1 Equivalence Between Two Cash Flows Step 1: Determine the base period, say, year 5. Step 2: Identify the interest rate to use. Step 3: Calculate equivalence.

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Presentation transcript:

1 Equivalence Between Two Cash Flows Step 1: Determine the base period, say, year 5. Step 2: Identify the interest rate to use. Step 3: Calculate equivalence value. $3,000$2,042 50

2 Example - Equivalence Various dollar amounts that will be economically equivalent to $3,000 in 5 years, given an interest rate of 8% P F $2,042 $3,000 $2,205 $2,382 $2,778$2,572

3 Example $100 $80 $120 $150 $200 $ V = Compute the equivalent lump-sum amount at n = 3 at 10% annual interest.

$100 $80 $120 $150 $200 $100 V Approach

$100 $80 $120 $150 $200 $100 V

6 Practice Problem How many years would it take an investment to double at 10% annual interest? P 2P2P 0 N = ?

7 Solution P 2P2P 0 N = ?

8 Rule of 72 Approximating how long it will take for a sum of money to double

9 Given: i = 10%, Find: C that makes the two cash flow streams to be indifferent Practice Problem $500 $1, A B CC

10 Step 1: Select the base period to use, say n = 2. Step 2: Find the equivalent lump sum value at n = 2 for both A and B. Step 3: Equate both equivalent values and solve for unknown C. Approach $500 $1, A B CC

11 Solution For A: For B: To Find C: $500 $1, A B CC

12 At what interest rate would you be indifferent between the two cash flows? $500 $1, $502 $502 $502 A B Practice Problem

13 Approach Step 1: Select the base period to compute the equivalent value (say, n = 3) Step 2: Find the net worth of each at n = 3. $500 $1, $502 $502 $502 A B

14 Establish Equivalence at n = 3 Find the solution by trial and error, say i = 8%

Interest Formulas for Single Cash Flows

16 Single Cash Flow Formula Single payment compound amount factor (growth factor) Given: Find: F P F N 0 (Appendix B)

17 Practice Problem If you had $2,000 now and invested it at 10%, how much would it be worth in 8 years? $2,000 F = ? 8 0 i = 10%

18 Solution

19 Single Cash Flow Formula Single payment present worth factor (discount factor) Given: Find: P F N 0

20 Practice Problem You want to set aside a lump sum amount today in a savings account that earns 7% annual interest to meet a future expense in the amount of $10,000 to be incurred in 6 years. How much do you need to deposit today?

21 Solution 0 6 $10,000 P

22 Multiple Payments How much do you need to deposit today (P) to withdraw $25,000 at n =1, $3,000 at n = 2, and $5,000 at n =4, if your account earns 10% annual interest? $25,000 $3,000 $5,000 P

$25,000 $3,000 $5,000 P $25,000 P1P $3,000 P2P $5,000 P3P3 ++ Uneven Payment Series

24 Check Beginning Balance 028,6226, , , Interest Earned (10%) 02, Payment+28,622-25,000-3,0000-5,000 Ending Balance $28,6226, , , Rounding error It should be “0.”

Interest Formulas – Equal Payment Series

26 Equal Payment Series 012 N 0 12 N AAA F P 0 N

27 Equal Payment Series – Compound Amount Factor 012 N 0 12 N AAA F 012 N AAA F

28 Compound Amount Factor 012 N 0 12N AAA F A(1+i) N-1 A(1+i) N-2

29 Equal Payment Series Compound Amount Factor (Future Value of an Annuity) Example: Given: A = $5,000, N = 5 years, and i = 6% Find: F Solution: F = $5,000(F/A,6%,5) = $28, N F A

30 Validation

31 Finding an Annuity Value Example: Given: F = $5,000, N = 5 years, and i = 7% Find: A Solution: A = $5,000(A/F,7%,5) = $ N F A = ?

32 Example 2.10 Handling Time Shifts in a Uniform Series F = ? $5,000 $5,000 $5,000 $5,000 $5,000 i = 6% First deposit occurs at n = 0

33 F = ? $5,000 $5,000 $5,000 $5,000 $5,000 i = 6% F = 28, F= F (1+i)=28,  1.06=$29,876.59

34 F = ? $5,000 $5,000 $5,000 $5,000 $5,000 i = 6% F = 28, Add $5,000 at time 0 and subtract $5,000 at time 5. F= 28, ,000(1.06) 5 -5,000=$29,876.59

35 Example College savings plan for 10-years-old daughter. She will start college at age 18 and will need $100,000. How much should be saved at the end of each year if i=7%?

36 Solution Given: F = $100,000 i = 7% N = 8 years A = $100,000(A/F,7%,8) = $9, Sinking Fund Factor In Excel: =PMT(i,N,pv,fv,type) =PMT(7%,8,0,100000,0) =$9,746.78

37 Capital Recovery Factor Example 2.12: Paying Off Education Loan Given: P = $21,061.82, N = 5 years, and i = 6% Find: A Solution: A = $21,061.82(A/P,6%,5) = $5, N P A = ? 0

38 P =$21, A A A A A i = 6% A’ A’ A’ A’ A’ i = 6% P’ = $21,061.82(F/P, 6%, 1) Grace period Example 2.14 Deferred Loan Repayment Plan

39 Two-Step Procedure