5–Minute Check 3 A.yes B.no Determine whether the function is continuous at x = 2.

5–Minute Check 3 A.yes B.no Determine whether the function is continuous at x = 2.

5–Minute Check 4 Describe the end behavior of f (x) = –6x 4 + 3x 3 – 17x 2 – 5x A. B. C. D.

5–Minute Check 4 Describe the end behavior of f (x) = –6x 4 + 3x 3 – 17x 2 – 5x A. B. C. D.

5–Minute Check 5 Determine between which consecutive integers the real zeros of f (x) = x 3 + x 2 – 2x + 5 are located on the interval [–4, 4]. A.–2 < x < –1 B. –3 < x < –2 C. 0 < x < 1 D. –4 < x < –3

5–Minute Check 5 Determine between which consecutive integers the real zeros of f (x) = x 3 + x 2 – 2x + 5 are located on the interval [–4, 4]. A.–2 < x < –1 B. –3 < x < –2 C. 0 < x < 1 D. –4 < x < –3

Vocabulary increasing decreasing constant maximum minimum extrema average rate of change secant line

Key Concept 1

Example 1 Analyze Increasing and Decreasing Behavior B. Use the graph of the function f (x) = –x 3 + x to estimate intervals to the nearest 0.5 unit on which the function is increasing, decreasing, or constant. Support the answer numerically.

Example 1 Analyze Increasing and Decreasing Behavior Support Numerically Create a table using x-values in each interval. Analyze Graphically From the graph, we can estimate that f is decreasing on, increasing on, and decreasing on.

Example 1 Analyze Increasing and Decreasing Behavior Answer: f (x) is decreasing on and and increasing on

Example 1 Use the graph of the function f (x) = 2x 2 + 3x – 1 to estimate intervals to the nearest 0.5 unit on which the function is increasing, decreasing, or constant. Support the answer numerically. A.f (x) is increasing on (–∞, –1) and (–1, ∞). B.f (x) is increasing on (–∞, –1) and decreasing on (–1, ∞). C.f (x) is decreasing on (–∞, –1) and increasing on (–1, ∞). D.f (x) is decreasing on (–∞, –1) and decreasing on (–1, ∞).

Example 1 Use the graph of the function f (x) = 2x 2 + 3x – 1 to estimate intervals to the nearest 0.5 unit on which the function is increasing, decreasing, or constant. Support the answer numerically. A.f (x) is increasing on (–∞, –1) and (–1, ∞). B.f (x) is increasing on (–∞, –1) and decreasing on (–1, ∞). C.f (x) is decreasing on (–∞, –1) and increasing on (–1, ∞). D.f (x) is decreasing on (–∞, –1) and decreasing on (–1, ∞).

Key Concept 2

Example 2 Estimate and Identify Extrema of a Function Estimate and classify the extrema to the nearest 0.5 unit for the graph of f (x). Support the answers numerically.

Example 2 Estimate and classify the extrema to the nearest 0.5 unit for the graph of f (x). Support the answers numerically. A.There is a relative minimum of 2 at x = –1 and a relative maximum of 1 at x = 0. There are no absolute extrema. B.There is a relative maximum of 2 at x = –1 and a relative minimum of 1 at x = 0. There are no absolute extrema. C.There is a relative maximum of 2 at x = –1 and no relative minimum. There are no absolute extrema. D.There is no relative maximum and there is a relative minimum of 1 at x = 0. There are no absolute extrema.

Example 2 Estimate and classify the extrema to the nearest 0.5 unit for the graph of f (x). Support the answers numerically. A.There is a relative minimum of 2 at x = –1 and a relative maximum of 1 at x = 0. There are no absolute extrema. B.There is a relative maximum of 2 at x = –1 and a relative minimum of 1 at x = 0. There are no absolute extrema. C.There is a relative maximum of 2 at x = –1 and no relative minimum. There are no absolute extrema. D.There is no relative maximum and there is a relative minimum of 1 at x = 0. There are no absolute extrema.

Example 3 Use a Graphing Calculator to Approximate Extrema GRAPHING CALCULATOR Approximate to the nearest hundredth the relative or absolute extrema of f (x) = x 4 – 5x 2 – 2x + 4. State the x-value(s) where they occur. f (x) = x 4 – 5x 2 – 2x + 4 Graph the function and adjust the window as needed so that all of the graph’s behavior is visible.

Example 3 Use a Graphing Calculator to Approximate Extrema Using the minimum and maximum selection from the CALC menu of your graphing calculator, you can estimate that f(x) has a relative minimum of 0.80 at x = – 1.47, an absolute minimum of –5.51 at x = 1.67, and a relative maximum of 4.20 at x = – 0.20.

