Inorganic Nomenclature Write the name of the cation. If the anion is an element, change its ending to -ide; if the anion is a polyatomic ion, simply write.

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Presentation transcript:

Inorganic Nomenclature Write the name of the cation. If the anion is an element, change its ending to -ide; if the anion is a polyatomic ion, simply write the name of the polyatomic ion. If the cation can have more than one possible charge, write the charge as a Roman numeral in parentheses.

Patterns in Oxyanion Nomenclature When there are two oxyanions involving the same element: –The one with fewer oxygens ends in -ite. NO 2 − : nitrite ; SO 3 2− : sulfite –The one with more oxygens ends in -ate. NO 3 − : nitrate; SO 4 2− : sulfate

Patterns in Oxyanion Nomenclature The one with the second fewest oxygens ends in -ite. –ClO 2 − : chlorite The one with the second most oxygens ends in -ate. –ClO 3 − : chlorate

Patterns in Oxyanion Nomenclature The one with the fewest oxygens has the prefix hypo- and ends in -ite. –ClO − : hypochlorite The one with the most oxygens has the prefix per- and ends in -ate. –ClO 4 − : perchlorate

Sample Exercise 2.11 Determining the Formula of an Oxyanion form Its Name Based on the formula for the sulfate ion, predict the formula for (a) the selenate ion and (b) the selenite ion. (Sulfur and selenium are both members of group 6A and form analogous oxyanions.) Solution (a) The sulfate ion is SO 4 2–. The analogous selenate ion is therefore SeO 4 2–. (b) The ending -ite indicates an oxyanion with the same charge but one O atom fewer than the corresponding oxyanion that ends in -ate. Thus, the formula for the selenite ion is SeO 3 2–.

The formula for the bromate ion is analogous to that for the chlorate ion. Write the formula for the hypobromite and perbromate ions. Practice Exercise

Answer: BrO – and BrO 4 –

Acid Nomenclature If the anion in the acid ends in -ide, change the ending to -ic acid and add the prefix hydro-. –HCl: hydrochloric acid –HBr: hydrobromic acid –HI: hydroiodic acid

Acid Nomenclature If the anion in the acid ends in -ite, change the ending to -ous acid. –HClO: hypochlorous acid –HClO 2 : chlorous acid

Acid Nomenclature If the anion in the acid ends in -ate, change the ending to -ic acid. –HClO 3 : chloric acid –HClO 4 : perchloric acid

Sample Exercise 2.14 Relating the Names and Formulas of Acids Name the following acids: (a) HCN, (b) HNO 3, (c) H 2 SO 4, (d) H 2 SO 3. Solution (a) The anion from which this acid is derived is CN –, the cyanide ion. Because this ion has an -ide ending, the acid is given a hydro- prefix and an -ic ending: hydrocyanic acid. Only water solutions of HCN are referred to as hydrocyanic acid: The pure compound, which is a gas under normal conditions, is called hydrogen cyanide. Both hydrocyanic acid and hydrogen cyanide are extremely toxic. (b) Because is the nitrate NO 3 – ion, HNO 3 is called nitric acid (the - ate ending of the anion is replaced with an -ic ending in naming the acid). (c) Because SO 4 2– is the sulfate ion, H 2 SO 4 is called sulfuric acid. (d) Because SO 3 2– is the sulfite ion, H 2 SO 3 is sulfurous acid (the -ite ending of the anion is replaced with an -ous ending).

Give the chemical formulas for (a) hydrobromic acid, (b) carbonic acid. Practice Exercise

Answer: (a) HBr, (b) H 2 CO 3

Nomenclature of Binary Compounds The less electronegative atom is usually listed first. A prefix is used to denote the number of atoms of each element in the compound (mono- is not used on the first element listed, however).

Nomenclature of Binary Compounds The ending on the more electronegative element is changed to -ide. –CO 2 : carbon dioxide –CCl 4 : carbon tetrachloride

Nomenclature of Binary Compounds If the prefix ends with a or o and the name of the element begins with a vowel, the two successive vowels are often elided into one. N 2 O 5 : dinitrogen pentoxide

Sample Exercise 2.15 Relating the Names and Formulas of Binary Molecular Compounds Name the following compounds: (a) SO 2, (b) PCl 5, (c) N 2 O 3. Give the chemical formula for (a) silicon tetrabromide, (b) disulfur dichloride. Answer: (a) SiBr 4, (b) S 2 Cl 2 Practice Exercise Solution The compounds consist entirely of nonmetals, so they are molecular rather than ionic. Using the prefixes in Table 2.6, we have (a) sulfur dioxide, (b) phosphorus pentachloride, and (c) dinitrogen trioxide.