By: Hawa Soumare
Question
Part A: Finding zeros Part B: Integration Part C: Interpreting graphs Part D: Finding derivative and comparison Plan
First, set |V(t)| = 2. Which you then change to |V(t)| - 2 = 0. You plug this into the calculator, graph it, and find the zeros between the interval 2 ≤ t ≤ 4 Part A: Find all values of t in the interval 2 ≤ t ≤ 4 for which the speed of the particle is 2.
We can find s(5) by plugging in 5 for t Remember it is given that s(0) = 10 Part B: Write an expression involving an integral that gives the position s ( t ). Use this expression to find the position of the particle at time t = 5.
The particle will change direction when v(t) changes signs. You graph v(t) between 0 ≤ t ≤ 5 and see where it passes the x-axis. This occurs at t = and t = v ( t ) changes sign from negative to positive at time t = v ( t ) changes sign from positive to negative at time t = Therefore, the particle changes direction at time t = and time t = (or 3.317). Part C: Find all times t in the interval 0 ≤ t ≤ 5 at which the particle changes direction. Justify your answer.
Speed is increasing when the signs of v(t) and a(t) are the same and decreasing when the signs are different Using the calculator you will find: Part D: Is the speed of the particle increasing or decreasing at time t = 4 ? Give a reason for your answer.
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