 Start with the coefficient of 5x 3 y 2.  Cube your result.  Add the digits of your answer together.  Take the cube root of your answer.  Add the sum of the exponents in 6ab 2.

 14-3 Worksheet (odd problems)  Page – 21 (odd)

A.0.1 B.0.2 C.0.25 D.0.3 The probability distribution shows the probabilities of different types of weather occurring on a particular day. Ariana’s soccer game will be canceled if there is rain or snow. What’s the probability that the game will be cancelled?

 Maximum occurs at the mean.  Mean, Median and Mode are equal  Population mean and Standard Deviation can be used to determine probabilities Since the histogram is high on the right and low on the left, the data are negatively skewed.

A normal distribution of data has a mean of 66 and standard deviation of 11. Find the probability that random value x is less than 44, that is P(x < 44). µ = 66 and  = 11 µ – 2 , that is 66 – 2(11) or 44 Answer: P(x < 44) = 2.5%

 A. PACKAGING Students counted the number of candies in 100 small packages. They found that the number of candies per package was normally distributed, with a mean of 23 candies per package and a standard deviation of 1 piece of candy. About how many packages had between 22 and 24 candies? About 68 packages contained between 22 and 24 pieces. B. What is the probability that a package selected at random had more than 25 candies? The probability that a package selected at random had more than 25 candies is about 2.5%.

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The Interquartile Range is the difference between the upper quartile and lower quartile. In this example, the interquartile range is = 7

 You can use also calculate this using your TI-84 calculator. Place the data into L1 using STATS, EDIT function. Then analyze the data using STATS, CALC, 1: 1-Var Stats. The first screen (at left) gives = Mean (average) and = Standard Deviation. The second screen provides the Med = Median, Q1 = lower quartile value, and Q3 = upper quartile value.  So, using the TI-84 calculator, you can quickly find the interquartile range by using Q3 – Q1. In this example 11 – 4 = 7.

 The following represents the body temperatures of healthy students Find the average temperature. (tenths) (98.37) 2. Find the standard deviation. (tenths) (0.96) 3. What percent of the students have a temperature below ? (97.5) 4. What percentage is between and 99.33? (81.5)

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