Modern Control System EKT 308 General Introduction Introduction to Control System Brief Review - Differential Equation - Laplace Transform
Course Assessment Lecture 3 hours per week Number of units 3 Final Examination 50 marks Class Test 1 10 marks Class Test 2 10 marks Mini Project 15 marks Assignment/Quiz 15 marks
Course Outcomes CO1: : The ability to obtain the mathematical model for electrical and mechanical systems and solve state equations. CO2: : The ability to perform time domain analysis with response to test inputs and to determine the stability of the system. CO3: The ability to perform frequency domain analysis of linear system and to evaluate its stability using frequency domain methods. CO4: The ability to design lag, lead , lead-lag compensators for linear control systems.
Lecturer Dr. Md. Mijanur Rahman mijanur@unimap.edu.my 018 9418701 016 6781633
Text Book References Dorf, Richard C., Bishop, Robert H., “Modern Control Systems”, Pearson, Twelfth Edition, 2011 Nise , Norman S. , “Control Systems Engineering”, John Wiley and Sons , Fourth Edition, 2004. Kuo B.C., "Automatic Control Systems", Prentice Hall, 8th Edition, 1995 Ogata, K, "Modern Control Engineering"Prentice Hall, 1999 Stanley M. Shinners, “Advanced Modern Control System Theory and Design”, John Wiley and Sons, 2nd Edition. 1998
What is a Control System ? A device or a set of devices Manages, commands, directs or regulates the behavior of other devices or systems.
What is a Control System ? (contd….) Process (Plant) to be controlled Process with a controller
Examples
Examples (contd…) Human Control
System Control
Classification of Control Systems Control systems are often classified as • Open-loop Control System • Closed-Loop Control Systems Also called Feedback or Automatic Control System
Open-Loop Control System Day-to-day Examples Microwave oven set to operate for fixed time Washing machine set to operate on fixed timed sequence. No Feedback
Open-Loop Speed Control of Rotating Disk For example, ceiling or table fan control
What is Feedback? Feedback is a process whereby some proportion of the output signal of a system is passed (fed back) to the input. This is often used to control the dynamic behavior of the System
Closed-Loop Control System Utilizes feedback signal (measure of the output) Forms closed loop
Example of Closed-Loop Control System Controller: Driver Actuator: Steering Mechanism The driver uses the difference between the actual and the desired direction to generate a controlled adjustment of the steering wheel
Closed-Loop Speed Control of Rotating Disk
GPS Control
Satellite Control
Satellite Control (Contd…)
Servo Control
Introduction to Scilab Xcos
Differential Equation N-th order ordinary differential equation Often required to describe physical system Higher order equations are difficult to solve directly. However, quite easy to solve through Laplace transform.
Example of Diff. Equation
Example of Diff. Equation (Contd…) Newton’s second law:
Table 2.2 (continued) Summary of Governing Differential Equations for Ideal Elements
Laplace Transform A transformation from time (t) domain to complex frequency (s) domain Laplace Transform is given by
Laplace Transform (contd…) Example: Consider the step function. u(t) u(t) = 1 for t >= 0 u(t) = 0 for t < 0 1 t -1
Inverse Laplace Transform Transformation from s-domain back to t-domain Inverse Laplace Transform is defined as: Where, is a constant
Laplace Transform Pairs Laplace transform and its inverse are seldom calculated through equations. Almost always they are calculated using look-up tables.
Laplace Transform’s table for common functions Unit Impulse, 1 Unit step, Unit ramp, Exponential, Sine, Cosine, Damped sine, Damped cosain, Damped ramp,
Characteristic of Laplace Transform (1) Linear and are constant and and If are Laplace Transforms
Characteristic of Laplace Transform (contd…) (2) Differential Theorem For higher order systems where Let and
Characteristic of Laplace Transform (contd…) (3) Integration Theorem Let where is the initial value of the function. (4) Initial value Theorem Initial value means and as the frequency is inversed of time, this implies that , thus
Characteristic of Laplace Transform (contd…) (5) Final value Theorem In this respect as , gives Example1 Consider a second order Using differential property and assume intial condition is zero Rearrangge Inverse Lapalce
Example 2 Assume, 0 initial conditions. Taking Laplace transform, we obtain
Example 2 (contd…)
Example 2 (contd…) Thus the solution of the differential equation From table, inverse Laplace transform is Thus the solution of the differential equation
Example 3 Non zero initial condition
Example 3 (contd…)
Example 4 (a) Show that is a solution to the following differential equation (b) Find solution to the above equation using Laplace transform with the following initial condition.
Solution (a)
Solution (b)