Surface area of a cylinder Imagine a cylinder opened out Rectangle Circle

Surface area of a cylinder hh C=πd or 2 πr 2πr2πr Area of the rectangle is length x width = 2πr x h = 2πrh

Surface area of a cylinder A=π r 2 Area of the each ‘end’ is πr 2 So area of both circles is 2 πr 2

Surface area of a cylinder πr2πr2 Total surface area is 2πrh + 2 πr 2 πr2πr2 2π rh

Surface area of a cylinder Area of rectangle = 2πrh = 2 x 3.14 x 5 x 10 = 314 cm 2 Area of two ends= 2πr 2 = 2 x 3.14 x 5 x 5 = 157 cm 2 Total surface area is 2πrh + 2πr 2 Total surface area = = 471 cm 2 Find the surface area of a cylinder of radius 5 cm and height 10 cm 10 cm 5 cm 10 cm 2 x 3.14 x 5 cm 5 cm