ELEMENTS OF ELECTRICAL ENGINEERING PRESENTATION ON OHM’LAW PRESENTED BY :Jahnavi tadvi(150140109041) Parita limbad(150140109058) Parmar charandasi(150140109076)

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Presentation transcript:

ELEMENTS OF ELECTRICAL ENGINEERING PRESENTATION ON OHM’LAW PRESENTED BY :Jahnavi tadvi( ) Parita limbad( ) Parmar charandasi( ) BRANCH:Electrical

Ohms law, named after Mr. Ohm, defines the relationship between power, voltage, current and resistance. These are the very basic electrical units we work with. The principles apply to a.c., d.c. or r.f. (radio frequency). Ohms Law

Why is ohms law so very important? Ohms law, sometimes more correctly called Ohm's Law, named after Mr. Georg Ohm, mathematician and physicist defines the relationship between power, voltage, current and resistance. These are the very basic electrical units we work with. The principles apply to a.c., d.c. or r.f. (radio frequency).

Ohms Law Ohms Law is the a foundation stone of electronics and electricity. These formulae are very easy to learn and are used extensively in this course Without a thorough understanding of "ohms law" you will not get very far either in design or in troubleshooting even the simplest of electronic or electrical circuits.

Ohms Law Mr. Ohm established in the late 1820's that if a voltage [later found to be either A.C., D.C. or R.F.] was applied to a resistance then "current would flow and then power would be consumed".

Ohms Law Some practical every day examples of this very basic rule are: Radiators (electric fires), Electric Frypans, Toasters, Irons and electric light bulbs The radiator consumes power producing heat for warmth, the frypan consumes power producing heat for general cooking,

Ohms Law the toaster consumes power producing heat for cooking toast, the iron consumes power producing heat for ironing our clothes and the electric light bulb consumes power producing heat and more important light for lighting up an area.

Ohms Law A further example is an electric hot water system. All are examples of ohms law at its most basic.

Hot and Cold Resistance encountered in Ohms Law One VERY important point to observe with ohms law in dealing with some of those examples is that quite often there are two types of resistance values. "Cold Resistance" as would be measured by an ohm-meter or digital multimeter and a "Hot Resistance".

Hot and Cold Resistance The latter is a phenomenem of the material used for forming the resistance itself, it has a temperature co-efficient which often once heated alters the initial resistance value, usually dramatically upward.

Hot and Cold Resistance A very good working example of this is an electric light bulb If you measure the first light bulb with a digital multimeter. It showes zero resistance, in fact open circuit.

Hot and Cold Resistance That's what you get, when for safety reasons you put a burnt out bulb back into an empty packet and a "neat and tidy" wife puts it back into the cupboard

Hot and Cold Resistance O.K. here's a "goodie" and, it's labelled "240V - 60W", it measured an initial "cold resistance" of 73.2 ohms. Then measure the actual voltage at a power point as being 243.9V A.C. at the moment [note: voltages vary widely during a day due to locations and loads - remember that fact - also for pure resistances, the principles apply equally to A.C. or D.C.].

Hot and Cold Resistance Using the formula which we will see below, the resistance for power consumed should be R = E 2 / P OR R = / 60W = 991 ohms That is 991 ohms calculated compared to an initial reading of 73.2 ohms with a digital multimeter? The reason? The "hot" resistance is always at least ten times the "cold" resistance.

Hot and Cold Resistance Another example is what is most often the biggest consumer of power in the average home. The "electric jug", "electric kettle" or what ever it is called in your part of the world. Most people are astonished by that news.

Hot and Cold Resistance My "electric kettle" is labelled as " V 2200W". Yes 2,200 watts! That is why it boils water so quickly.

