Computer Networks Group Universität Paderborn Ad hoc and Sensor Networks Chapter 6: Link layer protocols Holger Karl.

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Presentation transcript:

Computer Networks Group Universität Paderborn Ad hoc and Sensor Networks Chapter 6: Link layer protocols Holger Karl

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols2 Goals of this chapter – Link layer tasks in general  Framing – group bit sequence into packets/frames  Important: format, size  Error control – make sure that the sent bits arrive and no other  Forward and backward error control  Flow control – ensure that a fast sender does not overrun its slow(er) receiver  Link management – discovery and manage links to neighbors  Do not use a neighbor at any cost, only if link is good enough ! Understand the issues involved in turning the radio communication between two neighboring nodes into a somewhat reliable link

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols3 Overview  Error control  Framing  Link management

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols4 Error control  Error control has to ensure that data transport is  Error-free – deliver exactly the sent bits/packets  In-sequence – deliver them in the original order  Duplicate-free – and at most once  Loss-free – and at least once  Causes: fading, interference, loss of bit synchronization, …  Results in bit errors, bursty, sometimes heavy-tailed runs (see physical layer chapter)  In wireless, sometimes quite high average bit error rates – … possible!  Approaches  Backward error control – ARQ  Forward error control – FEC

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols5 Backward error control – ARQ  Basic procedure (a quick recap)  Put header information around the payload  Compute a checksum and add it to the packet  Typically: Cyclic redundancy check (CRC), quick, low overhead, low residual error rate  Provide feedback from receiver to sender  Send positive or negative acknowledgement  Sender uses timer to detect that acknowledgements have not arrived  Assumes packet has not arrived  Optimal timer setting?  If sender infers that a packet has not been received correctly, sender can retransmit it  What is maximum number of retransmission attempts? If bounded, at best a semi-reliable protocols results

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols6 Standard ARQ protocols  Alternating bit – at most one packet outstanding, single bit sequence number  Go-back N – send up to N packets, if a packet has not been acknowledged when timer goes off, retransmit all unacknowledged packets  Selective Repeat – when timer goes off, only send that particular packet

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols7 How to use acknowledgements  Be careful about ACKs from different layers  A MAC ACK (e.g., S-MAC) does not necessarily imply buffer space in the link layer  On the other hand, having both MAC and link layer ACKs is a waste  Do not (necessarily) acknowledge every packet – use cumulative ACKs  Tradeoff against buffer space  Tradeoff against number of negative ACKs to send

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols8 When to retransmit  Assuming sender has decided to retransmit a packet – when to do so?  In a BSC channel, any time is as good as any  In fading channels, try to avoid bad channel states – postpone transmissions  Instead (e.g.): send a packet to another node if in queue (exploit multi-user diversity)  How long to wait?  Example solution: Probing protocol  Idea: reflect channel state by two protocol modes, “normal” and “probing”  When error occurs, go from normal to probing mode  In probing mode, periodically send short packets (acknowledged by receiver) – when successful, go to normal mode

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols9 Forward error control  Idea: Endow symbols in a packet with additional redundancy to withstand a limited amount of random permutations  Additionally: interleaving – change order of symbols to withstand burst errors

10.10 Data can be corrupted during transmission. Some applications require that errors be detected and corrected. Note

10.11 In a single-bit error, only 1 bit in the data unit has changed. Note

10.12 Figure 10.1 Single-bit error

10.13 A burst error means that 2 or more bits in the data unit have changed. Note

10.14 Figure 10.2 Burst error of length 8

10.15 To detect or correct errors, we need to send extra (redundant) bits with data. Note

10.16 Figure 10.3 The structure of encoder and decoder

10.17 In this book, we concentrate on block codes; we leave convolution codes to advanced texts. Note

10.18 In modulo-N arithmetic, we use only the integers in the range 0 to N −1, inclusive. Note

10.19 Figure 10.4 XORing of two single bits or two words

BLOCK CODING In block coding, we divide our message into blocks, each of k bits, called datawords. We add r redundant bits to each block to make the length n = k + r. The resulting n-bit blocks are called codewords. Error Detection Error Correction Hamming Distance Minimum Hamming Distance Topics discussed in this section:

