Entry Task  Find the value of x in each figure  1. 2. 10 x 4 x 6 14.

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Presentation transcript:

Entry Task  Find the value of x in each figure  x 4 x 6 14

Proportions in Triangles Lesson 7-5

Investigation 1 Parallels and Proportionality  For this investigation you will need a ruler and a protractor.  Step 1: In the figure below, find the value of x x A D B E C 8 12 D E C 8 16 x A D B 24 x + 12 A D B

Now let’s see if the converse is true?  Complete steps 3-9 of Investigation 1. When you are finished, use your observations to write a conjecture about the ratios of the lengths of the segments that are cut off by parallel lines.  Our book calls this theorem the Side-Splitter Theorem.  If a line is parallel to one side of a triangle and intersects the other two sides, then it divides those sides proportionally.  The converse of this theorem is also true:  If a line divides two sides of a triangle proportionally, then it is parallel to the third side.

Corollary to the Side-Splitter Theorem  This extends the theorem to multiple parallel lines.  If three parallel lines intersect on two transversals, then the segments intercepted on the transversal are proportional. 

Investigation 2  Complete this investigation and compare your results with others near you.  Use your observations to write a conjecture.

Triangle-Angle-Bisector Theorem  The angle bisector of a triangle divides the opposite side into two segments that are proportional to the other two sides of the triangle.

Lesson Check  Find the value of x in each figure Find the value of x and y in the figure.

 One more investigation… Investigating corresponding parts of triangles.  In this investigation, you will look at the relationship between corresponding altitudes, corresponding medians, and corresponding angle bisectors of similar triangles.  Proportional Parts Conjecture:  If two triangles are similar, then the corresponding altitudes, medians, and angle bisectors are proportional to the corresponding sides.

Homework Page 475 (10-22 evens, all, evens)