Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Homework # 7 – Word Problems pg 92 # 51 An investor purchases 50 shares of a stock at $3.50.

Slides:



Advertisements
Similar presentations
Solving Linear Equations
Advertisements

Systems of Equations & Inequalities
Homework Answers (1-2 Worksheet)
Copyright © 2013, 2009, 2006 Pearson Education, Inc. 1 1 Section 2.2 The Multiplication Property of Equality Copyright © 2013, 2009, 2006 Pearson Education,
Basic Concepts of Algebra
Chapter 2 Review Algebra 1.
Operations: Add, Subtract, Multiply, Divide
Rational Numbers.
Multiplying and Dividing Real Numbers Objective: To multiply and divide real numbers.
1.2 & 1.3 Warm-Up. 1-2 Algebraic Expressions and Models An established ORDER OF OPERATIONS is used to evaluate an expression involving more than one operation.
Warm Up Simplify the following expression using order of operations.
§ 1.7 Multiplication and Division of Real Numbers.
Two equations are equivalent if they have the same solutions. Solving a Linear Equation An equation is a statement in which two expressions are equal.
Expressions, Equations, and Functions Chapter 1 Introductory terms and symbols: Variable – A letter or symbol to represent an unknown – Examples: Algebraic.
Chapter 1 Section 6. Objectives 1 Copyright © 2012, 2008, 2004 Pearson Education, Inc. Multiplying and Dividing Real Numbers Find the product of a positive.
SECTION 2.7 DIVISION OF REAL NUMBERS Objectives: Divide real numbers Use division to simplify algebraic expressions.
Warm-Up 1. f( g(x)) = ____ for g(x) = 2x + 1 and f(x) = 4x , if x = 3 2. (f + g)(x) = ____ for g(x) = 3x2+ 2x and f(x) = 3x (f/g)(x)
11-7 Multiplying Integers Warm Up Find each product ,600 14,000.
Chapter 1.  Pg. 4-9  Obj: Learn how to write algebraic expressions.  Content Standard: A.SSE.1.a.
Use the Distributive Property to: 1) simplify expressions 2) Solve equations.
Sec. 1-4 Day 2 HW pg (42-46, 53, 62-63, 67, 71-72)
Section 2.1 Solving Equations Using Properties of Equality.
Page Verbal and Algebraic Expressions/Equations.
Simplifying Algebraic Expressions Evaluating Algebraic Expressions 3-2 How are expressions simplified by combining like terms? How are expressions simplified.
ALGEBRA READINESS Chapter 5 Section 6.
12.1 Solving Two-Step Equations
7.4 Logarithmic Functions Write equivalent forms for exponential and logarithmic equations. Use the definitions of exponential and logarithmic functions.
2-5 HW = Pg #6-50 e, HW Continued 56.) C57.) B.
© 2010 Pearson Prentice Hall. All rights reserved. CHAPTER 6 Algebra: Equations and Inequalities.
Solving Linear Equations and Inequalities Chapter 2.
Do Now 10/2/09 Take out HW from last night. Take out HW from last night. Text p.81, #10-21 all, #33-35 all Text p.81, #10-21 all, #33-35 all Copy HW in.
EXAMPLE 1 Find multiplicative inverses of numbers a. The multiplicative inverse of 1 5 – is – 5 because b. The multiplicative inverse of 6 7 – is 7 6 –
1.5 The Distributive Property For any numbers a, b, and c, a(b + c) = ab + ac (b + c)a = ba + ca a(b – c)=ab – ac (b – c)a = ba – ca For example: 3(2 +
Chapter 4: System of Equations and Inequalities Section 4.4: Solving Linear Systems Using the Addition Method.
Chapter 2 Copyright © 2015, 2011, 2007 Pearson Education, Inc. Chapter 2-1 Solving Linear Equations and Inequalities.
Do Now 9/20/12 Take out HW from last night. Take out HW from last night. Text p. 28, #8-24 evens, #17, 35, & 36 Text p. 28, #8-24 evens, #17, 35, & 36.
You have seen positive exponents
Lesson 1-6 Multiplying and Dividing Real Numbers Pages
Chapter 1 Section 4 Distributive Property. Symbols: For any numbers a, b, c, a(b + c) = ab + ac and a(b - c) = ab – ac. Numbers: 2(5 + 3) = (2 ∙ 5) +
MTH 091 Sections 3.1 and 9.2 Simplifying Algebraic Expressions.
Solving Inequalities Using Multiplication and Division Chapter 4 Section 3.
§ 2.2 The Multiplication Property of Equality. Blitzer, Introductory Algebra, 5e – Slide #2 Section 2.2 Properties of Equality PropertyDefinition Addition.
Bell Quiz. Objectives Multiply and Divide signed numbers. Discuss the properties of real numbers that apply specifically to multiplication. Explain the.
The Distributive Property and Simplifying Expressions Sections 2.5 – 2.8.
My Equations Booklet.
6) x + 2y = 2 x – 4y = 14.
2 Understanding Variables and Solving Equations.
Algebra 1 Notes: Lesson 1-5: The Distributive Property
A.2 Simplifying Simplify means combine Like Terms.
The Distributive Property
Chapter 2 – Properties of Real Numbers
Solve for variable 3x = 6 7x = -21
Chapter 2 Review 14 questions: 1 – write a verbal expression
2 Understanding Variables and Solving Equations.
 Warm-up: n HW: Pg. 10 (40) Pg. 12 (75, 79, 84, 85, 8996, 110)
Equations Containing Decimals
Unit 3 Review.
Distributive Property
Algebra: Equations and Inequalities
Equations Containing Decimals
Several Transformations
Solving Equations Containing Fractions
Section Solving Linear Systems Algebraically
Rules for Multiplication and Division
2 Equations, Inequalities, and Applications.
2-5 (Part I) Applying the Distributive Property
10/3/11 In your notebook, answer completely the following:
2 Chapter Chapter 2 Equations, Inequalities and Problem Solving.
Chapter 2: Solving One-step Equations and Inequalities
Warm Up Simplify      20  2 3.
Presentation transcript:

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Homework # 7 – Word Problems pg 92 # 51 An investor purchases 50 shares of a stock at $3.50 per share. The next day, the change in value of a share of the stock is -$0.25. What is the total value of the shares the next day?

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Section 2.5 – Apply the Distributive Property Find the total areas of the two rectangles modeled below. Example # 1 7 units Total Area of the Rectangles = Area # 1 + Area # 2 x units 7 units 3 units Rectangle # 1 Rectangle # 2 Area of Rectangle = Length * Width Area # 1 = Length * Width Area # 1 = 7 units * x units Area # 1 = 7x units Area # 2 = Length * Width Area # 2 = 7 units * 3 units Area # 2 = 21 units Total Area of the Rectangles = 7x units + 21 units Total Area of the Rectangles = 7x + 21 units

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Section 2.5 – Apply the Distributive Property Find the area of the rectangle modeled below. Example # 1 (con’t) The Distributive Property allows you to find the product of a number with a sum/difference expression. x + 3 units 7 units Rectangle Area of Rectangle = Length * Width Area of Rectangle = 7 units *( x + 3 ) units Area of Rectangle = ((7 * x) + (7 * 3))units Area of Rectangle = 7x + 21 units Note: Thus; Total Area of the Rectangles = Area of Rectangle Total Area of the Rectangles = 7x + 21 units

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Section 2.5 – Apply the Distributive Property 4(x-2) (3-5)6 6(3-5) 4(x+5) (3+5)4 4(3+5) Given Examples = 4(x) - 4(2) = (3)6 - (5)6 = 6(3) - 6(5) = 4(x) + 4(5) = (3)4 + (5)4 = 4(3) + 4(5) Distributive Step = = -12a(b - c) = ab - acThe product of a and (b - c) = = -12(b - c)a = ba - ca = 4x + 20 = 4x - 8 = = 32(b + c)a = ba + ca = = 32a(b + c) = ab + acThe product of a and (b + c) AnswerAlgebraWords Distributive Property