10.21 Figure 10.5 Datawords and codewords in block coding ( n = k+r), r: extra bits

10.22 Figure 10.6 Process of error detection in block coding

10.23 Let us assume that k = 2 and n = 3. Table 10.1 shows the list of datawords and codewords. Later, we will see how to derive a codeword from a dataword. Assume the sender encodes the dataword 01 as 011 and sends it to the receiver. Consider the following cases: 1. The receiver receives 011. It is a valid codeword. The receiver extracts the dataword 01 from it. Example 10.2

The codeword is corrupted during transmission, and 111 is received. This is not a valid codeword and is discarded. 3. The codeword is corrupted during transmission, and 000 is received. This is a valid codeword. The receiver incorrectly extracts the dataword 00. Two corrupted bits have made the error undetectable. Example 10.2 (continued)

10.25 Table 10.1 A code for error detection (Example 10.2)

10.26 An error-detecting code can detect only the types of errors for which it is designed; other types of errors may remain undetected. Note

10.27 Figure 10.7 Structure of encoder and decoder in error correction

10.28 Let us add more redundant bits to Example 10.2 to see if the receiver can correct an error without knowing what was actually sent. We add 3 redundant bits to the 2-bit dataword to make 5-bit codewords. Table 10.2 shows the datawords and codewords. Assume the dataword is 01. The sender creates the codeword The codeword is corrupted during transmission, and is received. First, the receiver finds that the received codeword is not in the table. This means an error has occurred. The receiver, assuming that there is only 1 bit corrupted, uses the following strategy to guess the correct dataword. Example 10.3

Comparing the received codeword with the first codeword in the table (01001 versus 00000), the receiver decides that the first codeword is not the one that was sent because there are two different bits. 2. By the same reasoning, the original codeword cannot be the third or fourth one in the table. 3. The original codeword must be the second one in the table because this is the only one that differs from the received codeword by 1 bit. The receiver replaces with and consults the table to find the dataword 01. Example 10.3 (continued)

10.30 Table 10.2 A code for error correction (Example 10.3)

10.31 The Hamming distance between two words is the number of differences between corresponding bits. Note

10.32 Let us find the Hamming distance between two pairs of words (number of differences betrween 2 words) 1. The Hamming distance d(000, 011) is 2 because Example The Hamming distance d(10101, 11110) is 3 because

10.33 The minimum Hamming distance is the smallest Hamming distance between all possible pairs in a set of words. Note

10.34 Find the minimum Hamming distance of the coding scheme in Table Solution We first find all Hamming distances. Example 10.5 The d min in this case is 2.

10.35 Find the minimum Hamming distance of the coding scheme in Table Solution We first find all the Hamming distances. The d min in this case is 3. Example 10.6

10.36 To guarantee the detection of up to s errors in all cases, the minimum Hamming distance in a block code must be d min = s + 1. Note

10.37 The minimum Hamming distance for our first code scheme (Table 10.1) is 2. This code guarantees detection of only a single error. For example, if the third codeword (101) is sent and one error occurs, the received codeword does not match any valid codeword. If two errors occur, however, the received codeword may match a valid codeword and the errors are not detected. Example 10.7

10.38 Our second block code scheme (Table 10.2) has d min = 3. This code can detect up to two errors. Again, we see that when any of the valid codewords is sent, two errors create a codeword which is not in the table of valid codewords. The receiver cannot be fooled. However, some combinations of three errors change a valid codeword to another valid codeword. The receiver accepts the received codeword and the errors are undetected. Example 10.8

