Fundamentals of Cellular Communications and Networks Akram Bin Sediq and Halim Yanikomeroglu SYSC 4700.

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Presentation transcript:

Fundamentals of Cellular Communications and Networks Akram Bin Sediq and Halim Yanikomeroglu SYSC 4700

Objectives To learn some fundamental concepts in cellular communications such as Channel reuse Clustering Cell-splitting Sectoring Interference Duplexing Heterogeneous cellular network

Wireless access – Through access points (base stations), coupled to the wire network – Attain coverage with minimum infrastructure cost Put as few base stations as possible

– Problem: Number of channels << number of active users! – Example: # of users (subscribers) = 200,000 Percentage of active users = 5% # number of active users = 10,000 BW leased = 10 MHz BW required per user = 25 KHz – 400 << 10,000 !!! – How can you service 10,000 users with only 400 channels???? – Answer: Reuse the channels (radio resources) Channel reuse (1/2) # available channels = 10 MHz/ 25 KHz = 400

Channel reuse (2/2) – Channel (frequency, time, code, hybrid) reuse -> cellular concept – 10,000 active usersreuse the channels 400 channels 25 times! – Cluster: The area in which all the channels are used only once.

Problems with channel reuse – Problem: if two users in adjacent clusters use the same channel i (one channel out of 400), then there will be excessive multiple access interference! – Multiple access interference: inevitable in cellular systems, but should be regulated – Control and management of multiple access interference: Radio resource management (RRM) Optimization of assignment problems – BS/AP assignment – Power assignment – Channel assignment

Regulating channel assignment (1/2) – Divide each cluster into cells (cell: area served by one base station) 4 cells/ cluster Cluster size: N=4 A: ch 1 to 100 B: ch 101 to 200 C: ch 201 to 300 D: ch 301 to 400

Regulating channel assignment (2/2) – Cluster size N N↑ → co-channel interference (CCI) ↓ N↑ → capacity/cell decreases – Example (400 channels per cluster): ABAB CDCD ABAB CDCD ABAB ABAB ABAB ABAB Cluster size: N=4 # channels per cell = 100 Cluster size: N=2 # channels per cell = 200

Cluster size and Quality of Service (1/2) – Example: Signal to Interference Ratio (SIR) calculation (N=4) Both users in Cell A and Cell A’ use the same transmit power P t Uplink with

Cluster size and Quality of Service (2/2) – Example: SIR calculation (N=9) - Example: # cells =100, # channels = k N=4 -> total capacity = # clusters * k = (100/4) k = 25k N=5 -> total capacity = # clusters * k = (100/5) k = 20 k N↑ → co-channel interference↓ → QoS ↑ But for the same number of Base stations, N↑ → # clusters ↓ → capacity ↓

Increased user demand – Demand ↑ → more reuse → # clusters ↑ – If cluster size remains the same → more cells in the same area → Cell splitting

Mobility – Handoff

Coverage region of a base station – Propagation on a flat terrain (no shadowing) – With shadowing – Non-uniform demand

Hexagonal layout

Sectoring Use directional antenna to reduce co-channel interference, thus we can use small cluster size → increase capacity Wireless Communications: Principles and Practice, 2 nd Edition by T.S. Rappaport 120 degree antennas are the most popular Better SIR, More capacity But More handoff More antennas and their RF’s parts

Duplexing Uplink (reverse link) and downlink (forward link) Frequency division duplexing (FDD): Time division duplexing (FDD):

Interference

Heterogeneous cellular network Het-Net Relay CoMP Source: Huawei

Question Goal: To provide a cellular voice service to a town using 20 MHz of bandwidth; each user requires 20 kHz of bandwidth for voice communications. a.How many users can be supported concurrently, using a single high power transmitter to cover the whole town? 20 MHz / 20 KHz = 1,000 users b.How many users can be supported concurrently, using a cellular topology with 20 base stations and a cluster size of 4? Divide the 20 MHz BW into 4 sets and assign one set to each cell Each cell has a BW of 20 (MHz/cluster) / 4 (cells/cluster) = 5 MHz/cell # of users per cell = 5 (MHz/cell) / 20 (kHz/user) = 250 users/cell The total number of users = 250 users/cell * 20 cells = 5,000 users