction The action and reaction forces must act on different objects and be of the same type

Action-Reaction Examples, 1 The force exerted by object 1 on object 2 is equal in magnitude and opposite in direction to exerted by object 2 on object 1

Action-Reaction Examples, 2 The normal force (table on monitor) is the reaction of the force the monitor exerts on the table Normal means perpendicular, in this case The action (Earth on monitor) force is equal in magnitude and opposite in direction to the reaction force, the force the monitor exerts on the Earth

Free Body Diagram In a free body diagram, you want the forces acting on a particular object Model the object as a particle The normal force and the force of gravity are the forces that act on the monitor

Free Body Diagram, cont. The most important step in solving problems involving Newton’s Laws is to draw the free body diagram Be sure to include only the forces acting on the object of interest Include any field forces acting on the object Do not assume the normal force equals the weight

Applications of Newton’s Law Assumptions Objects can be modeled as particles Interested only in the external forces acting on the object can neglect reaction forces Initially dealing with frictionless surfaces Masses of strings or ropes are negligible The force the rope exerts is away from the object and parallel to the rope When a rope attached to an object is pulling it, the magnitude of that force is the tension in the rope

Particles in Equilibrium If the acceleration of an object that can be modeled as a particle is zero, the object is said to be in equilibrium The model is the particle in equilibrium model Mathematically, the net force acting on the object is zero

Equilibrium, Example 1a A lamp is suspended from a chain of negligible mass The forces acting on the lamp are the downward force of gravity the upward tension in the chain Applying equilibrium gives

Equilibrium, Example 1b Not an action-reaction pair Both act on the lamp Action-reaction forces Lamp on chain and chain on lamp Chain on ceiling and ceiling on chain Only the forces acting on the lamp are included in the free body diagram

Equilibrium, Example 2a Example 5.4 Conceptualize the traffic light Assume cables don’t break Nothing is moving Categorize as an equilibrium problem No movement, so acceleration is zero Model as a particle in equilibrium

Equilibrium, Example 2b Analyze Need two free-body diagrams Apply equilibrium equation to the light Apply equilibrium equations to the knot

Equilibrium, Example 2 c Analyze, cont. Finalize Find T3 from applying equilibrium in the y-direction to the light Find T1 and T2 from applying equilibrium in the x- and y-directions to the knot Finalize Think about different situations and see if the results are reasonable

Particles Under a Net Force If an object that can be modelled as a particle experiences an acceleration, there must be a nonzero net force acting on it Model is particle under a net force model Draw a free-body diagram Apply Newton’s Second Law in component form

Newton’s Second Law, Example 1a Forces acting on the crate: A tension, acting through the rope, is the magnitude of force The gravitational force, The normal force, , exerted by the floor

Newton’s Second Law, Example 1b Apply Newton’s Second Law in component form: Solve for the unknown(s) If the tension is constant, then a is constant and the kinematic equations can be used to more fully describe the motion of the crate

Note About the Normal Force The normal force is not always equal to the gravitational force of the object For example, in this case may also be less than

Inclined Planes Forces acting on the object: The normal force acts perpendicular to the plane The gravitational force acts straight down Choose the coordinate system with x along the incline and y perpendicular to the incline Replace the force of gravity with its components

Multiple Objects When two or more objects are connected or in contact, Newton’s laws may be applied to the system as a whole and/or to each individual object Whichever you use to solve the problem, the other approach can be used as a check

Multiple Objects, Conceptualize Observe the two objects in contact Note the force Calculate the acceleration Reverse the direction of the applied force and repeat

Multiple Objects, Example 1 First treat the system as a whole: Apply Newton’s Laws to the individual blocks Solve for unknown(s) Check: |P12| = |P21|

Multiple Objects, Example 2 – Atwood’s Machine Forces acting on the objects: Tension (same for both objects, one string) Gravitational force Each object has the same acceleration since they are connected Draw the free-body diagrams Apply Newton’s Laws Solve for the unknown(s)

Exploring the Atwood’s Machine Vary the masses and observe the values of the tension and acceleration Note the acceleration is the same for both objects The tension is the same on both sides of the pulley as long as you assume a massless, frictionless pulley

Multiple Objects, Example 3 Draw the free-body diagram for each object One cord, so tension is the same for both objects Connected, so acceleration is the same for both objects Apply Newton’s Laws Solve for the unknown(s)

Problem-Solving Hints Newton’s Laws Conceptualize Draw a diagram Choose a convenient coordinate system for each object Categorize Is the model a particle in equilibrium? If so, SF = 0 Is the model a particle under a net force? If so, SF = m a

Problem-Solving Hints Newton’s Laws, cont Analyze Draw free-body diagrams for each object Include only forces acting on the object Find components along the coordinate axes Be sure units are consistent Apply the appropriate equation(s) in component form Solve for the unknown(s) Finalize Check your results for consistency with your free-body diagram Check extreme values