10.39 Figure 10.8 Geometric concept for finding d min in error detection

10.40 Figure 10.9 Geometric concept for finding d min in error correction

10.41 To guarantee correction of up to t errors in all cases, the minimum Hamming distance in a block code must be d min = 2t + 1. Note

10.42 A code scheme has a Hamming distance d min = 4. What is the error detection and correction capability of this scheme? Solution This code guarantees the detection of up to three errors (s = 3), but it can correct up to one error. In other words, if this code is used for error correction, part of its capability is wasted. Error correction codes need to have an odd minimum distance (3, 5, 7,... ). Example 10.9

LINEAR BLOCK CODES Almost all block codes used today belong to a subset called linear block codes. A linear block code is a code in which the exclusive OR (addition modulo-2) of two valid codewords creates another valid codeword. Minimum Distance for Linear Block Codes Some Linear Block Codes Topics discussed in this section:

10.44 In a linear block code, the exclusive OR (XOR) of any two valid codewords creates another valid codeword. Note

10.45 Let us see if the two codes we defined in Table 10.1 and Table 10.2 belong to the class of linear block codes. 1. The scheme in Table 10.1 is a linear block code because the result of XORing any codeword with any other codeword is a valid codeword. For example, the XORing of the second and third codewords creates the fourth one. 2. The scheme in Table 10.2 is also a linear block code. We can create all four codewords by XORing two other codewords. Example 10.10

10.46 In our first code (Table 10.1), the numbers of 1s in the nonzero codewords are 2, 2, and 2. So the minimum Hamming distance is d min = 2. In our second code (Table 10.2), the numbers of 1s in the nonzero codewords are 3, 3, and 4. So in this code we have d min = 3. Example 10.11

10.47 A simple parity-check code is a single-bit error-detecting code in which n = k + 1 with d min = 2. The extra-bit: parity bits is selected to make the total number of 1s in the codeword even ( even parity) or odd (for odd parity)

10.48 Table 10.3 Simple parity-check code C(5, 4)

10.49 Figure Encoder and decoder for simple parity-check code

10.50 A simple parity-check code can detect an odd number of errors. Note

10.51 All Hamming codes discussed in this book have d min = 3. The relationship between m and n in these codes is n = 2m − 1. Note

10.52 Figure Two-dimensional parity-check code

10.53 Figure Two-dimensional parity-check code

10.54 Figure Two-dimensional parity-check code

10.55 Table 10.4 Hamming code C(7, 4)

10.56 Figure The structure of the encoder and decoder for a Hamming code

CYCLIC CODES Cyclic codes are special linear block codes with one extra property. In a cyclic code, if a codeword is cyclically shifted (rotated), the result is another codeword. Cyclic Redundancy Check Hardware Implementation Polynomials Cyclic Code Analysis Advantages of Cyclic Codes Other Cyclic Codes Topics discussed in this section:

10.58 Table 10.6 A CRC code with C(7, 4)

10.59 Figure CRC encoder and decoder

10.60 Figure Division in CRC encoder The division is done to have the most left bit 0, and is done from left to right like a regular division. The division is done until the quotient has as many bits as the dividend. The new codeword is the dataword extended by the remainder. The divisor (generator) is agreed upon.

10.61 To recover the dataword, we divide the same way. In the following slide, we show an example where the codeword was changed (1 bit error) from to We see that there will be a remainder (syndrome)

10.62 Figure Division in the CRC decoder for two cases

10.63 The divisor in a cyclic code is normally called the generator polynomial or simply the generator. Note

10.64 Advantages: Very good performance in detecting single-bit errors, double errors, an odd number of errors and burst errors. Easy to implement

CHECKSUM The last error detection method we discuss here is called the checksum. The checksum is used in the Internet by several protocols although not at the data link layer. However, we briefly discuss it here. The idea is to simply send an additional data ( for example the sum) along with the data. At the destination, the sum is calculated and compared to the one sent. One’s Complement Internet Checksum Topics discussed in this section:

