Lesson 3.5 Graphing Using Slope-Intercept Form Essential Question: How do you graph a linear equation using the slope intercept form? 10-13-14 Warm-up:

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Lesson 3.5 Graphing Using Slope-Intercept Form Essential Question: How do you graph a linear equation using the slope intercept form? 10-13-14 Warm-up: Find the slope of the line that passes through the points. (1, 2) and (-2,3) Identify the x and y-intercept of the line with the given equation. 10x – 5y = 30 Common Core CC.9-12.F.IF.6 Graph linear and quadratic functions and show intercepts, maxima, and minima.

Find the Slope and y-intercept of a Line Words: A linear equation of the form y = mx + b is written in slope-intercept from where m is the slope and b is the y-intercept of the equation’s graph. Symbols y = mx + b slope y-intercept

Slope-Intercept Form y-intercept = b which stands for the beginning Use these tricks to help you: y-intercept = b which stands for the beginning slope = m which stands for the move

EXAMPLE 1 Identify slope and y-intercept Identify the slope and y-intercept of the line with the given equation. y = 3x + 4 1. 3x + y = 2 2. SOLUTION The equation is in the form y = mx + b. So, the slope of the line is 3, and the y-intercept is 4. a. b. Rewrite the equation in slope-intercept form by solving for y.

y = –3x + 2 3x + y = 2 Write original equation. EXAMPLE 1 Identify slope and y-intercept 3x + y = 2 Write original equation. y = –3x + 2 Subtract 3x from each side. ANSWER The line has a slope of –3 and a y-intercept of 2.

EXAMPLE 1 GUIDED PRACTICE Identify slope and y-intercept for Example 1 Identify the slope and y-intercept of the line with the given equation. y = 5x – 3 1. ANSWER 5, –3

EXAMPLE 1 GUIDED PRACTICE Identify slope and y-intercept for Example 1 Identify the slope and y-intercept of the line with the given equation. 3x – 3y = 12 2. ANSWER 1, –4

EXAMPLE 1 GUIDED PRACTICE Identify slope and y-intercept for Example 1 Identify the slope and y-intercept of the line with the given equation. x + 4y = 6 3. ANSWER 4 1  , 2

Graph the equation 2x + y = 3. EXAMPLE 2 Graph an equation using slope-intercept form Graph the equation 2x + y = 3. SOLUTION STEP 1 Rewrite the equation in slope-intercept form. y –2x + 3 = Identify the slope and the y-intercept. STEP 2 = –2 m and = 3 b

EXAMPLE 2 Graph an equation using slope-intercept form STEP 3 Plot the point that corresponds to the y-intercept, (0, 3). STEP 4 Use the slope to locate a second point on the line. Draw a line through the two points.

EXAMPLE 3 Change slopes of lines ESCALATORS To get from one floor to another at a library, you can take either the stairs or the escalator. You can climb stairs at a rate of 1.75 feet per second, and the escalator rises at a rate of 2 feet per second. You have to travel a vertical distance of 28 feet. The equations model the vertical distance d (in feet) you have left to travel after t seconds. Stairs: d = –1.75t + 28 Escalator: d = –2t + 28

EXAMPLE 3 Change slopes of lines a. Graph the equations in the same coordinate plane. b. How much time do you save by taking the escalator? SOLUTION a. Draw the graph of d = –1.75t + 28 using the fact that the d-intercept is 28 and the slope is –1.75. Similarly, draw the graph of d = –2t + 28. The graphs make sense only in the first quadrant.

EXAMPLE 3 Change slopes of lines The equation d = –1.75t + 28 has a t-intercept of 16. The equation d = –2t + 28 has a t-intercept of 14. So, you save 16 – 14 = 2 seconds by taking the escalator. b.

4. Graph the equation y = –2x + 5. EXAMPLE 2 GUIDED PRACTICE Graph an equation using slope-intercept form for Examples 2 and 3 4. Graph the equation y = –2x + 5. ANSWER

WHAT IF? In Example 3, suppose a person can GUIDED PRACTICE Graph an equation using slope-intercept form for Examples 2 and 3 WHAT IF? In Example 3, suppose a person can climb stairs at a rate of 1.4 feet second. How much time does taking the escalator save? 5. ANSWER 6 sec

Graph both equations in the same coordinate plane. EXAMPLE 4 Change intercepts of lines TELEVISION A company produced two 30 second commercials, one for $300,000 and the second for $400,000. Each airing of either commercial on a particular station costs $150,000. The cost C (in thousands of dollars) to produce the first commercial and air it n times is given by C = 150n + 300. The cost to produce the second and air it n times is given by C = 150n + 400. a. Graph both equations in the same coordinate plane.

EXAMPLE 4 Change intercepts of lines b. Based on the graphs, what is the difference of the costs to produce each commercial and air it 2 times? 4 times? What do you notice about the differences of the costs? SOLUTION a. The graphs of the equations are shown.

EXAMPLE 4 Change intercepts of lines b. You can see that the vertical distance between the lines is $100,000 when n = 2 and n = 4. The difference of the costs is $100,000 no matter how many times the commercials are aired.

Line a and line c have the same slope, so they are parallel. EXAMPLE 5 Identify parallel lines Determine which of the lines are parallel. Find the slope of each line. –1 – 0 –1 – 2 = –1 –3 1 3 = Line a: m = –3 – (–1 ) 0 – 5 –2 –5 = 2 5 = Line b: m = –5 – (–3) –2 – 4 –2 –6 = 1 3 = Line c: m = ANSWER Line a and line c have the same slope, so they are parallel.

EXAMPLE 5 GUIDED PRACTICE Identify parallel lines for Examples 4 and 5 6. WHAT IF? In Example 4, suppose that the cost of producing and airing a third commercial is given by C = 150n + 200. Graph the equation. Find the difference of the costs of the second commercial and the third. ANSWER 200,000

EXAMPLE 5 GUIDED PRACTICE Identify parallel lines for Examples 4 and 5 7. Determine which lines are parallel: line a through (1, 2) and (3, 4); line b through (3, 4) and (5, 8); line c through (9, 2) and (1, 2). ANSWER a and c

Classwork/Homework 3.5 Exercises 2-44 even pages 185-187