Stoichiometry and the mole- Your new bffl November 2 2 +3 3 -1, 2.009 * 10 3  Objective:  SWBAT perform stoichiometric conversions from mole to mass,

Slides:



Advertisements
Similar presentations
Catalyst – , * 10 3 Welcome Back! Monday Mystery Element! 1. Like many rare earth elements, is used to make phosphors in TVs 2. Attracted.
Advertisements

The Mole Avogadro’s Number. What is a Mole? The mole is a counting unit, similar to 1 dozen. 1 dozen eggs = 12 eggs 1 mole of eggs = 6.02x10 23 eggs.
STOY-KEE-AHM-EH-TREE. It‘s the study of amounts of substances that are involved in reactions.
(STOY-KEE-AHM-EH-TREE). Stoichiometry is the part of chemistry that studies amounts of reactants and products that are involved in reactions. Chemists.
Chapter 9 Stoichiometry.
Stoichiometry.
Stoichiometry! The math of chemistry .
Bell Ringer What is a Mole? What is the mass of a NaCl molecule?
Catalyst – May 6-4, 2011 Grab a calculator! Monday Mystery Element! 1. Used to make batteries 2. Can cause kidney failure and high blood pressure 3. Found.
1 Chapter 4 Recycling and Chemical Mathematics. 2 Nature’s Recycling – The carbon cycle.
Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chemical Stoichiometry Stoichiometry - The study of quantities of materials consumed.
and cooking with chemicals
Chapter 3 - Stoichiometry It is important to be able to quantify the amount of reagent(s) that will be needed to produce a given amount of product(s).
April 3, 2014 Stoichiometry. Stoichiometry is the study of quantities of materials consumed and produced in chemical reactions Stoikheion (Greek, “element”)
Chapter 12 Stoichiometry part 1. Stoichiometry The study of quantitative relationships between amounts of reactants used and products formed by a chemical.
Aim: Using mole ratios in balanced chemical equations.
Stoichiometry II. Solve stoichiometric problems involving moles, mass, and volume, given a balanced chemical reaction. Include: heat of reaction Additional.
1 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations.
Chapter 12 Review “Stoichiometry”
Stoichiometry & the Mole. Dimensional Analysis Review How many seconds are in 5.0 hours?
STOICHIOMETRY Chapter 9: Pages
Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chemical Stoichiometry Stoichiometry - The study of quantities of materials consumed.
The Mole Stoichiometry Limiting Reactant % Yield
Review. Stoichiometry u Greek for “measuring elements” u The calculations of quantities in chemical reactions based on a balanced equation. u We can interpret.
Solving Limiting Reactant Problems. Background In limiting reactant problems, we have the amounts (masses or mols) of two of the reactants. The problem.
Sec. 11.2: Stoichiometric Calculations
Chemical Reactions BELLWORK BRIEFLY WRITE ABOUT A SCIENTIFIC OBSERVATION YOU MADE RECENTLY.
Stoichiometry Chapter 9. Balanced Equations  Coefficients tell you how many times that particular molecule is needed in a reaction  Subscripts tell.
December 35 0, x What is the molar mass (g) of lithium hydroxide, LiOH? 2. How many atoms are in 2.05 moles of O 2 ? (Train Tracks!) 3. Challenge!
Moley, moley, mole…  Objective:  SWBAT perform stoichiometric conversions from mole to mass, from mass to mass  Catalyst:  What is.25 of a dozen?
