Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 4.

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Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 4

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 5

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 5, cont.

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 6

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 6, cont.

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 7 To find average velocity, divide total displacement by time. The bear with the greater average velocity is the bear that ends up further from where he started after the same period of time (bear B). At t = 8.0 min., the bear with the greater velocity is the one with the greater slope of position v. time (Bear A). Bear A has a negative velocity (moving backward) from about 40 to 50 min (negative slope) The velocity of bear B is never negative (never a negative slope).

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 8

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 9

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 10 a.Speeding up b.Slowing down c.Speeding up d.Slowing down

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 12

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 13 The following answers are estimates; yours should be close. a.0-30s, s, s (where the graph is horizontal) b.All 8 intervals (where the graph is straight) c.0 m/s 1.5 m/s 3.0 m/s 1.5 m/s 0 m/s m/s -3 m/s -4 m/s

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 13, cont. d.0 m/s m/s 2 0 m/s m/s 2 0 m/s m/s m/s m/s 2 e.0-30s, s f.0-30s, s, s (where the graph is horizontal) g.When the graph slopes upward, acceleration is positive. When it slopes downward, acceleration is negative. Zero slope means no acceleration.

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 14

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 15

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 16

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 17

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 18

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 19

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 20

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 21

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 22

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 23

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 24

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 26, a

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 26, b

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 26, c

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 28

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 29 The pebble falls 11 m, therefore, the well is 11 m deep.

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 31 a.No (graph is not horizontal). b.Yes (slope is constant). Starting Position +0.5 m 0.0 m -5.5 m v (m/s ) t (s ) c.~3 m/s (y-int. of velocity v. time graph or initial slope of position v. time graph)

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 32 a.

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 32, cont. b.

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 33 a v (m/s ) t (s ) b v (m/s ) t (s ) c v (m/s ) t (s ) e v (m/s ) t (s ) d v (m/s ) t (s )

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 34 or

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 35

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 36 For the 1 st time interval: For the 2 nd time interval:

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 36, cont.

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 37

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 38

Copyright © by Holt, Rinehart and Winston. All rights reserved. Problems – 39 Since v i =0