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Copyright 2013, 2009, 2005, 2002 Pearson, Education, Inc.

6.6 Rational Equations and Problem Solving

Step 1: Clear the equation of fractions or rational expressions by multiplying each side of the equation by the least common denominator (LCD) of all denominators in the equation. Step 2: Use the distributive property to remove grouping symbols such as parentheses. Step 3: Combine like terms on each side of the equation. Solving an Equation for a Specified Variable

Step 4: Use the addition property of equality to rewrite the equation as an equivalent equation with terms containing the specified variable on one side and all other terms on the other side. Step 5: Use the distributive property and the multiplication property of equality to get the specified variable alone. Solving an Equation for a Specified Variable

Solve the following equation for R 1. Example

Continued The quotient of a number and 9 times its reciprocal is 1. Find the number. Read and reread the problem. If we let n = the number, then = the reciprocal of the number 1. Understand

Continued Example (cont) 2. Translate The quotient of  a number n and 9 times its reciprocalis = 1 1

3. Solve Continued Example (cont)

4. Interpret Example (cont) Check: We substitute the values we found from the equation back into the problem. Note that nothing in the problem indicates that we are restricted to positive values. State: The missing number is 3 or –3. True

Ratios and Rates Ratio is the quotient of two numbers or two quantities. The units associated with the ratio are important. The units should match. If the units do not match, it is called a rate, rather than a ratio. The ratio of the numbers a and b can also be written as a:b, or.

Proportion is two ratios (or rates) that are equal to each other. We can rewrite the proportion by multiplying by the LCD, bd. This simplifies the proportion to ad = bc. This is commonly referred to as the cross product. Proportions

Solve the proportion for x. Example Continued

True Substitute the value for x into the original equation, to check the solution. So the solution is Example (cont)

If a 170-pound person weighs approximately 65 pounds on Mars, how much does a 9000-pound satellite weigh? Example

Continued An experienced roofer can roof a house in 26 hours. A beginner needs 39 hours to do the same job. How long will it take if the two roofers work together? Read and reread the problem. By using the times for each roofer to complete the job alone, we can figure out their corresponding work rates in portion of the job done per hour. 1. Understand Experienced roofer 26 1/26 Beginner roofer 39 1/39 Together t 1/t Time in hrsPortion job/hr

Continued Example (cont) 2. Translate Since the rate of the two roofers working together would be equal to the sum of the rates of the two roofers working independently,

3. Solve Continued Example (cont)

4. Interpret Example (cont) Check: We substitute the value we found from the proportion calculation back into the problem. State: The roofers would take 15.6 hours working together to finish the job. True

Example Continued The speed of Lazy River’s current is 5 mph. A boat travels 20 miles downstream in the same time as traveling 10 miles upstream. Find the speed of the boat in still water. Read and reread the problem. By using the formula d=rt, we can rewrite the formula to find that t = d/r. We note that the rate of the boat downstream would be the rate in still water + the water current and the rate of the boat upstream would be the rate in still water – the water current. 1. Understand Down 20 r /(r + 5) Up 10 r – 5 1 0/(r – 5) Distance rate time = d/r

Continued Example (cont) 2. Translate Since the problem states that the time to travel downstairs was the same as the time to travel upstairs, we get the equation

3. Solve Continued Example (cont)

4. Interpret Example (cont) Check: We substitute the value we found from the proportion calculation back into the problem. True State: The speed of the boat in still water is 15 mph.