Slide 1 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher Algebra n Learning Objectives Understand and use algebraic terms Manipulate algebraic expressions Solve simple linear equations (including transposition) Solve simultaneous linear equations (including the graphical technique) Solve business problems using simple algebra Chapter M3
Slide 2 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher n Algebra n Algebra applies quantitative concepts to unknown quantities represented by symbols. term n A term is a part of an expression that is connected to another term by a plus or minus sign. constant n A constant is a term whose value does not change. variable n A variable is a term that represents a quantity that may have different values. expression n An expression is a combination of constants and variables using arithmetic operations. Definitions
Slide 3 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher Definitions coefficient n A coefficient is a factor by which the rest of a term is multiplied. degree n The degree of expression is the highest exponent of any variable in the expression. equation n An equation is a statement that two expressions are equal.
Slide 4 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher Algebraic rules Rule: n If an expression contains like terms, these terms may be combined into a single term. Like terms are terms that differ only in their numerical coefficient. Constants may also be combined into a single constant. Example:
Slide 5 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher Algebraic rules Rule: n When an expression is contained in brackets, each term within the brackets is multiplied by any coefficient outside the brackets. Example:
Slide 6 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher Algebraic rules Rule: n To multiply one expression by another, multiply each term of one expression by each term of the other expression. The resulting expression is said to be the product of the two expressions. Example:
Slide 7 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher Rule: n Any term may be transposed from one side of an equation to the other. When the transposition is made, the sign of the term must change from its original sign. ‘+’ becomes a ‘-’ and ‘-’ becomes a ‘+’. Example: 15x - 20 = x 15x x = 12 15x + 4x = Algebraic rules
Slide 8 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher Solving linear equations Solve 9x - 27 = 4x + 3 for x 1.Place like terms of the variable on the left side of the equation and the constant terms on the right side. 9x - 4x = Collect like terms and constant terms. 5x = 30 3.Divide both sides of the equation by the coefficient of the variable (in this case 5). x = 6
Slide 9 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher Solving simultaneous equations (finding the value of two variables) Solve for x and y 3x + 4y = 33 (1) 2x - 3y = 5 (2) Step 1: Make the coefficient of either of the variables in one equation equal to its coefficient in the other equation. Multiply both sides of equation (1) by 2 and equation (2) by 3. 6x + 8y = 66 (3) 6x - 9y = 15 (4)
Slide 10 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher Solve for x and y : 3x + 4y = 33 (1) 2x - 3y = 5 (2) signs are the samesubtract equationssigns are differentadd equations. Step 2: Eliminate the variable that has the same coefficient by: subtracting equation (4) from equation (3). If the signs are the same, then subtract equations. If the signs are different, then add equations. 6x + 8y = 66 (3) minus:6x - 9y = 15 (4) equals 8y-(-9y) = 51 17y = 51 Divide both sides by 17 to find y. y = 3
Slide 11 © 2002 McGraw-Hill Australia, PPTs t/a Introductory Mathematics & Statistics for Business 4e by John S. Croucher Substitute in 3 for y in equation (1) and solve for x. 3x + 4(3) = 33 3x + 12 = 33 3x = x = 21 Divide both sides by 3. x = 7 Solve for x and y : 3x + 4y = 33 (1) 2x - 3y = 5 (2)