5.2 Law of Sines. We know how to solve right △ s utilizing SOH–CAH–TOA ratios. What if the triangle is NOT right?! Law of Sines  used when you have 2.

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Presentation transcript:

5.2 Law of Sines

We know how to solve right △ s utilizing SOH–CAH–TOA ratios. What if the triangle is NOT right?! Law of Sines  used when you have 2 angles & an included side a, b, c are lengths of sides of a triangle and A, B, C are the measures of their opposite angles or flip all – We can still solve Suggestion…. Draw a picture!! use any 2 you need

Ex 1) Solve △ ABC if m ∠ A = 56 °, m ∠ B = 74 ° and b = 78.2 subtract to get m ∠ C 180 – 56 – 74 = 50 a 78.2 c B C A 56° 74° 50° m ∠ C = 50°

More word problems!!! DRAW THOSE PICTURES! Ex 2) A ship is moving in a straight line toward the Point Cove lighthouse. The measure of the angle of elevation from the bridge of the ship to the lighthouse beacon is 25º. Later, from a point 600 ft closer, the angle of elevation is 47º. How high is the beacon above the boat bridge? 180 – 47 = ° 47° h 133° 22° = …  STORE A 25° h A Now to big △ x

Let’s try this one with a partner! Ex 3) Find the perimeter of the piece of land shown with the given measurements. P = ft 110 ft B C A 13° 61° 39° D 76°

Add all up: P = D + E + B = ft B C A 13° 61° 39° D 76° II I △ I  m ∠ B = 65°  C  D △ II  m ∠ B = 106°  E  B

Homework #502 Pg 254 #2, 13, 22, 23, 27, 33, 35, 41, 43, 44