By Fluke India.

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Presentation transcript:

By Fluke India

 A measurement that compares real power(watts) being consumed to the apparent power(Volt-Amps) of the load  A purely resistive load would have a power factor of 1.0

The system capacity is rated by the apparent power(kVA) which must be large enough to accommodate both the real power (kW) & reactive power(kVAR) Since reactive power requires system capacity, but performs no work, utilities charge more for it and plants try to keep net kVARs low High reactive power translates to low per factor

Utilities may charge higher rates or penalties for low power factor or high VARs System capacity restrictions cause voltage drops and overheating Inductive VARs can be corrected by applying capacitors or active conditioners

Sample calculation Assume the utility adds 1 % of demand charge for each 0.01 below PF of Assume your PF averages 0.86 each month and your demand charge is $7000. (0.97 – 0.86) * 100 % = 11 % (11 % x $7000) x 12 months = $9,240 avoidable annual cost

See if your utility rate plan imposes a charge for reactive demand or power factor Find out how the utility measures power factor or VARs. For example, are they looking at peak intervals or averages? Identify loads that are causing lagging reactive power and develop a strategy for power factor correction

To avoid paying higher utility fees, power factor should be higher than.97 Capacitors or conditioners may be applied on individual loads, at a confluence of several, or at the service entrance to improve power factor

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