Copyright © 2009 Pearson Education, Inc. Chapter 30 Inductance, Electromagnetic Oscillations, and AC Circuits HW8: Chapter 28:18,31,40 Chapter 29:3, 30,48.

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Copyright © 2009 Pearson Education, Inc. Chapter 30 Inductance, Electromagnetic Oscillations, and AC Circuits HW8: Chapter 28:18,31,40 Chapter 29:3, 30,48 Due on Friday, April 15

A transformer is a device for increasing or decreasing an ac voltage A transformer consists of two coils, either interwoven or linked by an iron core. A changing emf in one induces an emf in the other. The ratio of the emfs is equal to the ratio of the number of turns in each coil: This is the transformer equation 29-6 Transformers and Transmission of Power

This is a step-up transformer – the emf in the secondary coil is larger than the emf in the primary and N s > N p 29-6 Transformers and Transmission of Power

Energy must be conserved; therefore, in the absence of losses, the ratio of the currents must be the inverse of the ratio of turns: 29-6 Transformers and Transmission of Power Because of conservation of energy, the power output cannot be greater than the power input

29-6 Transformers and Transmission of Power Example 29-12: Cell phone charger. The charger for a cell phone contains a transformer that reduces 120-V ac to 5.0- V ac to charge the 3.7-V battery. (It also contains diodes to change the 5.0-V ac to 5.0-V dc.) Suppose the secondary coil contains 30 turns and the charger supplies 700 mA. Calculate (a) the number of turns in the primary coil, (b) the current in the primary, and (c) the power transformed.

Transformers work only if the current is changing (AC); this is one reason why electricity is transmitted as ac Transformers and Transmission of Power

A changing magnetic flux induces an electric field; this is a generalization of Faraday’s law. The electric field will exist regardless of whether there are any conductors around: 29-7 A Changing Magnetic Flux Produces an Electric Field.

Mutual inductance: a changing current in one coil will induce an emf in a second coil (flux due to current of the first coil) And vice versa; note that the constant M (the mutual inductance) that depends on the size, shape and the number of turns, and is known as the mutual inductance, is the same: 30-1 Mutual Inductance

Unit of inductance: the henry, H: 1 H = 1 V·s/A = 1 Ω·s. A transformer is an example of mutual inductance Mutual Inductance M 12 =M 21 =M

30-1 Mutual Inductance Example 30-1: Solenoid and coil. A long thin solenoid of length l and cross- sectional area A contains N 1 closely packed turns of wire. Wrapped around it is an insulated coil of N 2 turns. Assume all the flux from coil 1 (the solenoid) passes through coil 2, and calculate the mutual inductance.

30-1 Mutual Inductance Conceptual Example 30-2: Reversing the coils. How would Example 30–1 change if the coil with turns was inside the solenoid rather than outside the solenoid?

2.(II) Determine the mutual inductance per unit length between two long solenoids, one inside the other, whose radii are r 1 and r 2 (r 2 < r 1 ) and whose turns per unit length are n 1 and n 2 Problem 2

A changing current in a coil will also induce an emf in itself: Here, L is called the self-inductance: 30-2 Self-Inductance

Example 30-3: Solenoid inductance. (a) Determine a formula for the self-inductance L of a tightly wrapped and long solenoid containing N turns of wire in its length l and whose cross-sectional area is A. (b) Calculate the value of L if N = 100, l= 5.0 cm, A = 0.30 cm 2, and the solenoid is air filled.

8.(II) An air-filled cylindrical inductor has 2800 turns, and it is 2.5 cm in diameter and 21.7 cm long. (a) What is its inductance? (b) How many turns would you need to generate the same inductance if the core were filled with iron of magnetic permeability 1200 times that of free space? Problem 8