Holt McDougal Geometry 8-3 Solving Right Triangles 8-3 Solving Right Triangles Holt Geometry Warm Up Warm Up Lesson Presentation Lesson Presentation Lesson.

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Presentation transcript:

Holt McDougal Geometry 8-3 Solving Right Triangles 8-3 Solving Right Triangles Holt Geometry Warm Up Warm Up Lesson Presentation Lesson Presentation Lesson Quiz Lesson Quiz Holt McDougal Geometry

8-3 Solving Right Triangles Warm Up Use ∆ABC for Exercises 1–3. 1. If a = 8 and b = 5, find c. 2. If a = 60 and c = 61, find b. 3. If b = 6 and c = 10, find sin B. Find AB. 4. A(8, 10), B(3, 0) 5. A(1, –2), B(2, 6)

Holt McDougal Geometry 8-3 Solving Right Triangles Use trigonometric ratios to find angle measures in right triangles and to solve real-world problems. Objective

Holt McDougal Geometry 8-3 Solving Right Triangles In Lesson 8-2, you learned that sin 30° = 0.5. Conversely, if you know that the sine of an acute angle is 0.5, you can conclude that the angle measures 30°. This is written as sin -1 (0.5) = 30°.

Holt McDougal Geometry 8-3 Solving Right Triangles If you know the sine, cosine, or tangent of an acute angle measure, you can use the inverse trigonometric functions to find the measure of the angle.

Holt McDougal Geometry 8-3 Solving Right Triangles Example 2: Calculating Angle Measures from Trigonometric Ratios Use your calculator to find each angle measure to the nearest degree. A. cos -1 (0.87)B. sin -1 (0.85)C. tan -1 (0.71) cos -1 (0.87)  30°sin -1 (0.85)  58°tan -1 (0.71)  35°

Holt McDougal Geometry 8-3 Solving Right Triangles Check It Out! Example 2 Use your calculator to find each angle measure to the nearest degree. a. tan -1 (0.75)b. cos -1 (0.05)c. sin -1 (0.67) cos -1 (0.05)  87°sin -1 (0.67)  42°tan -1 (0.75)  35°

Holt McDougal Geometry 8-3 Solving Right Triangles Using given measures to find the unknown angle measures or side lengths of a triangle is known as solving a triangle. To solve a right triangle, you need to know two side lengths or one side length and an acute angle measure.

Holt McDougal Geometry 8-3 Solving Right Triangles Example 3: Solving Right Triangles Find the unknown measures. Round lengths to the nearest hundredth and angle measures to the nearest degree. By the Pythagorean Theorem, Since the acute angles of a right triangle are complementary, mT  90° – 29°  61°. RT 2 = RS 2 + ST 2 (5.7) 2 = ST 2

Holt McDougal Geometry 8-3 Solving Right Triangles Check It Out! Example 3 Find the unknown measures. Round lengths to the nearest hundredth and angle measures to the nearest degree. Since the acute angles of a right triangle are complementary, mD = 90° – 58° = 32°., so EF = 14 tan 32°. EF  8.75 DF 2 = DF 2 = ED 2 + EF 2 DF  16.51

Holt McDougal Geometry 8-3 Solving Right Triangles Examples: Use your calculator to find each angle measure to the nearest degree. 1. cos -1 (0.97) 2. tan -1 (2) 3. sin -1 (0.59) 14° 63° 36°

Holt McDougal Geometry 8-3 Solving Right Triangles Examples: Find the unknown measures. Round lengths to the nearest hundredth and angle measures to the nearest degree DF  5.7; mD  68°; mF  22° AC  0.63; BC  2.37; m B = 15°

Holt McDougal Geometry 8-3 Solving Right Triangles Classwork/Homework 8.3 #’s: 1-15all, 33, 35