EE HomePage.com Powerpoint Symbol Collection Copyright 2008 by EE HomePage.com These symbols may be freely reused. boolean functions op amp or comparator comparator with hysteresis invertersbuffers Type D Flip-Flops register transparent latch Logic Elements connection point DQ QB RSTB DQ QB RSTB SET DQ G DQ QB EN RSTB DQ QB SET DQ QB EN RSTB DQ QB EN SET All symbols are drawn with 1.5 pt lines. Grid spacing is 0.1 inches.

SR Latch RQ QBS SR Latch SR NAND Latch SRAction 00Keep state 01Q=0 QB=1 10Q=1 QB=0 11Q=0 QB=0 SBRBAction 00Q=1 QB=1 01Q=1 QB=0 10Q=0 QB=1 11Keep state Gated SR Latch ENAction 0Keep state 1same as SR latch EE HomePage.com Powerpoint Symbol Collection Logic Elements Copyright 2008 by EE HomePage.com These symbols may be freely reused. JKNext Value 00No Change 01Q=0 10Q=1 11Toggle JK Flip Flop connection point R S Q QB SB RB Q QB SBQ QBRB S R Q QB EN SQ QBR EN JQ QB RSTB SET K  X

EE HomePage.com Powerpoint Symbol Collection Copyright 2008 by EE HomePage.com These symbols may be freely reused. bridge rectifier Semiconductors PNPNPN photo Transistor P-channel N-channel transmission gate connection point D LED SCR ZENER D G S D S G D T2 T1 G Triac

EE HomePage.com Powerpoint Symbol Collection Copyright 2008 by EE HomePage.com These symbols may be freely reused. inductors SPKR polarized capacitor unpolarized capacitor power & ground symbols switches connection point Input Output BiDi connectors crystal Discrete Components current source voltage source signal source variable resistor fixed resistor potentiometer battery varistor SPST SPDT DPST mechanical ground VDDA VDD antenna microphone L xtal C + - C L + - V + - R RR C motor 3  motor

SINGLE POLE / SINGLE THROW (NC) SPST SINGLE POLE / DOUBLE THROW SPDT DOUBLE POLE/SINGLE THROW DPST SINGLE POLE / SINGLE THROW (NO) SPST DOUBLE POLE/DOUBLE THROW DPDT

ROTARY SWITCH STACKED ROTARY SWITCHES NORMALY CLOSED PUSH BUTTON SWITCH (NC) NORMALY OPEN PUSH BUTTON SWITCH (NO) TWO POLE NORMALY OPEN PUSH BUTTON SWITCHES

─ + ─ + ─ + ─ + ─ + ─ + CHASSIS

Kv R = _______ v CURRENT = 110  60 W V R = _______ 1.2 A kV R = _______ 2.7 mA mA 1.5 k  V = _______ I = ______  60 V  I = ______ 60 V A V = _______ 66 

 V = ______ k  R T = _______ 2.5 k  750  450   R T = _______ 65.5  50  72.5  + - R = _______ 60 V A 2 A  65 V 2.5 A E = 70 V

R 2 65  + - R 2 30  R 1 20  R 4 15  + - R k  R 3 = ______ R 1 1 k  + - R T = 10.8 M  R 1 40  R  R M  950 k  2.5 M  R R T = 6.55 M  E = 48V 25 mA R 3 10  E = 48 V + - R k  R 3 = ______ R 1 1 M  R k  E = 24V 25 mA + - R L R  5 V R 1 1 M 

+ - R k  R  R  I = _______ + - R 1 35  R 3 10  R 1 15  E = _______ 500 mA + - R 1 33  R 3 10  R 2 22  E = 230 V I =.133 P 1 = P 2 = P 3 = P T = V R1 = V R2 = V R3 = P T = _______ P T = ________ E = 800 V R T = R 1 20  R 3 R 2 30  E = 120 V 1.5 A R B1 = ______ R B2 = ______ R T = _______ I B1 = _______ I B2 = _______ I T = _______ V R3 = _______ V R4 = _______ P B1 = _______ P B2 = _______ P T = _______

+ - R 1 = 33  E T = 121 V V A to GROUND = ________ A I T = ________ R 2 = 65  R 3 = 12  + - I R1 = 150 mA I R2 = 100 mA I R2 = 1.2 A R1R1 R2R2 R3R3 I T = ______ + - R 1 50  R 2 25  R  R  E = 125 V B1B1 B2B2 B 1 R = ______ B 2 R = ______ I T = ______ + - R 1 50  R 2 25  R  R  E = 125 V B1B1 B2B2 B 1 R = ______ B 2 R = ______ I T = ______

+ - R 1 70  R 2 40  R  R  E = 225 V A B R B1 = R B2 = R T = R 1 20  R 2 20  R 4 40  E = 160 V R B1 & B2 = ______ R T = ______ I T = ______ R 3 20  R  I T = 1.65 B1B1 P B1 = ______ B2B2 + - R  R  R  R  E = 12 V A B + - R 1 8  R 2 6  R 5 6  R 6 4  E = 15 V A C R 3 2  R 4 4  B R 4 5  R 

