Unit 4: Triangle congruence

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Unit 4: Triangle congruence 4.3 Congruent Triangles

Warm Up (HW #20 [4.3] Pages 234 – 235 #s 11, 13 – 19) 1. Name all sides and angles of ∆FGH. 2. What is true about K and L? Why? 3. What does it mean for two segments to be congruent? FG, GH, FH, F, G, H K  L;Third s Thm. They have the same length.

Objectives Use properties of congruent triangles. Prove triangles congruent by using the definition of congruence. *Standard 5.0 Students prove that triangles are congruent or similar, and they are able to use the concept of corresponding parts of congruent triangles. ***Also Standard 2.0 Students write geometric proofs, including proofs by contradiction***

Geometric figures are congruent if they are the same size and shape Geometric figures are congruent if they are the same size and shape. Corresponding angles and corresponding sides are in the same position in polygons with an equal number of sides. Two polygons are congruent polygons if and only if their corresponding sides are congruent. Thus triangles that are the same size and shape are congruent.

Two vertices that are the endpoints of a side are called consecutive vertices. For example, P and Q are consecutive vertices. Helpful Hint To name a polygon, write the vertices in consecutive order. For example, you can name polygon PQRS as QRSP or SRQP, but not as PRQS. In a congruence statement, the order of the vertices indicates the corresponding parts. When you write a statement such as ABC  DEF, you are also stating which parts are congruent. Helpful Hint

Identify all pairs of corresponding congruent parts. Example 1: Naming Congruent Corresponding Parts Given: ∆PQR  ∆STW Identify all pairs of corresponding congruent parts. Angles: P  S, Q  T, R  W Sides: PQ  ST, QR  TW, PR  SW Check It Out! Example 1 If polygon LMNP  polygon EFGH, identify all pairs of corresponding congruent parts. Angles: L  E, M  F, N  G, P  H Sides: LM  EF, MN  FG, NP  GH, LP  EH

Given: ∆ABC  ∆DBC. Find the value of x. BCA and BCD are rt. s. Example 2A: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x. BCA and BCD are rt. s. Def. of  lines. BCA  BCD Rt.   Thm. mBCA = mBCD Def. of  s Substitute values for mBCA and mBCD. (2x – 16)° = 90° 2x = 106 Add 16 to both sides. x = 53 Divide both sides by 2.

Given: ∆ABC  ∆DBC. Find mDBC. mABC + mBCA + mA = 180° Example 2B: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find mDBC. ∆ Sum Thm. mABC + mBCA + mA = 180° Substitute values for mBCA and mA. mABC + 90 + 49.3 = 180 mABC + 139.3 = 180 Simplify. Subtract 139.3 from both sides. mABC = 40.7 DBC  ABC Corr. s of  ∆s are  . mDBC = mABC Def. of  s. mDBC  40.7° Trans. Prop. of =

Find the value of x and mF. Check It Out! Example 2a Given: ∆ABC  ∆DEF Find the value of x and mF. AB  DE Corr. sides of  ∆s are . AB = DE Def. of  parts. 2x – 2 = 6 Substitute values for AB and DE. 2x = 8 Add 2 to both sides. mEFD + mDEF + mFDE = 180° x = 4 Divide both sides by 2. mEFD + 53 + 90 = 180 mF + 143 = 180 ABC  DEF Corr. angles of  ∆ are . mF = 37° mABC = mDEF Def. of  angles. mDEF = 53° Transitive Prop. of =.

Given: YWX and YWZ are right angles, Example 3: Proving Triangles Congruent Given: YWX and YWZ are right angles, YW bisects XYZ, W is the midpoint of XZ, XY  YZ. Prove: ∆XYW  ∆ZYW Statements Reasons 1. YWX and YWZ are rt. angles. 1. Given 2. YWX  YWZ 2. Rt.   Thm. 3. YW bisects XYZ 3. Given 4. XYW  ZYW 4. Def. of bisector 5. W is mdpt. of XZ 5. Given 6. XW  ZW 6. Def. of mdpt. 7. YW  YW 7. Reflex. Prop. of  8. X  Z 8. Third angles Thm. 9. XY  YZ 9. Given 10. ∆XYW  ∆ZYW 10. Def. of  ∆

Given: AD bisects BE, BE bisects AD, AB  DE, A  D Check It Out! Example 3 Given: AD bisects BE, BE bisects AD, AB  DE, A  D Prove: ∆ABC  ∆DEC Statements Reasons 1. A  D 1. Given 2. BCA  DCE 2. Vertical s are . 3. ABC  DEC 3. Third s Thm. 4. Given 4. AB  DE 5. Given BE bisects AD 5. AD bisects BE, 6. BC  EC, AC  DC 6. Def. of bisector 7. ∆ABC  ∆DEC 7. Def. of  ∆s

Check It Out! Example 4 Use the diagram to prove the following. Given: MK bisects JL. JL bisects MK. JK  ML. JK || ML. Prove: ∆JKN  ∆LMN Statements Reasons 1. JK  ML 1. Given 2. JK || ML 2. Given 3. JKN  NML 3. Alt int. s are . 4. JL and MK bisect each other. 4. Given 5. JN  LN, MN  KN 5. Def. of bisector 6. KNJ  MNL 6. Vert. s Thm. 7. KJN  MLN 7. Third s Thm. 8. ∆JKN ∆LMN 8. Def. of  ∆s

1. ∆ABC  ∆JKL and AB = 2x + 12. JK = 4x – 50. Find x and AB. Lesson Quiz 1. ∆ABC  ∆JKL and AB = 2x + 12. JK = 4x – 50. Find x and AB. Given that polygon MNOP  polygon QRST, identify the congruent corresponding part. NO  ____ 3. T  ____ 31, 74 RS P

7. Def. of  ∆s 7. ABC  EDC 6. Third s Thm. 6. B  D Lesson Quiz 4. Given: C is the midpoint of BD and AE. A  E, AB  ED Prove: ∆ABC  ∆EDC 7. Def. of  ∆s 7. ABC  EDC 6. Third s Thm. 6. B  D 5. Vert. s Thm. 5. ACB  ECD 4. Given 4. AB  ED 3. Def. of mdpt. 3. AC  EC; BC  DC 2. Given 2. C is mdpt. of BD and AE 1. Given 1. A  E Reasons Statements