 Start with the absolute value of -14  Add the number of inches in ½ foot  Square your result  Subtract the number of degrees in a right angle  Multiply.

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Presentation transcript:

 Start with the absolute value of -14  Add the number of inches in ½ foot  Square your result  Subtract the number of degrees in a right angle  Multiply the digits of your answer together  Add the number of vertices in a pentagon

 Up to 5 points on overall grade per Quarter  2 points for a neat, organized, complete notebook  1 point for attending STEM activity  2 points for coordinating STEM visitor  1 point for Go Animate Video describing a recent invention, engineer or Algebra 2 Concept  1 point for article summary discussing Math or Science in the News

Page 685, 1-9, odd Page 692, ; odd

A.41 blocks B.45 blocks C.49 blocks D.53 blocks 1. PYRAMIDS Hermán is building a pyramid out of blocks for an engineering class. On the top level, there is one block. In the second level, there are 5 blocks. In the third, there are 9 blocks. This pattern continues for the rest of the levels down to the 18 th level at the base of the pyramid. Use this information to determine how many blocks will be in the 13 th level of the pyramid. a n = a 1 + (n – 1)d A.85 B.95 C.108 D Evaluate. A.3, 7, 12 B.3, 9, 15 C.3, 9, 18 D.3, 18, Find the first three terms of the arithmetic series for which a 1 = 3, a n = 33, and S n = 108.

A.41 blocks B.45 blocks C.49 blocks D.53 blocks 1. PYRAMIDS Hermán is building a pyramid out of blocks for an engineering class. On the top level, there is one block. In the second level, there are 5 blocks. In the third, there are 9 blocks. This pattern continues for the rest of the levels down to the 18 th level at the base of the pyramid. Use this information to determine how many blocks will be in the 13 th level of the pyramid. a n = a 1 + (n – 1)d A.85 B.95 C.108 D Evaluate. A.3, 7, 12 B.3, 9, 15 C.3, 9, 18 D.3, 18, Find the first three terms of the arithmetic series for which a 1 = 3, a n = 33, and S n = 108.

Solve |2x – 2|  4. Graph the solution set on a number line. |2x – 2|  4 is equivalent to 2x – 2  4 or 2x – 2  –4. Solve each inequality. 2x – 2  4or2x – 2  –4 2x  62x  –2 x  3x  –1 Answer: The solution set is  x | x  –1 or x  3 .

Graph y = |x| + 1. Identify the domain and range. Create a table of values. x|x| + 1 –34 –23 – The domain is all real numbers. The range is {y | y ≥ 1}.

A.y = |x| – 1 B.y = |x – 1| – 1 C.y = |x – 1| D.y = |x + 1| – 1 Identify the function shown by the graph.

(x, y) = (0, 0) Original inequality True Shade the region that contains (0, 0). Since the inequality symbol is ≥, the graph of the related equation y = |x| – 2 is solid. Graph the equation. Test (0, 0).

|x – y| > 5 x – y > 5 or x – y < -5 x – 5 > y or x + 5 < y Graph y x + 5 Shade both regions (not intersection)

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