+ - R 1 20  R 2 20  R 4 40  E = 170 V R B1 & B2 = R T = I B1 = 1.45 R 3 20  R 5 25  B1B1 P B1 = P B2 = B2B2 I B2 =.723 I T = 2.17 V B1 & B2 = V R5 = V R4 = 86.8 P R4 = P R5 = P T = Answer = _________ + - R 1 25  R 2 10  R 4 6  E = 24 V R 3 10  R 5 10  B1B1 B2B2 A + - R 2 15  R 3 10  R 1 15  E = 45 V R 4 10  AA

+ - R  E = 90 V R  R  B1B1 R  R  B R  B2B2 B3B3 R 1 90  R  R 4 50  R 6 25  R 2 90  R 5 66   A  R 7 25 

+ - R  E = 220 V R  R  R  R  B2B2 A B1B1 R 4 60 

+ - R 1 50  E = 75 V B1B1 R 2 65  R 3 25  R 4 80  R  R  B2B2

+ - R  R  R  E = 90 V I R1 =.692 I R3 =.6 I R2 = 1.2 I T = 2.49 P R1 = P R3 = 108 P R2 = 216 P T = R k  R k  R 5 2 k  E = 150 V R k  R k  B1B1 B2B2 B3B3 I B1 = _____ R B1 = _____ V R1 = _____P R1 = _____ I B2 = _____R B2 = _____V R2 = _____P R2 = _____ I B3 = _____R T = _____V R3 = _____P R3 = _____ I T = _____V R4 = _____P R4 = _____ P R5 = _____ P T = _____ R T = R  R  R 3 85  E = 480 V R T = _______

I T =.0489 I B1 =.0307 R B1 = 1950 V R1 = 36.84P R1 = 1.13 I B2 = R B2 = 3300 V R2 = P R2 =.707 R T = V R3 = P R3 =.595 V R4 = 27.7 P R4 =.5036 P T = R  R  E = 240 V R  R  B1B1 B2B R 1 20  R  E = 13 V R 2 12  R  B1B1 B2B2 R 3 15 

+ - R 2 80  R  R  E = 120 V I B1 = _____ R  R  I T = _____ B1B1 B2B2 B3B3 R B1 & B2 & B3 = _____ R T = _____ V R1 = _____V B1 & B2 & B3 = _____ I B2 = _____I B3 = _____ P R1 = _____P R3 = _____P R5 = _____ P R2 = _____P R4 = _____P T = _____

+ - R  R  R  E = 90 V R  B1B1 B2B2 B3B3 I B1 =.9 I T = 1.6 R T = I B2 =.45 I B3 =.25 P R1 = 81 P R3 = P R2 = 40.5 P R4 = P T = 144 V R3 = 27.5 V R4 = 62.5

+ - R 1 65  R 2 95  R  R T = _____ R  R  + - R M  R k  R T = _____ + - R  I T = 2.2 A E = 110 V R 2 _______ + - R  R 2  R T = _____ R 3 30  E = 110 V

V L = _______ R L CHANGES FROM 1.5 k  to 4.5 k  I S = 10 mA I R1 = _______ R 1 25  I S = 125 mA R  I R2 = _______ E T = _______ R k  I S = 160 mA R2R2 + - E 60 v RLRL I S = 10 mA V RL = I S x R L

I 2 = 8 A I T = 12 AI 1 = 4 A I 1 = 10 AI 4 = 4 A I 2 = 2 A I T entering = = 12 A I 3 = 8 A I T leaving = = 12 A

10 mh X L = 314  3 mh 110 V 10 kHz 10 mh 2 mh

10 mh X L = 314  L1 3.3 mh L2 2.5 mh R1 15  V kHz L1 2.2 mh R1 250  V1 120 V 50 kHz 1 A

10 mh X L = 314  L1 5 mh L2 2 mh R1 10  V1 1.5 kHz.75 A L1 250 µh R1 1 k  V1 60 V 150 kHz L2 125 µh

10 mh X L = 314  3 mh 110 V 10 kHz L1 50 µh 2 mh R1 5  V1 10 kHz.31 A

L C 10 mh.5 µF 1 k  110 V 10 kHz X L = 314  X C = 637  15 µF 25 µF 90 µF 60 Hz

L 10 mh.5 µF R1 120  60 V 400 Hz X L = 314  X C = 637  C1 5 µ 

ELECTRON PROTON NUCLEUS NEUTRON 0 CHARGE

VOLTAGE CURRENT RESISTANCE CARBON FILM (RESISTOR)SPIRAL SUBSTRATE CONNECTING LEADS INSULATING MATERIAL CARBON COMPOSITE (RESISTOR)

Power Question: How much power is being consumed in the circuit? I = 3.5 A 18 V

P E

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