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Section 2.5 – Apply the Distributive Property Example # 2 Use the distributive property to write an equivalent expression. a) (y – 2) * (-4) (y)*(-4) – (2)*(-4) -4y – (-8) -4y – (-8) -4y + 8 Distribute -4 Multiply Add the opposite of - 8 Simplified Expression b) -5x * (4 - x) (-5x)*(4) – (-5x)*(x) -20x – (-5x 2 ) -20x – (-5x 2 ) -20x + 5x 2 Distribute -5x Multiply Add the opposite of -5x 2 Simplified Expression c) -(3y – 9) (-1)*(3y) – (-1)*(9) -3y – (-9) -3y – (-9) -3y + 9 Distribute -1 Multiply Add the opposite of - 9 Simplified Expression

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Section 2.5 – Apply the Distributive Property Coefficient – the number part of a term with a variable part Terms – the parts of the expression that are added together Constant – the number part of expression that does not contain a variable Like Terms – are terms that have the same variable parts Example # 3 Identify the terms, like terms, coefficients, and constant terms of the following expression a) -2x – 8 + 6x + 5 c) 6 - 5x + 3y + 6 b) 3y + 6 – 8y – 2 Constant Terms: -8, +5 Constant Terms: 6, -2 Constant Terms: 6, 6 Coefficients: -2, +6Like Terms: -2x, 6x; -8, +5; Like Terms: 3y, -8y; +6, -2Coefficients: 3, -8 Coefficients: -5, 3Like Terms: 6, 6;

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Section 2.5 – Apply the Distributive Property PROBLEM SOLVING PLAN READ AND UNDERSTAND Read the Problem CAREFULLY!!! STEP 1 : Identify Variables and Constants. What is the problem asking? ORGANIZE YOUR THOUGHTS Formulate an Approach. STEP 2 : Make an equation, inequality or expression. SOLVE THE PROBLEM Evaluate the equation, inequality or expression STEP 3 : CHECK YOUR WORK DOES IT MAKES SENSE!!! STEP 4 :

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Section 2.5 – Apply the Distributive Property Example # 3 You are making curtains by alternating strips of solid colored fabric and patterned fabric. The solid colored fabric costs $0.99 per strip and the patterned fabric costs $1.25 per strip. You need 7 strips for one curtain. Find the total cost if you use 3 solid colored strips. Write a verbal model. Multiply C = ($0.99) * S + ($1.25) * (7 – S) Total Cost for Curtain w/ 3 Solid = Colored Strips (dollars) Cost for Solid Colored Strips (dollars per strips) Cost for + Patterned Colored Strips (dollars per strips) Number of * Solid Colored Strips (strips) Combine Like Terms Distribute $1.25 Simplified Equation Number of * Patterned Colored Strips (strips) C = ($0.99)* S + ($1.25) * (7 – S) Write an Equation. C = $0.99S + ($1.25)(7) - ($1.25)(S) C = $0.99S + $ $1.25S C = $ $0.26S

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Section 2.5 – Apply the Distributive Property Example # 3 (con’t) You are making curtains by alternating strips of solid colored fabric and patterned fabric. The solid colored fabric costs $0.99 per strip and the patterned fabric costs $1.25 per strip. You need 7 strips for one curtain. Find the total cost if you use 3 solid colored strips. Add Multiply Find the Total Cost (C) when the number of colored strips (S) = 3. C = $ $0.78 C = $7.97 C = $ $0.26(3) The total cost if you use 3 solid colored fabric strips to make a curtain is $ Substitute

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Section 2.6 – Divide Real Numbers Inverse Property of Multiplication The product of a nonzero number and its multiplicative inverse is 1. Example # 4 Division Rule To divide a number a by a nonzero number b, multiply a by the multiplicative inverse of b. a)b) The Sign of a Quotient - The quotient of two real numbers with the same sign is positive. The quotient of two real numbers with different signs is negative. The quotient of 0 and any nonzero real numbers is 0.

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Section 2.6 – Divide Real Numbers Example # 5 Simplify the following expression. a) = = = = Apply the division rule Use the Distributive Property Simplify Rewrite the fraction as division

Chapter 2 – Properties of Real Numbers Algebra I A - Meeting 9 Homework # 8 pg 99 # 3 – 42 mult. of 3; # 53 pg 106 # 9 – 23 odd; # 33 – 43 odd Section 2.5, 2.6