LecturePLUS Timberlake1 Atoms and Elements The Atom Atomic Number/Mass Number/ Isotopes

LecturePLUS Timberlake3 Subatomic Particles ParticleSymbol Charge Relative Mass (amu*) (*amu- atomic mass unit*) Electron e Proton p Neutron n0 1

LecturePLUS Timberlake4 Location of Subatomic Particles cm electrons protons neutrons cm nucleus

LecturePLUS Timberlake6 Atomic Number The # of protons (identifies the atom)

LecturePLUS Timberlake7 Atomic Number on the Periodic Table 11 Na Atomic Number Symbol

LecturePLUS Timberlake8 All atoms of an element have the same number of protons 11 Na 11 protons Sodium

LecturePLUS Timberlake10 Learning Check State the number of protons for atoms of each of the following: A. Nitrogen 1) 5 protons 2) 7 protons 3) 14 protons B. Sulfur 1) 32 protons 2) 16 protons 3) 6 protons C. Barium 1) 137 protons 2) 81 protons 3) 56 protons

LecturePLUS Timberlake11 Solution State the number of protons for atoms of each of the following: A. Nitrogen 2) 7 protons B. Sulfur 2) 16 protons C. Barium 3) 56 protons

LecturePLUS Timberlake12 Number of Electrons An atom is neutral The net charge is zero # of protons = # of electrons Atomic # = # of electrons

LecturePLUS Timberlake13 Mass Number Mass # = #protons + #neutrons # n = mass# - p #p = mass# - n

LecturePLUS Timberlake14 Atomic Symbols Show the mass number and atomic number Give the symbol of the element mass number 23 Na sodium-23 atomic number 11

Other ways to write elements: ClCl-36 Atomic Number Mass Number

LecturePLUS Timberlake16 Subatomic Particles in Some Atoms O P Zn p + 15 p + 30 p + 8 n16 n35 n 8 e - 15 e - 30 e -

LecturePLUS Timberlake17 Isotopes Atoms with the same number of protons, but different numbers of neutrons. Atoms of the same element (same atomic number) with different mass numbers Isotopes of chlorine 35 Cl 37 Cl17 chlorine - 35 chlorine - 37

LecturePLUS Timberlake18 Learning Check Naturally occurring carbon consists of three isotopes, 12 C, 13 C, and 14 C. State the number of protons, neutrons, and electrons in each of these carbon atoms. 12 C 13 C 14 C #p _______ _______ _______ #n _______ _______ _______ #e _______ _______ _______

LecturePLUS Timberlake19 Solution 12 C 13 C 14 C #p #n #e 6 6 6

LecturePLUS Timberlake20 Learning Check An atom of zinc has a mass number of 65. A.Number of protons in the zinc atom 1) 302) 353) 65 B.Number of neutrons in the zinc atom 1) 302) 353) 65 C. What is the mass number of a zinc isotope with 37 neutrons? 1) 372) 653) 67

LecturePLUS Timberlake21 Solution An atom of zinc has a mass number of 65. A.Number of protons in the zinc atom 1) 30 B.Number of neutrons in the zinc atom 2) 35 C. What is the mass number of a zinc isotope with 37 neutrons? 3) 67

LecturePLUS Timberlake22 Learning Check Write the atomic symbols for ios with the following: (Change your paper to reflect below) A. 8 p +, 8 n, 8 e - ___________ B.17p +, 20n, 17e - ___________ C. 47p +, 60 n, 47 e - ___________

LecturePLUS Timberlake23 Solution 16 O A. 8 p +, 8 n, 10 e - 8 B.17p +, 20n, 17e - 37 Cl 17 C. 47p +, 60 n, 47 e Ag 47

Ions Ions – atoms with a different number of protons and electrons. Electrons can be added or removed without changing the element. Adding e -s creates a negative ion Removing e -s creates a positive ion

Calculating the charge of an ion To calculate the charge of an ion: Add protons and electrons just like adding positive and negative integers. Sulfur with 16 protons and 18 electrons has a net charge of (+16) + (-18) = -2 and is written as: S -2

Calculating the charge of an ion Calcium with 20 protons and 18electrons has a net charge of (+20) + (-18) = +2 and is written as Ca +2

LecturePLUS Timberlake27 Atomic Mass on the Periodic Table 11 Na Atomic Number Symbol Atomic Mass

LecturePLUS Timberlake28 Atomic Mass Atomic mass is the weighted average mass of all the atomic masses of the isotopes of that atom. Each isotope exists naturally at a certain % abundance.

LecturePLUS Timberlake29 For Example Chlorine exists naturally as about 75.5 % Cl-35 and 24.5% Cl-37. This is called its % abundance.

Calculate Average Atomic Mass: Multiply the mass # by its % abundance in decimal form for each isotope then add. 35 x = 26.4 =35.5amu 37 x = 9.07

LecturePLUS Timberlake31 Credits: worldofteaching.org