10.66 Suppose our data is a list of five 4-bit numbers that we want to send to a destination. In addition to sending these numbers, we send the sum of the numbers. For example, if the set of numbers is (7, 11, 12, 0, 6), we send (7, 11, 12, 0, 6, 36), where 36 is the sum of the original numbers. The receiver adds the five numbers and compares the result with the sum. If the two are the same, the receiver assumes no error, accepts the five numbers, and discards the sum. Otherwise, there is an error somewhere and the data are not accepted. Example 10.18

10.67 We can make the job of the receiver easier if we send the negative (complement) of the sum, called the checksum. In this case, we send (7, 11, 12, 0, 6, −36). The receiver can add all the numbers received (including the checksum). If the result is 0, it assumes no error; otherwise, there is an error. Example 10.19

10.68 How can we represent the number 21 in one ’ s complement arithmetic using only four bits? Solution The number 21 in binary is (it needs five bits). We can wrap the leftmost bit and add it to the four rightmost bits. We have ( ) = 0110 or 6. Example 10.20

10.69 How can we represent the number −6 in one ’ s complement arithmetic using only four bits? Solution In one ’ s complement arithmetic, the negative or complement of a number is found by inverting all bits. Positive 6 is 0110; negative 6 is If we consider only unsigned numbers, this is 9. In other words, the complement of 6 is 9. Another way to find the complement of a number in one ’ s complement arithmetic is to subtract the number from 2 n − 1 (16 − 1 in this case). Example 10.21

10.70 Let us redo Exercise using one ’ s complement arithmetic. Figure shows the process at the sender and at the receiver. The sender initializes the checksum to 0 and adds all data items and the checksum (the checksum is considered as one data item and is shown in color). The result is 36. However, 36 cannot be expressed in 4 bits. The extra two bits are wrapped and added with the sum to create the wrapped sum value 6. In the figure, we have shown the details in binary. The sum is then complemented, resulting in the checksum value 9 (15 − 6 = 9). The sender now sends six data items to the receiver including the checksum 9. Example 10.22

10.71 The receiver follows the same procedure as the sender. It adds all data items (including the checksum); the result is 45. The sum is wrapped and becomes 15. The wrapped sum is complemented and becomes 0. Since the value of the checksum is 0, this means that the data is not corrupted. The receiver drops the checksum and keeps the other data items. If the checksum is not zero, the entire packet is dropped. Example (continued)

10.72 Figure Example 10.22

10.73 Internet Checksum  Using a 16-bit checksum calculated the following way

10.74 Sender site: 1. The message is divided into 16-bit words. 2. The value of the checksum word is set to All words including the checksum are added using one’s complement addition. 4. The sum is complemented and becomes the checksum. 5. The checksum is sent with the data. Note

10.75 Receiver site: 1. The message (including checksum) is divided into 16-bit words. 2. All words are added using one’s complement addition. 3. The sum is complemented and becomes the new checksum. 4. If the value of checksum is 0, the message is accepted; otherwise, it is rejected. Note

10.76 Let us calculate the checksum for a text of 8 characters ( “ Forouzan ” ). The text needs to be divided into 2-byte (16- bit) words. We use ASCII (see Appendix A) to change each byte to a 2-digit hexadecimal number. For example, F is represented as 0x46 and o is represented as 0x6F. Figure shows how the checksum is calculated at the sender and receiver sites. In part a of the figure, the value of partial sum for the first column is 0x36. We keep the rightmost digit (6) and insert the leftmost digit (3) as the carry in the second column. The process is repeated for each column. Note that if there is any corruption, the checksum recalculated by the receiver is not all 0s. We leave this an exercise. Example 10.23

10.77 Figure Example 10.23

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols78 Block-coded FEC  Level of redundancy: blocks of symbols  Block: k p-ary source symbols (not necessarily just bits)  Encoded into n q-ary channel symbols  Injective mapping (code) of p k source symbols ! q n channel symbols  Code rate: (k ld p) / (n ld q)  When p=q=2: k/n is code rate  For p=q=2: Hamming bound – code can correct up to t bit errors only if  Codes for (n,k,t) do not always exist

