Announcements – 272H EXAM 1 – Thursday, Feb. 13, 8-9:30 pm in room 203 –Chapters 14, 15, & 16 –Equation sheet will be provided –Pencil, calculator There.

Slides:



Advertisements
Similar presentations
Chapter 22: The Electric Field II: Continuous Charge Distributions
Advertisements

Applications of Gauss’s Law
Lecture 6 Problems.
Continuous Charge Distributions
Relative to the effort it would take to thoroughly read the chapter once, how much effort did you put into doing the reading assignment? a) 0-20% b) 20-50%
Hw: All Chapter 5 problems and exercises. Test 1 results Average 75 Median 78 >90>80>70>60>50
1/22/07184 Lecture 81 PHY 184 Spring 2007 Lecture 8 Title: Calculations on Electrostatics.
I-5 Special Electrostatic Fields Main Topics Electric Charge and Field in Conductors. The Field of the Electric Dipole. Behavior.
General Physics 2, Lec 6, By/ T.A. Eleyan
Cut the charge distribution into pieces for which the field is known
Chapter 22 Patterns of Fields in Space Electric flux Gauss’s law Ampere’s law Maxwell equations.
Hw: All Chapter 5 problems and exercises. Outline Applications of Gauss’s Law - The single Fixed Charge -Field of a sphere of charge -Field of a spherical.
Chapter 22 Gauss’s Law Gauss’s Law is a relationship between the field at all the points on the surface and the total charge enclosed within the surface.
Example Problem Solution:
Question A) B) C) D) E An electric field polarizes a metal block as shown.
Gauss’ Law.
Divide shell into rings of charge, each delimited by the angle  and the angle  Use polar coordinates  r  Distance from center: d  r  Rcos.
Electrical Energy and Capacitance
Chapter 22 Electric Field
General Physics 2, Lec 5, By/ T.A. Eleyan 1 Additional Questions (Gauss’s Law)
Electric fields Gauss’ law
Chapter 21 Gauss’s Law. Electric Field Lines Electric field lines (convenient for visualizing electric field patterns) – lines pointing in the direction.
Copyright © 2009 Pearson Education, Inc. Lecture 4 – Electricity & Magnetism (Electrostatics) a. Electric Charge, Electric Field & Gauss’ Law.
Electric Energy and Capacitance
Physics 2112 Unit 4: Gauss’ Law
MIDTERM 1 UTC Thu-Sep 27, 7:00PM - 9:00PM Course Summary Unit 1 Provided Bring pencils, calculators (memory cleared)
Application of Gauss’ Law to calculate Electric field:
Question. Question A) B) C) D) E An electric field polarizes a metal.
Tue. Feb. 3 – Physics Lecture #26 Gauss’s Law II: Gauss’s Law, Symmetry, and Conductors 1. Electric Field Vectors and Electric Field Lines 2. Electric.
Physics 2113 Lecture: 09 MON 14 SEP
Electric Field formulas for several continuous distribution of charge.
Key Ideas in Chapter 14: Electric Field  A charged particle makes an electric field at every location in space (except its own location).  The electric.
Copyright © 2012 Pearson Education Inc. PowerPoint ® Lectures for University Physics, Thirteenth Edition – Hugh D. Young and Roger A. Freedman Lectures.
Relative to the effort it would take to thoroughly read the chapter once, how much effort did you put into doing the reading assignment? a) 0-20% b) 20-50%
Physics 2102 Lecture 10r: WED04FEB
Electric Fields Due to Continuous Charge Distributions
Question 300 V/m 0 V/m 300 V/m A B 0.02m 0.03m 0.04m What is VB-VA?
Unimportable clickers:
Last Time Insulators: Electrons stay close to their own atoms
Electric flux To state Gauss’s Law in a quantitative form, we first need to define Electric Flux. # of field lines N = density of field lines x “area”
θ dθ Q R Clicker Question
Physics 2102 Lecture: 06 MON 26 JAN 08
Day 5: Objectives Electric Field Lines
Gauss’ Law Symmetry ALWAYS TRUE!
Patterns of Fields in Space
EXAM1 Wednesday, Feb. 12, 8:00-10:00 pm
ENE 325 Electromagnetic Fields and Waves
Which graphical representation of electric field of a point charge
PHYSICS 272 Electric & Magnetic Interactions
Physics 2113 Jonathan Dowling Physics 2113 Lecture 13 EXAM I: REVIEW.
Copyright © 2014 John Wiley & Sons, Inc. All rights reserved.
ENE 325 Electromagnetic Fields and Waves
Last Lectures This lecture Gauss’s law Using Gauss’s law for:
Chapter 21 Gauss’s Law.
Flux Capacitor (Schematic)
Physics 2113 Lecture: 11 MON 09 FEB
Last Lectures This lecture Gauss’s law Using Gauss’s law for:
problem1 - Charge in a Cube
Chapter 22 Electric Field
Quiz 1 (lecture 4) Ea
Electric Flux Density, Gauss’s Law, and Divergence
Norah Ali Al-moneef King Saud university
Phys102 Lecture 2 The Electric Field
Halliday/Resnick/Walker Fundamentals of Physics 8th edition
Electric flux To state Gauss’s Law in a quantitative form, we first need to define Electric Flux. # of field lines N = density of field lines x “area”
Chapter 21, Electric Charge, and electric Field
Electric field of distributed charges
Chapter 16 Electric Field of Distributed Charges
Gauss’s Law: applications
Physics 122B Electricity and Magnetism
Presentation transcript:

Announcements – 272H EXAM 1 – Thursday, Feb. 13, 8-9:30 pm in room 203 –Chapters 14, 15, & 16 –Equation sheet will be provided –Pencil, calculator There will be no lecture on Monday Feb. 17

ABCDEABCDE is equal Clicker Question

General Procedure for Calculating Electric Field of Distributed Charges 1.Cut the charge distribution into pieces for which the field is known 2.Write an expression for the electric field due to one piece (i) Choose origin (ii) Write an expression for  E and its components 3.Add up the contributions of all the pieces (i) Try to integrate symbolically (ii) If impossible – integrate numerically 4.Check the results: (i) Direction (ii) Units (iii) Special cases

A total charge Q is uniformly distributed over a half ring with radius R. The total charge inside a small element dθ is given by: 1.Choice One 2.Choice Two 3.Choice Three 4.Choice Four 5.Choice Five 6.Choice Six θ dθdθ Q R A. B. C. D. E. Clicker Question

A total charge Q is uniformly distributed over a half ring with radius R. The Y component of electric field at the center created by a short element dθ is given by: 1.Choice One 2.Choice Two 3.Choice Three 4.Choice Four θ dθdθ Q R A. B. C. D. +y Clicker Question

Section 15.5 – home study! A Uniformly Charged Disk

Uniformly Charged Disk Edge On Can a conducting disk have uniform charge distribution? A single metal disk cannot be uniformly charged: charges repel and concentrate at the edges

A Uniformly Charged Disk Close to the disk (0 < z < R) Along z axis Approximations: If z/R is extremely small Very close to disk (0 < z << R)

Field Far From the Disk Exact For z>>R Point Charge

Two disks of opposite charges, s<<R: charges distribute uniformly: +Q+Q-Q-Q s We will calculate E both inside and outside of the disk close to the center Two uniformly charged metal disks of radius R placed very near each other Almost all the charge is nearly uniformly distributed on the inner surfaces of the disks; very little charge on the outer surfaces. Capacitor Why must there be charge on the outer surfaces?

+Q+Q-Q-Q s We know the field for a single diskThere are only 2 “pieces” E-E- E+E+ E net Step 1: Cut Charge Distribution into Pieces

Step 2: Contribution of one Piece Origin: left disk, center E-E- E+E+ E net s z 0 Location of disks: z=0, z=s Distance from disk to  2 z, (s-z) Left: Right:

Step 3: Add up Contributions E-E- E+E+ E net s z 0 Location:  2 (inside a capacitor)  Does not depend on z

Step 3: Add up Contributions E-E- E+E+ E net s z 0 Location:  3 (fringe field) For s<<R: E 1 =E 3  0 Far from the capacitor (z>>R>>s): E 1 =E 3 ~1/z 3 (like dipole) Fringe field is very small compared to the field inside the capacitor.

E-E- E+E+ E net s z 0 Units:  Inside: Fringe: Step 4: check the results: Electric Field of a Capacitor

Given: capacitor, radius R=50 cm, gap s=1 mm (air). Find: maximum charge before sparks are formed (E crit =3  10 6 N/C) Solution: What Q would cause sparking if spacing s  2s? What is the attractive force between the plates? F=QE= (2.1  C)(3  10 6 N/C)=63 N F=Q(E crit /2)= (2.1  C)(3  10 6 /2 N/C)=31.5 N Exercise

Field inside: Field outside:(like point charge)  Qualitative approach  Integration Electric Field of a Spherical Shell of Charge

E 1 +E 4 E2E2 E3E3 E6E6 E5E5 Divide into 6 areas: Direction: radial- due to the symmetry  E of a Sphere Outside

Magnitude:  How would a charged sphere interact with other charges? - as a point charge (same force) E of a Sphere Outside As long as we are far from a region of distributed charges we can approximate the electric field of that region as being due to a point charge.

Magnitude: E=0  Note: E is not always 0 inside – other charges in the Universe may make a nonzero electric field inside. E of a Sphere Inside

E=0: Implications Fill charged sphere with plastic. Will plastic be polarized? No! Solid metal sphere: since it is a conductor, any excess charges on the sphere arranges itself uniformly on the outer surface. There will be no field nor excess charges inside! In general: In static equilibrium, there is no electric field inside metals E of a Sphere Inside

What is electric field right at the surface? Need to be >1000 atomic diameters away from surface for equations to work! E of a Sphere Inside Electric field at the surface is highly variable in magnitude and direction