Lecture 2a. Standardization I Why is a standardization needed? In order to determine the exact concentration of the amino acid solution, we need to know.

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Lecture 2a

Standardization I Why is a standardization needed? In order to determine the exact concentration of the amino acid solution, we need to know the exact concentration of the NaOH (in this lab it has been determined by lab support already). Requirements for primary standards: High purity Stability (low reactivity) Low hygroscopicity High equivalent weight Non-toxicity Ready and cheap availability

Standardization II Examples for Acid-Base titrations: Bases: KHP (potassium hydrogen phthalate, C 6 H 4 (COOK)(COOH), pK a = 5.40, MM= g/mol) C 6 H 4 (COOK)(COOH) + OH - C 6 H 4 (COOK)(COO - ) + H 2 O Acids: TRIS (2-amino-2-hydroxymethyl-propane-1,3-diol, (HOCH 2 ) 3 CNH 2, pK a = 8.07, MM= g/mol), sodium carbonate (Na 2 CO 3, pK a =6.37, 10.32, MM= g/mol) (HOCH 2 ) 3 CNH 2 + H + (HOCH 2 ) 3 CNH 3 +

Standardization III Other Standards (redox titrations): Potassium bromate: sodium thiosulfate solution Sodium chloride: silver nitrate solution Zinc powder: EDTA solution Sodium oxalate: potassium permanganate solution Potassium dichromate: ammonium ferrous sulfate solution

Titration I Why will the titration of the unknown amino acid solution with NaOH will show two equivalence points? Due to the addition of another acid, which is necessary to stabilize the amino acid solutions, the pH-value of the unknown solution is relatively low (pH~2.3). The unknown solution contains two forms of amino acid, namely H 2 A + and HA. There are a total of two protons that the OH - can remove to form HA and A -. The two equivalence point volumes are found from the titrations with the known NaOH solution. The volume between the two equivalence points gives the volume of NaOH required to remove one H + completely. Concentration of Unknown Amino Acid = (moles of OH - need to titrate from HA to A - ) / Volume of the unknown sample

Titration II To determine pK a1 and pK a2, locate the volume on the graphs half way between the two equivalence point volumes (shown as dark blue lines below: V eq1 =15 mL, V eq2 =30 mL) determined from the expanded derivative curves. The pH-value at this point is in the titration is equal to pK a2 (shown as dark red line, pK a =7.6 at V=22.5 mL). Next, measure an equal distance on the graph to the left of V eq1. The pH-value at this point is equal to pK a1 (dark green line, pK a =3.5 at V=7.5 mL).

Post-lab Report In the post-lab for experiment 8, the following graphs are required: Expanded derivative graph for EACH TRIAL of NaOH/amino acid titration Expanded titration graph for EACH TRIAL of NaOH/amino acid titration ONE FULL titration graph for the determination of pKa-values (see page 93). The post lab report for this project is an individual report and is due on April 12, 2016 or April 13, 2016 depending on when your section meets.