Solving an Absolute-Value Inequality Recall that  x  is the distance between x and 0. If  x  8, then any number between  8 and 8 is a solution of.

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Solving an Absolute-Value Inequality Recall that  x  is the distance between x and 0. If  x  8, then any number between  8 and 8 is a solution of the inequality.  8  7  6  5  4  3  2  Recall that | x | is the distance between x and 0. If | x |  8, then any number between  8 and 8 is a solution of the inequality.

Solve | x  4 | < 3 Solving an Absolute-Value Inequality x  4 IS POSITIVE x  4 IS NEGATIVE | x  4 |  3 x  4   3 x  7 | x  4 |  3 x  4   3 x  1 Reverse inequality symbol.  This can be written as 1  x  7. The solution is all real numbers greater than 1 and less than 7.

2x  1   9 | 2x  1 |  3  6 | 2x  1 |  9 2x   10 2x + 1 IS NEGATIVE  x   5 Solve | 2x  1 |  3  6 and graph the solution. | 2x  1 |  3  6 | 2x  1 |  9 2x  1  +9 2x  8 2x + 1 IS POSITIVE x  4 Solving an Absolute-Value Inequality Reverse inequality symbol. | 2x  1 |  3  6 | 2x  1 |  9 2x  1  +9 x  4 2x  8 | 2x  1 |  3  6 | 2x  1 |  9 2x  1   9 2x   10 x   5 2x + 1 IS POSITIVE 2x + 1 IS NEGATIVE  6  5  4  3  2  The solution is all real numbers greater than or equal to 4 or less than or equal to  5. This can be written as the compound inequality x   5 or x  4.  5

Writing an Absolute-Value Inequality You work in the quality control department of a manufacturing company. The diameter of a drill bit must be between 0.62 and 0.63 inch. Write an absolute-value inequality to represent this requirement. a. Does a bit with a diameter of inch meet the requirement? b.

Writing an Absolute-Value Inequality The diameter of a drill bit must be between 0.62 and 0.63 inch. a. Write an absolute-value inequality to represent this requirement. Let d represent the diameter (in inches) of the drill bit. Write a compound inequality  d  0.63 Find the halfway point Subtract from each part of the compound inequality   d   0.63    d   Rewrite as an absolute-value inequality. | d  |  This inequality can be read as “the actual diameter must differ from inch by no more than inch.”

The diameter of a drill bit must be between 0.62 and 0.63 inch. b. Does a bit with a diameter of meet the requirement? Writing an Absolute-Value Inequality | d  |  |  |  |  |  Because  0.005, the bit does meet the requirement  0.005