REVIEW: Converting to MOLES WHAT DOES A MOLE REPRESENT? 6.02 x MASS # MOLES Molecular Weight # particles # MOLES 6.02 X Volume of a gasMoles.
Bell Work: Mole Ratios 2 C 4 H 10 + ___ O 2 → ___ CO 2 + ___ H 2 O 1. Finish balancing the equation. How many moles of oxygen will react? 3. water.
The Mole & Stoichiometry!
Stoichiometry – Chemical Quantities Notes. Stoichiometry Stoichiometry – Study of quantitative relationships that can be derived from chemical formulas.
Chemical Quantities Chapter 6 Image source:
Stoichiometry Chapter Stoichiometry Stoichiometry is the study of quantitative relationships between the amounts of reactants used and amounts.
STOICHIOMETRY Calculations Based on Chemical Equations.
Chap. 9: Stoichiometry Identify the mole ratio of any two species in a chemical reaction. Calculate theoretical yields from chemical equations.
No Bell Ringer Today. We will have a test next Tuesday.
Unit 4: Formula Stoichiometry. What is stoichiometry? Deals with the quantitative information in chemical formula or chemical reaction. Deals with the.
What is Stoichiometry? Objectives: 6.0 Solve stoichiometric problems involving relationships among the number of particles, moles, and masses of reactants.
Stoichiometry Mass Calculations. Yesterday: Mole to Mole Ratios – relating reactants and products in a chemical equation If we have a balanced chemical.
Stoichiometry is… Greek for “measuring elements” Defined as: calculations of the quantities in chemical reactions, based on a balanced equation. There.
Stoichiometry and cooking with chemicals.  Interpret a balanced equation in terms of moles, mass, and volume of gases.  Solve mole-mole problems given.
Learning Objectives Perform stoichiometric calculations to determine – Mass relationships between products and reactants Stoichiometric Calculations.
© L.C.Lee 1997 Stoichiometry: Part 1: Mole Relationships in Chemical Equations.
Catalyst – May 16/2 3, 2011 Grab a calculator please! 1. What is 0.25 of a dozen? 2. If a dozen hotdogs weighs 3 kilograms, how much does 3 dozen hotdogs.
Moles and Molar Mass. Counting with Moles Mole – amount of a substance that contains 6.02 x particles of that substance 1 mole of the following.
Mass-Mass Conversions 56.0 g N 2 x g N 2 g NH = 1904 = When nitrogen and hydrogen react, they form ammonia gas, which has the formula.
Stoichiometry Chapter 12. Chocolate Chip Cookies!! 1 cup butter ;1/2 cup white sugar 1 cup packed brown sugar 1 teaspoon vanilla extract 2 eggs ; 2 1/2.
Chapter 12: Stoichiometry
Stoichiometry Grams – Moles Grams – Grams. What is Stoichiometry? Chemists are often responsible for designing a chemical reaction and analyzing the products.
Today’s Agenda Catalyst Holy Moley! Molar Conversions Work Time
Back to Mole Town! Agenda Review Mole Town map. Intro stoichiometry.
STOICHIOMETRY Chapter 9
Calculations with Equations
Chapter 12 Stoichiometry
Science Starter (Week 11, Day 1)
11.1 Defining Stoichiometry Ashley Lardizabal Discovery School
6.1 The Mole Obj 1 a-c, 2 Chemistry.
Stoichiometry Chapter 11.
Calculations Based on Chemical Equations
Stoichiometry Unit 8 Lesson 1.
Stoichiometry Unit 8 Lesson 1.
9.1 NOTES Stoichiometry.
Calculations Based on Chemical Equations
STOICHIOMETRY Chapter 9
Stoichiometry.
Stoichiometry Unit 8 Lesson 1.
Stoichiometry Unit 7 Lesson 1.
Presentation transcript:

