SOLUTION EXAMPLE 1 Represent relations Consider the relation given by the ordered pair (–2, –3), (–1, 1), (1, 3), (2, –2), and (3, 1). a. Identify the.

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SOLUTION EXAMPLE 1 Represent relations Consider the relation given by the ordered pair (–2, –3), (–1, 1), (1, 3), (2, –2), and (3, 1). a. Identify the domain and range. The domain consists of all the x- coordinates : –2, –1, 1, 2, and 3. The range consists of all the y- coordinates : –3, –2, 1, and 3.

SOLUTION EXAMPLE 1 Represent relations Represent the relation using a graph and a mapping diagram. b. b. GraphMapping Diagram

EXAMPLE 2 Tell whether the relation is a function. Explain. Identify functions a.a. SOLUTION The relation is a function because each input is mapped onto exactly one output.

EXAMPLE 2 Tell whether the relation is a function. Explain. Identify functions b.b. The relation is not a function because the input 1 is mapped onto both – 1 and 2. SOLUTION

GUIDED PRACTICE for Examples 1 and 2 1. Consider the relation given by the ordered pairs (–4, 3), (–2, 1), (0, 3), (1, –2), and (–2, –4) a. Identify the domain and range. The domain consists of all the x -coordinates : –4, –2, 0 and 1, The range consists of all the y- coordinates: 3, 1, –2 and –4

SOLUTION GUIDED PRACTICE for Examples 1 and 2 b. Represent the relation using a table and a mapping diagram.

GUIDED PRACTICE for Examples 1 and 2 2. Tell whether the relation is a function. Explain. ANSWERYes; each input has exactly one output.

EXAMPLE 3 Use the vertical line test Basketball The first graph below plots average points per game versus age at the end of the 2003–2004 NBA regular season for the 8 members of the Minnesota Timber wolves with the highest averages. The second graph plots average points per game versus age for one team member, Kevin Garnett, over his first 9 seasons. Are the relations shown by the graphs functions ? Explain.

SOLUTION EXAMPLE 3 Use the vertical line test The team graph does not represent a function because vertical lines at x = 28 and x = 29 each intersect the graph at more than one point. The graph for Kevin Garnett does represent a function because no vertical line intersects the graph at more than one point.

EXAMPLE 3 GUIDED PRACTICE for Example 3 3. WHAT IF? In Example 3, suppose that Kevin Garnett averages 24.2 points per game in his tenth season as he did in his ninth. If the relation given by the second graph is revised to include the tenth season, is the relation still a function? Explain. ANSWERYes; each input has exactly one output.

SOLUTION EXAMPLE 4 Graph an equation in two variables Graph the equation y = – 2x – 1. STEP 1 Construct a table of values. x–2–1 012 y31 –3–5

EXAMPLE 4 STEP 2 Plot the points. Notice that they all lie on a line. STEP 3 Connect the points with a line. Graph an equation in two variables

SOLUTION EXAMPLE 5 Classify and evaluate functions Tell whether the function is linear. Then evaluate the function when x = – 4. a. f (x) = –x 2 – 2x + 7 The function f is not linear because it has an x 2 -term. f (x) = –x 2 – 2x + 7 Write function. f (–4) = –(– 4) 2 – 2(–4) + 7 Substitute –4 for x. = –1= –1 Simplify.

SOLUTION EXAMPLE 5 Classify and evaluate functions b. g(x) = 5x + 8 The function g is linear because it has the form g(x) = mx + b. g(x) = 5x + 8 Write function. g(–4) = 5(–4) + 8 Substitute – 4 for x. = –12 Simplify.

GUIDED PRACTICE for Examples 4 and 5 4. Graph the equation y = 3x – 2. ANSWER

GUIDED PRACTICE for Examples 4 and 5 Tell whether the function is linear. Then evaluate the function when x = –2. 5. f (x) = x – 1 – x 3 6. g (x) = –4 – 2x ANSWER Not Linear; The f(x) = 5, when x = –2 Linear; The f(x) = 0, when x = –2

Diving EXAMPLE 6 Use a function in real life A diver using a Diver Propulsion Vehicle ( DPV ) descends to a depth of 130 feet.The pressure P ( in atmospheres ) on the diver is given by P(d) = d where d is the depth ( in feet ). Graph the function, and determine a reasonable domain and range. What is the pressure on the diver at a depth of 33 feet?

SOLUTION EXAMPLE 6 Use the vertical line test The graph of P(d) is shown. Because the depth varies from 0 feet to 130 feet, a reasonable domain is 0 ≤ d ≤ 130. The minimum value of P(d) is P(0) = 1, and the maximum value of P(d) is P(130) = 4.9. So, a reasonable range is 1 ≤ P(d) ≤ 4.9.

ANSWER At a depth of 33 feet, the pressure on the diver is P(33) = (33) 2 atmospheres, which you can verify from the graph. EXAMPLE 6 Use the vertical line test

GUIDED PRACTICE for Example 6 7. In 1960, the deep-sea vessel Trieste descended to an estimated depth of 35,800 feet. Determine a reasonable domain and range of the function P(d) in Example 6 for this trip. SOLUTION Because the depth varies from 0 feet to 35,800 feet, a reasonable domain is 0 ≤ d ≤ 35,800. The minimum value of P(d) is P(0) = 1, and the maximum value of P(d) is P(35,800) = So, a reasonable range is 1 ≤ P(d) ≤ 1075.