Solving Two-Step and Multi-Step Equations Warm Up Lesson Presentation

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Presentation transcript:

Solving Two-Step and Multi-Step Equations Warm Up Lesson Presentation Lesson Quiz Holt McDougal Algebra 1 Holt Algebra 1

Objective Solve equations in one variable that contain more than one operation.

Example 1A: Solving Two-Step Equations Solve 18 = 4a + 10. 18 = 4a + 10 First a is multiplied by 4. Then 10 is added. Work backward: Subtract 10 from both sides. –10 – 10 8 = 4a Since a is multiplied by 4, divide both sides by 4 to undo the multiplication. 8 = 4a 4 2 = a

Example 1B: Solving Two-Step Equations Solve 5t – 2 = –32. 5t – 2 = –32 First t is multiplied by 5. Then 2 is subtracted. Work backward: Add 2 to both sides. + 2 + 2 5t = –30 Since t is multiplied by 5, divide both sides by 5 to undo the multiplication. 5t = –30 5 t = –6

Check it Out! Example 1a Solve –4 + 7x = 3. –4 + 7x = 3 First x is multiplied by 7. Then –4 is added. Work backward: Add 4 to both sides. + 4 + 4 7x = 7 Since x is multiplied by 7, divide both sides by 7 to undo the multiplication. 7x = 7 7 x = 1

Check it Out! Example 1b Solve 1.5 = 1.2y – 5.7. 1.5 = 1.2y – 5.7 First y is multiplied by 1.2. Then 5.7 is subtracted. Work backward: Add 5.7 to both sides. + 5.7 + 5.7 7.2 = 1.2y Since y is multiplied by 1.2, divide both sides by 1.2 to undo the multiplication. 7.2 = 1.2y 1.2 6 = y

Check it Out! Example 1c Solve . First n is divided by 7. Then 2 is added. Work backward: Subtract 2 from both sides. –2 –2 Since n is divided by 7, multiply both sides by 7 to undo the division. n = 0

Example 2A: Solving Two-Step Equations That Contain Fractions Solve . Method 1 Use fraction operations. Since is subtracted from , add to both sides to undo the subtraction. 3 4 y 8 Since y is divided by 8, multiply both sides by 8 to undo the division.

Example 2A Continued Solve . Method 1 Use fraction operations. Simplify.

Example 2B: Solving Two-Step Equations That Contain Fractions Solve . Method 1 Use fraction operations. Since is added to r, subtract from both sides to undo the addition. 3 4 2 The reciprocal of is . Since r is multiplied by , multiply both sides by . 3 2

Example 2B Continued Solve . Method 1 Use fraction operations.

Example 2B Continued Solve . Method 2 Multiply by the LCD to clear the fractions. Multiply both sides by 12, the LCD of the fractions. Distribute 12 on the left side. 8r + 9 = 7 Simplify. Since 9 is added to 8r, subtract 9 from both sides to undo the addition. –9 –9 8r = –2

Example 2B Continued Solve . Method 2 Multiply by the LCD to clear the fractions. 8r = –2 Since r is multiplied by 8, divide both sides by 8 to undo the multiplication. 8 8

Method 2 Multiply by the LCD to clear the fractions. Check It Out! Example 2a Solve . Method 2 Multiply by the LCD to clear the fractions. Multiply both sides by 10, the LCD of the fractions. Distribute 10 on the left side. 4x – 5 = 50 Simplify. + 5 + 5 Since 5 is subtracted from 4x, add 5 to both sides to undo the subtraction. 4x = 55

Check It Out! Example 2a Solve . Method 2 Multiply by the LCD to clear the fractions. 4x = 55 Simplify. Since 4 is multiplied by x, divide both sides by 4 to undo the multiplication. 4 4

Method 2 Multiply by the LCD to clear the fractions. Check It Out! Example 2b Solve . Method 2 Multiply by the LCD to clear the fractions. Multiply both sides by 8, the LCD of the fractions. Distribute 8 on the left side. 6u + 4 = 7 Simplify.  4  4 Since 4 is added to 6u, subtract 4 from both sides to undo the addition. 6u = 3

Check It Out! Example 2b Continued Solve . Method 2 Multiply by the LCD to clear the fractions. Since u is multiplied by 6, divide both sides by 6 to undo the multiplication. 6u = 3 6 6

Method 1 Use fraction operations. Check It Out! Example 2c Solve . Method 1 Use fraction operations. Since is subtracted from , add to both sides to undo the subtraction. 1 3 n 5 Simplify.

Check It Out! Example 2c Continued Solve . Method 1 Use fraction operations. Since n is divided by 5, multiply both sides by 5 to undo the division. n = 15

Equations that are more complicated may have to be simplified before they can be solved. You may have to use the Distributive Property or combine like terms before you begin using inverse operations.

Example 3A: Simplifying Before Solving Equations Solve 8x – 21 + 5x = –15. 8x – 21 – 5x = –15 8x – 5x – 21 = –15 Use the Commutative Property of Addition. 3x – 21 = –15 Combine like terms. + 21 +21 Since 21 is subtracted from 3x, add 21 to both sides to undo the subtraction. 3x = 6 Since x is multiplied by 3, divide both sides by 3 to undo the multiplication. x = 2

Check It Out! Example 3a Solve 2a + 3 – 8a = 8. 2a + 3 – 8a = 8 2a – 8a + 3 = 8 Use the Commutative Property of Addition. –6a + 3 = 8 Combine like terms. – 3 – 3 Since 3 is added to –6a, subtract 3 from both sides to undo the addition. –6a = 5 Since a is multiplied by –6, divide both sides by –6 to undo the multiplication.