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols79 Popular block codes  Popular examples  Reed-Solomon codes (RS)  Bose-Chaudhuri-Hocquenghem codes (BCH)  Energy consumption  E.g., BCH encoding: negligible overhead (linear-feedback shift register)  BCH decoding: depends on block length and Hamming distance (n, t as on last slide)  Similar for RS codes

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols80 Convolutional codes  Code rate: ratio of k user bits mapped onto n coded bits  Constraint length K determines coding gain  Energy  Encoding: cheap  Decoding: Viterbi algorithm, energy & memory depends exponentially (!) on constraint length

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols81 Energy consumption of convolutional codes  Tradeoff between coding energy and reduced transmission power (coding gain)  Overall: block codes tend to be more energy- efficient RESIDUAL bit error prob.!

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols82 Comparison: FEC vs. ARQ  FEC  Constant overhead for each packet  Not (easily) possible to adapt to changing channel characteristics  ARQ  Overhead only when errors occurred (expect for ACK, always needed)  Both schemes have their uses ! hybrid schemes BCH + unlimited number of retransmissions Relative energy consumption t: error correction capacity

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols83 Power control on a link level  Further controllable parameter: transmission power  Higher power, lower error rates – less FEC/ARQ necessary  Lower power, higher error rates – higher FEC necessary  Tradeoff!

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols84 Overview  Error control  Framing  Link management

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols85 Frame, packet size  Small packets: low packet error rate, high packetization overhead  Large packets: high packet error rate, low overhead  Depends on bit error rate, energy consumption per transmitted bit  Notation: h(overhead, payload size, BER)

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols86 Dynamically adapt frame length  For known bit error rate (BER), optimal frame length is easy to determine  Problem: how to estimate BER?  Collect channel state information at the receiver (RSSI, FEC decoder information, …)  Example: Use number of attempts T required to transmit the last M packets as an estimator of the packet error rate (assuming a BSC)  Details: homework assignment  Second problem: how long are observations valid/how should they be aged?  Only recent past is – if anything at all – somewhat credible

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols87 Putting it together: ARQ, FEC, frame length optimization  Applying ARQ, FEC (both block and convolutional codes), frame length optimization to a Rayleigh fading channel  Channel modeled as Gilbert-Elliot

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols88 Overview  Error control  Framing  Link management

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols89 Link management  Goal: decide to which neighbors that are more or less reachable a link should be established  Problem: communication quality fluctuates, far away neighbors can be costly to talk to, error-prone, quality can only be estimated  Establish a neighborhood table for each node  Partially automatically constructed by MAC protocols

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols90 Link quality characteristics  Expected: simple, circular shape of “region of communication” – not realistic  Instead:  Correlation between distance and loss rate is weak; iso-loss-lines are not circular but irregular  Asymmetric links are relatively frequent (up to 15%)  Significant short-term PER variations even for stationary nodes

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols91 Three regions of communication  Effective region: PER consistently < 10%  Transitional region: anything in between, with large variation for nodes at same distance  Poor region: PER well beyond 90%

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols92 Link quality estimation  How to estimate, on-line, in the field, the actual link quality?  Requirements  Precision – estimator should give the statistically correct result  Agility – estimator should react quickly to changes  Stability – estimator should not be influenced by short aberrations  Efficiency – Active or passive estimator  Example: WMEWMA only estimates at fixed intervals

SS 05Ad hoc & sensor networs - Ch 6: Link layer protocols93 Conclusion  Link layer combines traditional mechanisms  Framing, packet synchronization, flow control with relatively specific issues  Careful choice of error control mechanisms – tradeoffs between FEC & ARQ & transmission power & packet size …  Link estimation and characterization