SOLVING SIMULTANEOUS EQUATIONS ALCOHOLIC METHOD. SOLVING SIMULTANEOUS EQUATIONS-ALCOHOLIC METHOD On Friday night I had the choice of buying 3 cans of.

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SOLVING SIMULTANEOUS EQUATIONS ALCOHOLIC METHOD

SOLVING SIMULTANEOUS EQUATIONS-ALCOHOLIC METHOD On Friday night I had the choice of buying 3 cans of lager and 2 cans of bitter for £ 6 or 3 cans of lager and 1 can of bitter for £ My mate wants to buy the lager from me, how much did the lager cost?

SOLVING SIMULTANEOUS EQUATIONS-ALCOHOLIC METHOD Write as equations; Equation (1) 3l + 2b = 6 Equation (2) 3l + b = 4.5

SOLVING SIMULTANEOUS EQUATIONS-ALCOHOLIC METHOD Find the difference; Equation (1) 3l + 2b = 6 -Equation (2) - 3l + b = 4.5 b = 1.5

SOLVING SIMULTANEOUS EQUATIONS-ALCOHOLIC METHOD So 1 can of bitter costs £ 1.50 So by substituting b = 1.5, l can be found Equation (1) 3l + (2 x 1.5) = 6 3l + 3= 6 3l = 6 – 3 3l = 3 So … l = 1 1 Can of Lager = £1

SOLVING SIMULTANEOUS EQUATIONS-ALCOHOLIC METHOD Try this one yourself On Friday night you have the choice of buying 2 cans of lager and 3 cans of bitter for £ 11 or 2 cans of lager and 1 can of bitter for £ 7. Your mate wants to buy the lager from you, how much did the lager cost?

SOLVING SIMULTANEOUS EQUATIONS-ALCOHOLIC METHOD Equation (1) 2l + 3b = 11 Equation (2) -2l + b = 7 Difference 2b = 4 So… b = 2

SOLVING SIMULTANEOUS EQUATIONS-ALCOHOLIC METHOD