DC Series Circuits Solving circuits step by step.

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Presentation transcript:

DC Series Circuits Solving circuits step by step

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  RT = R1 + R2 + R3 12K +22K +15K 49K Ohms

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V ? I = E / R I = 48 / 49K 48 / =

Wait a minute! What in tarnation is ? Move three places to the right and you have m That is still smaller than one. Move three more to the right,  Round to three places and we have 980  I = Amps, or 980  A

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V ? I = E / R I = 48 / 49K 48 / = 980  A Amps

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A Since current is the same in all parts of a series circuit:

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A E = I x R E = x Cancel three places left and right of the decimal, leaving 12 x = The answer is 11.76, rounded off = 11.8 Volts

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A E = I x R E = x Cancel three places left and right of the decimal, leaving 22 x = V The answer is 21.56, rounded off = 21.6

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A E = I x R E = x Cancel three places left and right of the decimal, leaving 15 x = V The answer is 14.7, rounded off = V 14.7V Double-check Add volts = 48.1

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A 11.8V 21.6V 14.7V P IE P = I x E P = x 11.8 P = , or11.6 m Watts

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A 11.8V 21.6V 14.7V P IE P = I x E P = x 21.6 P = , or21.2 m 11.6 mW

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A 11.8V 21.6V 14.7V P IE P = I x E P = x 14.7 P = , or14.4 m 11.6 mW 21.2 mW

R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A 11.8V 21.6V 14.7V P IE P = I x E P = x 48 P = , or47.0 m 11.6 mW 21.2 mW 14.4 mW Double-check = mW