GPS 10 Reaction Review. Types of Reactions  Synthesis  Decomposition  Single Replacement  Double Replacement  Combustion  Neutralization  Redox.

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Presentation transcript:

GPS 10 Reaction Review

Types of Reactions  Synthesis  Decomposition  Single Replacement  Double Replacement  Combustion  Neutralization  Redox

Synthesis  Element + Element yields Compound

Mg + O 2 MgO

Na + Br 2 NaBr

Decomposition  A compound breaks apart into two or more elements or compounds

H2OH2O H 2 + O 2

NaCl Na + Cl 2

Single Replacement  An element reacts with a compound

Na 3 N + F 2 NaF + N 2

NaCl + Mg MgCl 2 + Na

Double Replacement  A compound reacts with a compound PbCl 2 + Li 2 SO 4 → PbSO 4 + LiCl

CaCl 2 + Mg(NO 3 ) 2 Ca(NO 3 ) 2 + MgCl 2

NaOH + Mg(NO 3 ) 2 NaNO 3 + Mg(OH) 2

KCl + H 3 PO 4

Combustion  A hydrocarbon reacts with oxygen

C 2 H 2 + O 2 H 2 O + CO 2

C 6 H 12 O 6 + O 2 H 2 O + CO 2

KOH + H 3 PO 4 H 2 O + K 3 PO 4

a)____ Al 2 (SO 3 ) 3 + ____ Mg(OH) 2 b)____ C 3 H 8 + ___ O 2 c)____ Zn + ____ HCl Summary #4

CuBr 2 + Zn ZnBr 2 + Cu  What is being reduced?  What is being oxidized?  What is the reducing agent?  What is the oxidizing agent? Cu Zn Cu Zn

Fe + ZnCl 2 FeCl 3 + Zn a.what is being oxidize? b.what is being reduced? c.This reaction is a single replacement reaction but may also be classified as a reaction. Summary #6 Fe Zn redox

H 2 CO 3 + Ca(C 2 H 3 O 2 ) 2 2HC 2 H 3 O 2 + CaCO 3 How many oxygen on both sides of the balanced equation? 7 oxygen

Fe + O 2 → Fe 2 O 3 a.After balancing the equation, how many atoms of oxygen are on each side of the equation? b.If we started with g of iron and 3.45 g of oxygen gas, how much iron (III) oxide is produced? Summary # g

One mole of magnesium phosphate reacts with 6 moles of sodium hydroxide to produce 2 moles of sodium phosphate and 3 moles of magnesium hydroxide. Mg 3 (PO 4 ) 2 + NaOH Na 3 PO 4 + Mg(OH)

beryllium sulfide + gallium carbonate gallium sulfide + beryllium carbonate Summary 8d. Coefficients to balance should be 3, 1, 1, 3

a)Lead + oxygen gas → lead (IV) oxide b)Iron (II) nitride → iron + nitrogen gas Summary #8