Example 3 Use a Graphing Calculator to Approximate Extrema Answer: relative minimum: (–1.47, 0.80); relative maximum: (–0.20, 4.20); absolute minimum: (1.67, –5.51)

Example 3 GRAPHING CALCULATOR Approximate to the nearest hundredth the relative or absolute extrema of f (x) = x 3 + 2x 2 – x – 1. State the x-value(s) where they occur. A.relative minimum: (0.22, –1.11); relative maximum: (–1.55, 1.63) B. relative minimum: (–1.55, 1.63); relative maximum: (0.22, –1.11) C.relative minimum: (0.22, –1.11); relative maximum: none D.relative minimum: (0.22, 0); relative minimum: (–0.55, 0) relative maximum: (–1.55, 1.63)

Example 3 GRAPHING CALCULATOR Approximate to the nearest hundredth the relative or absolute extrema of f (x) = x 3 + 2x 2 – x – 1. State the x-value(s) where they occur. A.relative minimum: (0.22, –1.11); relative maximum: (–1.55, 1.63) B. relative minimum: (–1.55, 1.63); relative maximum: (0.22, –1.11) C.relative minimum: (0.22, –1.11); relative maximum: none D.relative minimum: (0.22, 0); relative minimum: (–0.55, 0) relative maximum: (–1.55, 1.63)

Example 4 Use Extrema for Optimization FUEL ECONOMY Advertisements for a new car claim that a tank of gas will take a driver and three passengers about 360 miles. After researching on the Internet, you find the function for miles per tank of gas for the car is f (x) =  0.025x x + 240, where x is the speed in miles per hour. What speed optimizes the distance the car can travel on a tank of gas? How far will the car travel at that optimum speed?

Example 4 Use Extrema for Optimization We want to maximize the distance a car can travel on a tank of gas. Graph the function f (x) = –0.025x x using a graphing calculator. Then use the maximum selection from the CALC menu to approximate the x-value that will produce the greatest value for f (x).

Example 4 Answer:The optimal speed is about 70 miles per hour. The car will travel miles when traveling at the optimum speed. Use Extrema for Optimization The graph has a maximum of for x ≈ 70. So the speed that optimizes the distance the car can travel on a tank of gas is 70 miles per hour. The distance the car travels at that speed is miles.

Example 4 VOLUME A square with side length x is cut from each corner of a rectangle with dimensions 8 inches by 12 inches. Then the figure is folded to form an open box, as shown in the diagram. Determine the length and width of the box that will allow the maximum volume. A.6.43 in. by in. B.4.86 in. by 8.86 in. C.3 in. by 7 in. D.1.57 in. by 67.6 in.

Example 4 VOLUME A square with side length x is cut from each corner of a rectangle with dimensions 8 inches by 12 inches. Then the figure is folded to form an open box, as shown in the diagram. Determine the length and width of the box that will allow the maximum volume. A.6.43 in. by in. B.4.86 in. by 8.86 in. C.3 in. by 7 in. D.1.57 in. by 67.6 in.

Key Concept3

Example 5 Find Average Rates of Change A. Find the average rate of change of f (x) = –2x 2 + 4x + 6 on the interval [–3, –1]. Use the Slope Formula to find the average rate of change of f on the interval [–3, –1]. Substitute –3 for x 1 and –1 for x 2. Evaluate f(–1) and f(–3).

Example 5 Find Average Rates of Change Simplify. Answer: The average rate of change on the interval [–3, –1] is 12. The graph of the secant line supports this conclusion.

Example 5 Find Average Rates of Change Simplify. Answer:12 The average rate of change on the interval [–3, –1] is 12. The graph of the secant line supports this conclusion.

Example 5 Find Average Rates of Change B. Find the average rate of change of f (x) = –2x 2 + 4x + 6 on the interval [2, 5]. Use the Slope Formula to find the average rate of change of f on the interval [2, 5]. Substitute 2 for x 1 and 5 for x 2. Evaluate f(5) and f(2).

Example 5 Find Average Rates of Change Simplify. Answer: The average rate of change on the interval [2, 5] is –10. The graph of the secant line supports this conclusion.

Example 5 Find Average Rates of Change Simplify. Answer:–10 The average rate of change on the interval [2, 5] is –10. The graph of the secant line supports this conclusion.

Example 5 Find the average rate of change of f (x) = –3x 3 + 2x + 3 on the interval [–2, –1]. A.27 B.11 C. D.–19

Example 5 Find the average rate of change of f (x) = –3x 3 + 2x + 3 on the interval [–2, –1]. A.27 B.11 C. D.–19

Example 6 A. GRAVITY The formula for the distance traveled by falling objects on the Moon is d (t) = 2.7t 2, where d (t) is the distance in feet and t is the time in seconds. Find and interpret the average speed of the object for the time interval of 1 to 2 seconds. Find Average Speed Substitute 1 for t 1 and 2 for t 2. Evaluate d(2) and d(1). Simplify.

Example 6 The average rate of change on the interval is 8.1 feet per second. Therefore, the average speed of the object in this interval is 8.1 feet per second. Find Average Speed Answer: 8.1 feet per second