3.2 WARM - UP Solve the system graphically. 4x – 2y = -8 x + y = 1 –5–4–3–2–112543 –5 –4 –3 –2 –1 1 2 5 4 3 4x – 2y = -8 -4x -2y = -4x – 8 y = 2x + 4 x.

Slides:



Advertisements
Similar presentations
Chapter 3: Systems of Linear Equations and Inequalities.
Advertisements

+ Water wars An enemy submarine has launched a missile toward another submarine in your fleet following the path 2x-y=4. Your submarine retaliates launching.
3-6 Solving Systems of Linear Equations in Three Variables Objective: CA 2.0: Students solve systems of linear equations and inequalities in three variables.
Solving a System of Equations by ELIMINATION. Elimination Solving systems by Elimination: 1.Line up like terms in standard form x + y = # (you may have.
3.5 Solving systems of equations in 3 variables
Algebra II w/ trig. Substitution Method: 1. Solve an equation for x or y 2. Substitute your result from step 1 into the other equation and solve for the.
Thinking Mathematically Algebra: Graphs, Functions and Linear Systems 7.3 Systems of Linear Equations In Two Variables.
7.1 SOLVING SYSTEMS BY GRAPHING The students will be able to: Identify solutions of linear equations in two variables. Solve systems of linear equations.
Solving Linear Systems by Linear Combinations
Algebra 1 Notes Lesson 7-2 Substitution. Mathematics Standards -Patterns, Functions and Algebra: Solve real- world problems that can be modeled using.
ALGEBRA II SOLUTIONS OF SYSTEMS OF LINEAR EQUATIONS.
3.2 Solving Systems Algebraically
Unit 1.3 USE YOUR CALCULATOR!!!.
3x – 5y = 11 x = 3y + 1 Do Now. Homework Solutions 2)2x – 2y = – 6 y = – 2x 2x – 2(– 2x) = – 6 2x + 4x = – 6 6x = – 6 x = – 1y = – 2x y = – 2(– 1) y =
Do Now 1/13/12  In your notebook, list the possible ways to solve a linear system. Then solve the following systems. 5x + 6y = 50 -x + 6y = 26 -8y + 6x.
Integrated Math 2 Lesson #7 Systems of Equations - Elimination Mrs. Goodman.
Ants, Freeways, & Other Systems. Solving linear Systems Algebraically State Standard – 2.0 Students solve systems of linear equations and.
Goal: Solve a system of linear equations in two variables by the linear combination method.
SOLVING SYSTEMS ALGEBRAICALLY SECTION 3-2. SOLVING BY SUBSTITUTION 1) 3x + 4y = 12 STEP 1 : SOLVE ONE EQUATION FOR ONE OF THE VARIABLES 2) 2x + y = 10.
Warm-Up Exercises Solve the system by substitution. 2x2x y = – 1. 3x3x – y – = 1 4x+y = 2. 72x2x+3y3y = – ANSWER () 1, 2 – ANSWER () 1, 3.
3-2 Solving Linear Systems Algebraically day 2 Objective: CA 2.0: Students solve system of linear equations in two variables algebraically.
By looking at a graph, name the three types of solutions that you can have in a system of equations. Groupwork graded Groupwork worksheet 1-14 Work on.
Solving by Substitution Method or Elimination (Addition) Method
3-2 Solving Linear Systems Algebraically Objective: CA 2.0: Students solve system of linear equations in two variables algebraically.
7.4. 5x + 2y = 16 5x + 2y = 16 3x – 4y = 20 3x – 4y = 20 In this linear system neither variable can be eliminated by adding the equations. In this linear.
Unit 1.3 USE YOUR CALCULATOR!!! MM3A5c. Unit 1 – Algebra: Linear Systems, Matrices, & Vertex- Edge Graphs  1.3 – Solve Linear Systems Algebraically 
Do Now (3x + y) – (2x + y) 4(2x + 3y) – (8x – y)
§2.5 Model Direct Variation CA Standard 2.0 Students solve systems of linear equations and inequalities (in two or three variables) by substitution, with.
Complete the DO NOW in your packets
SystemsOfInequalities. 7-1 Solving Systems by Graphing What is a system of linear equations? “SOLUTION” No solution Infinitely Many Solutions Page 342.
WARM UP GRAPHING LINES Write the equation in slope- intercept form and then Graph. (Lesson 4.7) 1.3x + y = 1 2.x + y = 0 3.y = -4 3.
Solving Systems of Equations by Elimination. Standard and Objective A.REI.5 Prove that, given a system of two equations in two variables, replacing one.
Solving Systems by Elimination 5.4 NOTES, DATE ____________.
EXAMPLE 4 Solve linear systems with many or no solutions Solve the linear system. a.x – 2y = 4 3x – 6y = 8 b.4x – 10y = 8 – 14x + 35y = – 28 SOLUTION a.
3.3 Solving Linear Systems by Linear Combination 10/12/12.
Algebra Review. Systems of Equations Review: Substitution Linear Combination 2 Methods to Solve:
TODAY IN ALGEBRA 2.0…  Review: Solving Linear Systems by Graphing  Learning Goal 1: 3.2 Solving Linear Systems by Substitution with one equation solved.
3.2 Solve Linear Systems Algebraically Algebra II.
Chapter 3 Section 2. EXAMPLE 1 Use the substitution method Solve the system using the substitution method. 2x + 5y = –5 x + 3y = 3 Equation 1 Equation.
Elimination Method - Systems. Elimination Method  With the elimination method, you create like terms that add to zero.
Solving a System of Equations by ELIMINATION. Elimination Solving systems by Elimination: 1.Line up like terms in standard form x + y = # (you may have.
Ch. 3 Notes 3.1 – 3.3 and 3.6.
Use the elimination method
Algebra 2 Chapter 3 Review Sections: 3-1, 3-2 part 1 & 2, 3-3, and 3-5.
Warm Up Find the solution to linear system using the substitution method. 1) 2x = 82) x = 3y - 11 x + y = 2 2x – 5y = 33 x + y = 2 2x – 5y = 33.
6) x + 2y = 2 x – 4y = 14.
10.3 Solving Linear Systems
Solving Systems of Linear Equations in 3 Variables.
Warm-Up Graph Solve for y: Graph line #2.
Chapter 3: Linear Systems
THE SUBSTITUTION METHOD
Warm-Up 2-1.
Linear Systems Chapter 3.
Solving Linear Systems by Linear Combinations
Solving Linear Systems Algebraically
3.5 Solving systems of equations in 3 variables
Lesson 7.1 How do you solve systems of linear equations by graphing?
Solve Linear Equations by Elimination
Warm-up Solve by graphing X+Y=-2 2x-3y=-9.
Warm-up 1. Solve the system of equations 3x + 2y = 12 and x – y = – 1 graphically. 2. Solve the system. Then classify the system as consistent and independent,
Solving Systems of Linear Equations in 3 Variables.
Systems of Equations Solve by Graphing.
Section Solving Linear Systems Algebraically
Warm-up: Solve the system by any method:
Example 2B: Solving Linear Systems by Elimination
Algebra 2 Monday, October 20, 2014
Systems Warm-Up Solve each linear system. x + 7 = y -4x + 2 = y
Lesson 0 – 8 Systems of Linear Equations
Warm-Up # Is (–1, 4) a solution to
Systems of three equations with three variables are often called 3-by-3 systems. In general, to find a single solution to any system of equations,
Presentation transcript:

