Common Core Standards Covered in this lesson: HSA-CED.A.2 --Create equations in two or more variables to represent relationships between quantities 8.F.A.3.

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Presentation transcript:

Common Core Standards Covered in this lesson: HSA-CED.A.2 --Create equations in two or more variables to represent relationships between quantities 8.F.A.3 Interpret the equation y=mx + b as defining a linear function, whose graph is a straight line

1) Write an equation of a line in slope- intercept form that passes through the point (1, -2) and has a slope of 3.

Point Slope Form Equation: y – y 1 = m(x – x 1 ) Where m is the slope x 1 and y 1 are a point on the line Slope Intercept Form: y = mx + b Where m is the slope b is your y-intercept y – (-2) = 3(x – 1) y + 2 = 3x – 3 y = 3x – 5  y = 3x – 5  SLOPE INTERCEPT FORM

2. Find the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2).

 FIND SLOPE FIRST

2. Find the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2).  Slope = -7  Select a point (you may pick either point you used to find the slope with) Let’s choose (-4, 5)

2. Find the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2).  Now we have a slope (-7) and a point (-4, 5). Put equation in point slope form!

2. Find the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2).  y – 5 = -7(x + 4)  Solve for y to get into slope- intercept form

2. Find the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2).  y – 5 = -7(x + 4) y – 5 = -7x – 28 y = - 7x – 23 y = - 7x – 23

y = - 7x – 23 This is the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2)