Stoichiometry and the mole- Your new bffl November , * 10 3  Objective:  SWBAT perform stoichiometric conversions from mole to mass, from mass to mass  Catalyst:  How many basketballs are in a dozen?  How many turkeys are in a dozen?  How was your break? *This week… bring scientific calculators if you have them!

Exit Question  What do you need to do to get where you want to be in this class?

Agenda  Catalyst/Welcome Back  Test Review/Tracking/Corrections  OMG! YOUR NEW BFFL! The mole.  Bring back the train tracks  Exit Question

What is a mole to us chemists?  A benign overgrowth of cells because of a failure in mitosis?  NO! But gross…  A rascly little rodent?  NOOOO!  A TV show featuring celebrities?  NOOOOO!  Then WHAT IS IT?????!!!???!?!?!???!!!!

The Mole Think of the term “ a dozen ”… How many donuts are in a dozen? How many eggs are in a dozen?

The Mole Just like a dozen refers to 12 objects …

The Mole Just like a dozen refers to 12 objects … … the mole refers to …

The Mole Just like a dozen refers to 12 objects … … the mole refers to … 6.02 x particles

The Mole This number is called Avogadro ’ s number … 6.02 x ,000,000,000,000,000,000,000

Avogadro ’ s Number 1 mol = 6.02 x atoms 1 mol = 6.02 x molecules Why do YOU think we would do this?

Interpreting Equations 4 Fe + 3 O 2  2 Fe 2 O 3 “4 moles of iron react with 3 moles of oxygen gas to produce 2 moles of iron(III) oxide” Coefficients in chemical reactions just refer to how many moles are reacting!

Interpreting Equations C 3 H O 2  3 CO 2 + 4H 2 O “1 mole of propane (C 3 H 8 ) reacts with 5 moles of oxygen gas to produce 3 moles of carbon dioxide and 4 moles of water”

How many moles needed? (moles – moles) C 3 H O 2  3 CO 2 + 4H 2 O If you start with 10.0 moles of propane (C 3 H 8 ), how many moles of oxygen gas is needed to fully combust (react)?

How many moles produced? (moles – moles) C 3 H O 2  3 CO 2 + 4H 2 O If you start with 10.0 moles of propane (C 3 H 8 ), how many moles of carbon dioxide will be produced?

What’s the point of all this?  Key Point #1: Stoichiometry relates the amount of REACTANTS with the amount of PRODUCTS.  It all relates back to the mole…  Scientists use stoichiometry to plan reactions!  And guess what else is coming back….

TRAIN TRACKS!!!  Step 1:  What to what?  Step 2:  Write conversion factor(s)  Step 3:  Train tracks

Avogadro ’ s Number 1 mol = 6.02 x atoms How many atoms are in.25 mol N 2 ?

Avogadro ’ s Number 1 mol = 6.02 x atoms How many atoms are in.25 mol N 2 ?.25 mol N 2

Avogadro ’ s Number 1 mol = 6.02 x atoms How many atoms are in.25 mol N 2 ?.25 mol N 2 1 mol N x atoms I guess you can use your calculator for this…

Your turn! Whiteboards. How many atoms are in 1.1 moles of C 12 H 22 O 11 ?

OOOH, I want some more train tracks!  Key Point #2:  Molar mass the amount of grams in the mole of a substance.  But Mr. J, how am I ever going to find out this information?

Molar Mass 1 mol C =

Molar Mass 1 mol C = 12 g C

Molar Mass  The atomic weight of an atom is also the molar mass of that atom.  Carbon has an atomic weight of  In 1 mole of carbon, there are grams.  In 1 mole of sodium, how many grams are there?

Molar Mass 1 mol Na =

Molar Mass 1 mol Na = 23 g Na

Molar Mass-Can you figure out this one?? 1 mol CO 2 =

Molar Mass 1 mol CO 2 = C = 12 gO = 16 gO = 16 g

Molar Mass 1 mol CO 2 = C = 12 g+ O = 16 g + O = 16 g

Molar Mass 1 mol CO 2 = 44 g CO 2 C = 12 g+ O = 16 g + O = 16 g

Molar Mass 1 mol KNO 3 = K = + N = + O =

Molar Mass 1 mol KNO 3 = K = 39 g + N = 14 g + (3) O = 16 g

Molar Mass 1 mol KNO 3 = 101 g K = 39 g + N = 14 g + (3) O = 16 g

Molar Mass- Let’s try a problem 1 mol KNO 3 = 101 g If we have 3.5 moles of KNO 3, how many grams would we have?

Molar Mass 1 mol CH 4 = If we have 20 grams CH 4, how many moles of CH 4 do we have?

Independent Practice  1, 11, 16… we will go over to show you how to solve this hilarious assignment!  Attach your work on a separate sheet of paper.

Exit Question  How many molecules are in a mole of NH 4 ?  How many grams are there in 2.3 moles of NH 4 ?