3.2 WARM - UP Solve the system graphically. 4x – 2y = -8 x + y = 1 –5–4–3–2– –5 –4 –3 –2 – x – 2y = -8 -4x -2y = -4x – 8 y = 2x + 4 x + y = 1 y = -x + 1 -x -x Solution: (-1, 2)

3.2 Solving Systems Algebraically State Standard – 2.0 Students solve systems of linear equations and inequalities (in two or three variables) by substitution, linear combination, with graphs, or with matrices. The Substitution Method 1) Solve one of the equations for a variable. 2) Substitute step 1 into the other equation. 3) Solve for the variable 4) Substitute the value in Step 2 into one of the original equations to get the other variable

( 1, -1 ) Extra Example 1 Solve using the Substitution method: x – 2y = 3 3x + 2y = 1 x –2y = 3 +2y x = 2y + 3 3(2y + 3) + 2y = 1 6y y = 1 8y + 9 = y = -8 y = -1 x –2(-1) = 3 x + 2 = 3 x = 1

The Elimination Method 1) Multiply one or both of the equations by a constant. 2) Add the revised equations in order to eliminate one of the variables. 3) Substitute the value in Step 2 into one of the original equations to get the other variable 3.2 Solving Systems Algebraically

(, ) Extra Example 3a Solve using the Elimination method: 2x – 4y = 13 4x – 5y = 8 -2( )2x – 4y = 13 4x – 5y = 8 -4x + 8y = -26 4x – 5y = 8 3y = -18 y = -6 2x – 4(-6) = 13 2x + 24 = x = -11 x =

(, ) Extra Example 3b Solve using the Linear Combination method: 2x + 3y = -1 -5x + 5y = 15 5( )2x + 3y = -1 -5x + 5y = 15 10x + 15y = x + 10y = 30 25y = 25 y = 1 2x + 3 (1) = -1 2x + 3 = x = -4 x = ( )

If you get the variables to cancel and you get: 0 = 0 You will have: Infinitely many solutions No solutions If you get the variables to cancel and you get: 0 = (some #) You will have:

Example 3 A caterer is planning a party for 64 people. The customer has $150 to spend. A $39 pan of pasta feeds 14 people and a $12 sandwich tray feeds 6 people. How many pans of pasta and how many sandwich trays should the caterer make? -2( )14p + 6s = 64 39p + 12s = p – 12s = p + 12s = p = 22 p = 2 14(2)+ 6s = s = s = 36 s = 6 The caterer should make 2 pans of pasta and 6 trays of sandwiches.

Guided Practice 6x + 6y = 3 4x + 4y = 2 3x – 3y = 3 -4x + y = 21 -2x + y = 13 x – 4y = -31 x – 6y = 6 -3x + 2y = -2 -5x + 7y = 10 15x – 21y = 22 -4x + 8y = 24 -x + 2y = 6

HOMEWORK Due Tomorrow: pg. 130 – 131 (1 – 13) eoo, (19 – 39) eoo, (54 – 59) all