Chapter 19 Gas Stoichiometry. The next two slides contain GFM problems involving PV=nRT. The first is the last problem from yesterdays lecture if we did.

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Presentation transcript:

Chapter 19 Gas Stoichiometry

The next two slides contain GFM problems involving PV=nRT. The first is the last problem from yesterdays lecture if we did not get to it. The next problem is an extra problem if we finished yesterdays lecture.

1.00g of a gas occupies dm 3 at 760 torr and 3.0°C. The gas is most likely: (a) BH 3 (b) B 2 H 6 (c) (d) B 3 H 12

A chemist collects 23.6g of an unknown gas from the air. It occupies a volume of 12.0 L at standard temperature and pressure. What common gas do you think the chemist has collected?

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr 119g KBr mol KBr

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr 119g KBr mol KBr 2 mol KBr 1 mol Br 2

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr 119g KBr mol KBr 2 mol KBr 1 mol Br dm 3

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr 119g KBr mol KBr 2 mol KBr 1 mol Br dm 3 1 dm cm 3

If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP? 2KBr + Cl 2 → Br 2 + 2KCl 20.0g KBr 119g KBr mol KBr 2 mol KBr 1 mol Br dm 3 1 dm cm 3 = 1880 cm 3

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O 3

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O dm 3 O 2

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O dm 3 O dm 3 mol O 2

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O dm 3 O dm 3 mol O 2 3 mol O 2 4 mol Al

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O dm 3 O dm 3 mol O 2 3 mol O 2 4 mol Al mol Al 27.0 g

In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with 5.00 dm 3 of oxygen at STP? 4Al + 3O 2 → 2Al 2 O dm 3 O dm 3 mol O 2 3 mol O 2 4 mol Al mol Al 27.0 g = 8.04 g

How many cm 3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm 3 of hydrogen chloride gas at STP? H 2 + Cl 2 → 2HCl

How many cm 3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm 3 of hydrogen chloride gas at STP? H 2 + Cl 2 → 2HCl

How many cm 3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm 3 of hydrogen chloride gas at STP? H 2 + Cl 2 → 2HCl This is a volume – volume calculation. We can use a shortcut for these type of calculations cm 3 HCl

How many cm 3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm 3 of hydrogen chloride gas at STP? H 2 + Cl 2 → 2HCl This is a volume – volume calculation. We can use a shortcut for these type of calculations cm 3 HCl 2 cm 3 HCl 1 cm 3 Cl 2 = 25.0 cm 3

Homework (Period 1) Worksheet: Ideal Gas Equation (due in two days). Worksheet: Gas Stoichiometry (due in two days). Lab Summary: “Molecular Mass of a Gas” (due in two days). Study Guide Chapter 19 (due in two days).

Homework (Period 6) Worksheet: Ideal Gas Equation (due tomorrow). Lab Summary: “Molecular Mass of a Gas” (due tomorrow). Study Guide Chapter 19 (due tomorrow). Worksheet: Gas Stoichiometry (due in two days).