Rewrite Addition Problems as Multiplication Problems using the Distributive Property 6.NS.4 Quick Code LZ2581 Sadlier 6-5A 1/2014

What is the GCF of 24 and 9? 24 1x24 2x12 3x8 4x6 9 1x9 3x3 GCF = 3 Think… 3 times what makes 24 and 3 times what else makes = (3 x 8)(3 x 3)+ 3 (8 + 3) Review….

Mary plans to buy 12 yellow flowers and 18 blue flowers for her mother’s party. How can she combine the flowers into equal sets to put into vases?

In this lesson you will learn how to rewrite addition problems as multiplication problems by using the Distributive Property.

Let’s Review 1, 2, 3, and 6 Factor Pairs of 12 1x12 2x6 3x4 4x3 6x2 x1 Factor Pairs of 18 1x18 2x9 3x6 6x3 9x2 x1 2. Find common factors 1. List factor pairs 2. Find GCF

A Common Misunderstanding Factors are numbers that are answers to multiplication. Factors 1 x 5 2 x 53 x 54 x 55 x 5 Multiples Factors 1 x 7 2 x 73 x 74 x 75 x 7 Multiples

Core Lesson Mary plans to buy 15 yellow flowers and 18 blue flowers for her mother’s party. 15 yellow flowers + 18 blue flowers How can she combine the flowers into equal groups to put into vases?

Core Lesson Factor Pairs of 15 1x15 3x5 5x3 x1 Factor Pairs of 18 1x18 2x9 3x6 6x3 9x2 x1 Common factors: 1, 3 15 yellow flowers + 18 blue flowers

Core Lesson 3 groups of 5 yellow flowers Factor Pairs of 15 # groups# flowers 1x15 3x5 5x3 x1

Core Lesson 3 groups of 6 blue flowers Factor Pairs of 18 # groups# flowers 1x18 2x9 3x6 6x3 9x2 x1

Core Lesson Mary can divide the flowers up in to 3 vases.

The Distributive Property allows us to write an addition problem as a multiplication problem (5) + 3(6) 3(5 + 6) vases flowers

Core Lesson Factor Pairs of 25 1x25 5x5 x1 Factor Pairs of 30 1x30 2x15 3x10 5x6 6x5 x3 15x2 30x1 Common factors: 1, 5 Mary decided to buy 25 yellow flowers and 30 blue flowers.

Core Lesson Factor Pairs of 25 # groups# flowers 1x25 5x5 x1 5 groups of 5 yellow flowers

Core Lesson Factor Pairs of 30 # groups# flowers 1x30 2x15 3x10 5x6 6x5 x3 15x2 30x1 5 groups of 6 blue flowers.

Core Lesson Mary can use 5 vases to divide the flowers into equal groups (5) + 5(6) 5(5 + 6)

 Step 1: Find the Greatest Common Factor of Both Addends;  Step 2: Write each addend as a multiple of the GCF;  Step 3: Use the Distributive Property to rewrite the expression Rewrite using the Distributive Property GCF = 8 24 = 8 3 & 40 = 8 5 So = 8(3 + 5)

In this lesson you have learned how to rewrite addition problems as multiplication problems by using the Distributive Property.