HC CHEMISTRY HC CHEMISTRY NATURES’ CHEMISTRY (F) Skin Care.

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HC CHEMISTRY HC CHEMISTRY NATURES’ CHEMISTRY (F) Skin Care

Nature’s Chemistry HC HC (F) Skin Care After completing this lesson you should be able to : Free radical formation, structure and chain reactions. When UV light breaks bonds, free radicals are formed. Free radicals have unpaired electrons and, as a result, are highly reactive. Free radical chain reactions include the following steps: initiation, propagation and termination. Recognise initiation, propagation and termination steps of a free radical chain reaction. Be able to write equations for these steps given relevant information.

Photochemistry COPY Photochemistry is the branch of chemistry concerned with the chemical effects of light. Generally, this term is used to describe a chemical reaction caused by absorption of ultraviolet (wavelength from 100 to 400 nm), visible light (400 - 750 nm) or infrared radiation (750 - 2500 nm).

Hydrogen and chlorine COPY   COPY Hydrogen and chlorine When UV light breaks bonds free radicals are formed. Free radicals have unpaired electrons and, as a result, are highly reactive. Free radical chain reactions include the following steps: initiation, propagation and termination.

Hydrogen and chlorine COPY 1) Initiation   COPY Hydrogen and chlorine 1) Initiation U.V. light provides the energy for the homolytic fission of halogen into reactive halogen atoms or free radicals (atoms with an unpaired electron). Cl2(g) → Cl.(g) + .Cl(g)

Hydrogen and chlorine COPY 2) Propagation   COPY Hydrogen and chlorine 2) Propagation In this stage, free radicals collide with other species but the number of free radicals is maintained (hence the term propagation). H2(g) + .Cl → H.(g) + HCl(g) H.(g) + Cl2(g) → HCl(g) + Cl. (g) These reactions continue until reactants are used up, or until free radicals are used up by collision with each other.

Hydrogen and chlorine COPY   COPY Hydrogen and chlorine 3) Termination In this stage, free radicals are used up by collision with each other. H.(g) + .Cl(g) → HCl(g) H.(g) + .H(g) → H2(g) Cl.(g) + .Cl(g) → Cl2(g)

Free radical Substitution Hexane

Free radical Substitution Methane COPY Free radical Substitution Methane Another free radical reaction takes place when halogen is substituted into an alkane in the presence of UV light. This reaction is not explosive and results in the decolourisation of bromine.   Alkanes react with bromine in the presence of U.V. light, though the reaction with bromine is slow. The reaction can be shown as follows: CH4(g) + Br2(g) → CH3Br(g) + HBr(g) The presence of acid HBr in the product can be shown with moist pH paper. However, the reaction does not end here and further substitution can occur with hydrogen atoms progressively replaced by halogen atoms. The slow substitution reaction follows a free radical chain reaction, initiated by U.V. light (hf). For convenience, the reaction can be split into three stages.

Free radical Substitution Methane COPY Free radical Substitution Methane 1) Initiation U.V. light provides the energy for the homolytic fission of halogen into reactive halogen atoms or free radicals (atoms or molecular fragments with an unpaired electron). Br2(g) → Br.(g) + .Br(g)

Free radical Substitution Methane COPY Free radical Substitution Methane 2) Propagation In this stage, free radicals collide with other species but the number of free radicals is maintained (hence the term propagation). CH3-H(g) + .Br → CH3.(g) + HBr(g) CH3.(g) + Br2(g) → CH3 - Br(g) + Br. (g) These reactions continue until reactants are used up, or until free radicals are used up by collision with each other.

Free radical Substitution Methane COPY Free radical Substitution Methane 3) Termination In this stage, free radicals are used up by collision with each other. Br.(g) + .Br(g) → Br2(g) CH3.(g) + .Br(g) → CH3 - Br(g) CH3.(g) + .CH3(g) → CH3 - CH3(g)   The product of the last equation is ethane. However, to minimise the range of possible products, an excess of the original alkane is used and the products separated from the excess alkane by distillation.

Free radical Substitution Methane COPY Free radical Substitution Methane Evidence to support this mechanism The reaction is initiated by U.V. light and, once started, can continue in the dark. Other substitution products are made such as CH2Br2, CHBr3, CBr4 together with longer alkanes (and smaller amounts of substitution products of these alkanes. However, these other substitution products can be minimised by using an excess of the original alkane to try to ensure collision of the relatively small number of free radicals produced by sunlight quickly uses up the bromine.

COPY Many chemicals are stored in brown bottles to stop light initiating reactions that could cause the stored chemical to break down.