Electrochemistry Lesson 5 Balancing Redox Reactions

Balancing Redox Full Reactions in Acid Solution MnO C 2 O 4 2- →MnO 2 + CO 3 2- MnO 4 - → MnO 2 C 2 O 4 2- → CO MnO C 2 O H 2 O + 8H + → 2MnO 2 + 6CO H + + 4H 2 O 2MnO C 2 O H 2 O → 2MnO 2 + 6CO H + 1.Separate into half reactions2.Balance each half reaction 3.Add the two half reactions4.Simplify 5.Check + 4H + + 3e - + 2H 2 O2(2( 3(3( + 2e - + 4H + ) 2 ) -8 24

Balancing Redox Full Reactions in Basic Solution 2MnO C 2 O H 2 O → 2MnO 2 + 6CO H + 1.Balance in acid solution2.Add OH - to neutralize the H + 4OH - 4H 2 O2

Balancing Redox Full Reactions in Basic Solution 2MnO C 2 O → 2MnO 2 + 6CO OH - 2H 2 O

Balancing Redox Full Reactions in Acid Solution Fe+O 2 → H 2 O+Fe(OH) 3 Fe +→+ Fe(OH) 3 O 2 → H 2 0 4Fe + 12H 2 O + 3O 2 +12H + → 12H + + 4Fe(OH) 3 + 6H 2 O 4Fe + 6H 2 O + 3O 2 → 4Fe(OH) 3 3H 2 O3H + + 3e - ) + H 2 O)+4H + 4e - + 3( 4(4( 00 6

Balance the redox reaction As→H 2 AsO 4 - +AsH 3 (alkaline) You must separate into two half reactions!This is called a Disproportionation reaction ( same reactant gets reduced and ozidized) 3As + 12H 2 O + 15H + + 5As → 3H 2 AsO H + + 5AsH 3 8As + 12H 2 O → 3H 2 AsO H + + 5AsH 3 3OH - 3OH - + 8As + 9H 2 O → 3H 2 AsO AsH 3-3 As H 2 AsO 4 - AsH 3 + 4H 2 O+6H + + 5e - 3H e - 3(3( ) 5(5( ) → → 3

Balance the redox reaction IPO 4 - →IO 3 - +I 2 + PO 4 3- (alkaline) You must separate into two half reactions!

Balance the redox reaction IPO 4 - →IO 3 - +I 2 + PO 4 3- (alkaline) You must separate into two half reactions! IPO 4 - → + PO 4 3-

Balance the redox reaction IPO 4 - →IO 3 - +I 2 + PO 4 3- (alkaline) You must separate into two half reactions!(another Disproportionation) IPO 4 - → + PO 4 3-

Balance the redox reaction IPO 4 - →IO 3 - +I 2 + PO 4 3- (alkaline) You must separate into two half reactions! IPO 4 - → IO PO 4 3- IPO 4 - → I 2 + PO 4 3-

Balance the redox reaction IPO 4 - →IO 3 - +I 2 + PO 4 3- (alkaline) You must separate into two half reactions! IPO 4 - → IO PO IPO 4 - → I 2 + 2PO 4 3-

Balance the redox reaction IPO 4 - →IO 3 - +I 2 + PO 4 3- (alkaline) You must separate into two half reactions! IPO H 2 O → IO PO H + 2IPO 4 - → I 2 + 2PO 4 3-

Balance the redox reaction IPO 4 - →IO 3 - +I 2 + PO 4 3- (alkaline) You must separate into two half reactions! IPO H 2 O → IO PO H + + 3e - 2IPO e - → I 2 + 2PO 4 3-

Balance the redox reaction IPO 4 - →IO 3 - +I 2 + PO 4 3- (alkaline) You must separate into two half reactions! 4(IPO H 2 O → IO PO H + + 3e - ) 3(2IPO e - → I 2 + 2PO 4 3- ) Continue…

Continue: Balance the redox reaction IPO 4 - →IO 3 - +I 2 + PO 4 3- (alkaline) You must separate into two half reactions! 4(IPO H 2 O → IO PO H + + 3e - ) 3(2IPO e - → I 2 + 2PO 4 3- ) 12H 2 O + 10IPO 4 - → 3I PO H + + 4IO OH - 24OH IPO 4 - → 3I PO IO H 2 O-34

Homework Page207 Exercise#24 do 5 acidic redox equations and 5 basic redox equations.