What are the ohms law formulas? Notice the formulas share a common algebraic relationship with one another. For the worked examples voltage is E and we have assigned a value of 12V, Current is I and is 2 amperes while resistance is R of 6 ohms. Note that "*" means multiply by, while "/" means divide by.

ohms law formulas For voltage [E = I * R] E (volts) = I (current) * R (resistance) OR 12 volts = 2 amperes * 6 ohms For current [I = E / R] I (current) = E (volts) / R (resistance) OR 2 amperes = 12 volts / 6 ohms For resistance [R = E / I] R (resistance) = E (volts) / I (current) OR 6 ohms = 12 volts / 2 amperes

ohms law formulas Now let's calculate power using the same examples. For power P = E 2 / R OR Power = 24 watts = 12 2 volts / 6 ohms Also P = I 2 * R OR Power = 24 watts = 2 2 amperes * 6 ohms Also P = E * I OR Power = 24 watts = 12 volts * 2 amperes

ohms law formulas That's all you need for ohms law - remember just two formulas: for voltage E = I * R and; for power P = E 2 / R You can always determine the other formulas with elementary algebra.

Ohms law is the very foundation stone of electronics! Knowing two quantities in ohms law will always reveal the third value.

What is capacitance? In the topic current we learnt of the unit of measuring electrical quantity or charge was a coulomb. Now a capacitor (formerly condenser) has the ability to hold a charge of electrons. The number of electrons it can hold under a given electrical pressure (voltage) is called its capacitance or capacity.

Capacitance Two metallic plates separated by a non- conducting substance between them make a simple capacitor. Here is the symbol of a capacitor in a pretty basic circuit charged by a battery.

Capacitance

In this circuit when the switch is open the capacitor has no charge upon it, when the switch is closed current flows because of the voltage pressure, this current is determined by the amount of resistance in the circuit.

Capacitance At the instance the switch closes the emf forces electrons into the top plate of the capacitor from the negative end of the battery and pulls others out of the bottom plate toward the positive end of the battery.

Capacitance Two points need to be considered here. Firstly as the current flow progresses, more electrons flow into the capacitor and a greater opposing emf is developed there to oppose further current flow,

Capacitance the difference between battery voltage and the voltage on the capacitor becomes less and less and current continues to decrease. When the capacitor voltage equals the battery voltage no further current will flow.

Capacitance The second point is if the capacitor is able to store one coulomb of charge at one volt it is said to have a capacitance of one Farad. This is a very large unit of measure. Power supply capacitors are often in the region of 4,700 uF or 4,700 / millionths of a Farad. Radio circuits often have capacitances down to 10 pF which is 10 / million, millionths of a Farad.

Capacitance The unit uF stands for micro-farad (one millionth) and pF stands for pico-farad (one million, millionths). These are the two common values of capacitance you will encounter in electronics.

Time constant of capacitance The time required for a capacitor to reach its charge is proportional to the capacitance value and the resistance value.

Time constant of capacitance The time constant of a resistance - capacitance circuit is: T = R X C where T = time in seconds where R = resistance in ohms where C = capacitance in farads

Time constant of capacitance The time in this formula is the time to acquire 63% of the voltage value of the source. It is also the discharge time if we were discharging the capacitance. Should the capacitance in the figure above be 4U7 (4.7 uF) and the resistance was 1M ohms (one meg-ohm or 1,000,000 ohms)

Time constant of capacitance then the time constant would be T = R X C = [1,000,000 X 0.000,0047] = 4.7 seconds. These properties are taken advantage of in crude non critical timing circuits.

Capacitors in series and parallel Capacitors in parallel ADD together as C1 + C2 + C While capacitors in series REDUCE by: 1 / (1 / C1 + 1 / C2 + 1 / C ) Consider three capacitors of 10, 22, and 47 uF respectively.

Capacitors in series and parallel Added in parallel we get = 79 uF. While in series we would get: 1 / (1 / / / 47) = uF. Note that the result is always LESS than the original lowest value.

A very important property of Capacitors Capacitors will pass AC currents but not DC. Throughout electronic circuits this very important property is taken advantage of to pass ac or rf signals from one stage to another while blocking any DC component from the previous stage.

capacitors passing ac blocking dc

THANK YOU